Continuity of function | Theorem | f is Continous iff f (Ā) is subset closure of f(A) | metric space

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OMG Maths

OMG Maths

Күн бұрын

Пікірлер: 32
@OMGMaths
@OMGMaths 3 жыл бұрын
You can download PDF from: omgmaths.com/real-analysis/f-is-continous-iff-f-a-is-subset-closure-of-fa-continuity-of-function-real-analysis/ Related Playlist: Limit and Continuity kzbin.info/aero/PLYisSyPLgRv63erEi49zu0w1x_oAP1K89 Please like, Share and Comment. "Subsribe"kzbin.info/door/xVm7BDqq6KLjptLZ94j-cg for more videos.
@aishinikiyara2675
@aishinikiyara2675 2 жыл бұрын
Very good explanation mam.
@OMGMaths
@OMGMaths 2 жыл бұрын
Thank You 😊 Your appreciation means a lot lot for me….Please write your valuable reviews at g.page/r/CRP90Pt3uFhFEAg/review Like ,share and Subscribe.
@malihafatima9239
@malihafatima9239 3 жыл бұрын
Mam jii u r great... Bht acha smjhaya... Concept clear ho gia ... Superb ❣️
@OMGMaths
@OMGMaths 3 жыл бұрын
Thank You 😊 Subscribe and press 🔔 for updates. Click to find find more videos on limit and continuity kzbin.info/aero/PLYisSyPLgRv63erEi49zu0w1x_oAP1K89
@malihafatima9239
@malihafatima9239 3 жыл бұрын
@@OMGMaths After your superb vedio lecture, I have already subscribed your channel ☺️☺️
@OMGMaths
@OMGMaths 3 жыл бұрын
Thank You 😊
@VikasSharma-xb4ev
@VikasSharma-xb4ev 8 ай бұрын
Same problem topology ka rahne par same proof hoga ya different?
@07ankitanand24
@07ankitanand24 9 ай бұрын
just a small mistake that (f( f^(-1)(A)) is a subset of A and not equal to A. it is equal iff f is onto. which may not be the case.
@saqibshah5307
@saqibshah5307 3 жыл бұрын
thank you mam bht acha smjhate haa app
@simplewayofliving
@simplewayofliving 2 жыл бұрын
mam,theorems samajh me toh aa jati hai but karne se beech beech me steps bhool jate hai....what to do?
@OMGMaths
@OMGMaths 2 жыл бұрын
written practice is must jo jhada bhuli hai 2-3 time practice karo
@sonali5687
@sonali5687 Жыл бұрын
Can i use this same proof for topological space??
@reshmakandasi1424
@reshmakandasi1424 Жыл бұрын
Same question 😢
@tulsisoni2598
@tulsisoni2598 Жыл бұрын
Thank you mam 😄
@OMGMaths
@OMGMaths Жыл бұрын
Glad it was helpful 😊 Subscribe kzbin.info and press 🔔 for notifications. Please Keep Watching and Share with others.
@malikbilal3251
@malikbilal3251 2 жыл бұрын
Bundles of thanks mam.❤
@OMGMaths
@OMGMaths 2 жыл бұрын
Please give your valuable reviews at g.page/r/CRP90Pt3uFhFEAg/review
@bseacademy2597
@bseacademy2597 3 жыл бұрын
Excellent mam
@OMGMaths
@OMGMaths 3 жыл бұрын
Thanks for the visit 😊.......“subscribe” and press 🔔 for updates. You can find more videos on "Real Analysis" kzbin.info/aero/PLYisSyPLgRv7nqpvKXN7vbMuGM1LT8zwy Please Like and Share with your Friends.
@pushkarkumar3089
@pushkarkumar3089 2 жыл бұрын
Very nice!!!
@OMGMaths
@OMGMaths 2 жыл бұрын
It's my pleasure 🙏 Subscribe kzbin.info and press 🔔 for notifications. Keep Watching…and Share with others.
@madhubarman4138
@madhubarman4138 3 жыл бұрын
Thanks mam
@OMGMaths
@OMGMaths 3 жыл бұрын
Glad it was helpful! “subscribe” and press 🔔 for updates. more videos on Real Analysis kzbin.info/aero/PLYisSyPLgRv7nqpvKXN7vbMuGM1LT8zwy
@zahrahayyat7865
@zahrahayyat7865 3 жыл бұрын
Mam plz ye theorem bh solve krwayen ksi lecture men plz statement ye hai is ki "A mapping of a metric space X into a metric space Y is continuous on X iff f⁻¹(V) is open in X for every open set V in Y"
@zahrahayyat7865
@zahrahayyat7865 3 жыл бұрын
Plz mam
@OMGMaths
@OMGMaths 3 жыл бұрын
This is the required result. kzbin.info/www/bejne/eKa6nHmjgtyer9U You can find more videos on “Limit and Continuity” here kzbin.info/aero/PLYisSyPLgRv63erEi49zu0w1x_oAP1K89 Keep Watching..... subscribe and press 🔔 for updates.
@harshikeshsingh2648
@harshikeshsingh2648 2 жыл бұрын
Good
@surajchouhan1125
@surajchouhan1125 3 жыл бұрын
Regular lecture daliye Mam
@OMGMaths
@OMGMaths 3 жыл бұрын
yes sure
@322-pinkidhobi9
@322-pinkidhobi9 2 жыл бұрын
Let A = {(x, y) ∈ R^2: X^2− 3y > 5}. Show that A is an open set in (R^2 , d2) using continuity.
@vishalmaurya3194
@vishalmaurya3194 Жыл бұрын
😍😍
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