Isothermal and Free Expansion of Gases- Thermodynamics (Part 8)

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@balajijagan2018 5 жыл бұрын

I was seraching some good lectures for chemistry in english but everything were in hindi and i found it difficult to understand mam,But your teaching is awesome and i can easily understand it.Thank you mam🙏🙏

@Veddrawingandvlogs 3 жыл бұрын

how were your exams

@shagunsharma1401 5 жыл бұрын

You have a great talent to explain concepts of chemistry in an easy way ..... Please make more videos for 12th class organic chemistry

@niranjanarl1508 3 жыл бұрын

Thank u so much mam.....this was very useful🙂🙂

@niranjansahu9352 6 жыл бұрын

Mam u r a Very good teacher and ur explanations r really very understoodable to me tq mam for ur vedios

@muhammedansar3558 4 жыл бұрын

Good work mam. Keep uploading videos👍👍👍

@diyaagrawal5048 3 жыл бұрын

Awesome explanation ma'am 👏... Thanku thanku so much..

@adityanagpal3884 2 жыл бұрын

very well

@sumayya28basheer 5 жыл бұрын

Brilliantly explained. Thank you!

@SureshSahu-j4m 7 ай бұрын

Thank you ma'am mean alot please make such videos

@GAMINGANDTECHVAIBHAV 4 жыл бұрын

What a explanation mam , well explained , really it cleared my every delta doubt 😁🙏

@ishitawadhwani5310 6 жыл бұрын

You’re an amazing teacher.

@haridutt9600 4 жыл бұрын

Mam my doubt is that for isothermal process the value of q is o and as u said that the work is wasted will the value of w would also be o and thus deltaU would be zero 🤔 please tell me mam

@manitaprajapati9459 2 жыл бұрын

Thanks mam

@reemamujib9681 5 жыл бұрын

Mam , so for free expansion the gas in the isolated container has to be compressed right before they can be expanded( due to 0 p(ex))

@niranjansahu9352 6 жыл бұрын

Plz mam keep making vedios on our part 2 Book of chem i need it very much

@mrzadahmed4651 4 ай бұрын

god bless you maam you are a life saver

@zorawarsingh6415 6 жыл бұрын

Mam u teach very well i loved ur way of teeching

@garimaagarwal726 3 жыл бұрын

Deep learning ..

@maliaka.trambu6715 3 жыл бұрын

U explain very very nicely ❤

@vivekjain8062 4 жыл бұрын

Please help mam , i have a doubt In adiabatic process ,as u said in this video del q =0 but not del t But if temperature is increasing or decreasing then heat should also increase or decrease ??

@carultch 2 жыл бұрын

This is only true when you are dealing with a condensed form of matter whose change in density is insignificant as it is heated. For gasses specifically, they are free to do work or have work done on them, as undergo any process that isn't constant volume. This means, isothermal and adiabatic are two different processes for a gas. Isothermal means constant temperature. Since temperature doesn't change, and temperature alone determines internal energy, this means all heat added to the system becomes work done by the system. (not on a closed cycle, otherwise that would violate the 2nd law of thermodynamics). For an adiabatic process, there is no heat transfer. The change in internal energy therefore is equal and opposite to the work done by the system. Adiabatic reversible processes are also called isentropic, since they happen with constant entropy of the gas.

@neetaccelerator9627 5 жыл бұрын

Ma'am first of all thanks. I have a doubt ma'am. In case of rearrangement of 1st equation, how can ∆U be =0 as ∆U is always 0 in case of free expansion only and need not be zero in case of just irreversible change as you have mentioned(there is no mention that it is a case of free expansion) . Also if ∆U is 0 then q and W must also be 0 as ∆U=q+w. And if we assume that process to be free expansion then w is 0(as w=-p∆v and in free expansion p=0). How can we say q=-w? Exactly for this doubt I was searching for a video. Please help.

@SeemaDhawanArora 5 жыл бұрын

Aditya saurabh are you talking of this video? We are talking about free expansion here

@Riya-gk1vt 4 жыл бұрын

Same doubt

@smnclashed6311 4 жыл бұрын

It isnt neccessaey that q and w should be zero, look we talk in context to isothermal reactions, this means that there is no temperature change, now q can be changed only by two factors, they are either changing temperature or by doing work. Since U = q + w nd U = 0 and temp is also constant, the only other thing contributing to q is work done(w) since the sum is 0 we get q + w = O nd hence q = -w. The reactions are only for isothermal nd not for free expansion

@randomworld9909 3 жыл бұрын

Same problem can anyone plz explain it

@Raghuofficial7 11 ай бұрын

@@smnclashed6311thankyou so much

@EveryEngMechanical 4 жыл бұрын

in free expansion internal energy can we called free expansion is a isothermal process

@carultch 2 жыл бұрын

Free expansion is technically isothermal, but it is misleading to call it that. Isothermal usually means isothermal and reversible, if not otherwise specified. It really is called an isenthalpic process, since the internal energy (and correspondingly, enthalpy) is constant. The process is irreversible, and doesn't do work, as a reversible isothermal process would do.

@Raghuofficial7 11 ай бұрын

Thank you so much mam❤

@lovelyyadav3709 5 жыл бұрын

Mam in the case of free expansion is there no piston present.? Which can be pushed by gas molecules. Is there free molecules of gas in a vacuum

@GAMINGANDTECHVAIBHAV 4 жыл бұрын

Ya ofcourse , in container there will be gas molecules ( pressure internal present). We use piston only to see is there is pressure or not. Hope you understand 🙂

@SureshSahu-j4m 7 ай бұрын

Ma'am please cover full 12 syllabus

@reemamujib9681 5 жыл бұрын

Mam , so there should be no expansion or compression taking place during free expansion ... I am not getting the concept behind it .... Mam pls explain it when you are free

@GAMINGANDTECHVAIBHAV 4 жыл бұрын

This is a concept of work only , we are studying that what will be the work in expansion....

@VENOM-dt3ru 4 жыл бұрын

I think , in free expansion there is no external pressure so pressure inside the system causes expansion! During calculations of work done we use external pressure. So work done in free expansion is zero but system still expanding!!