Im an engineering student in korea. Your lecture is so helpful and easy to understand. :-) thank you very much!!
@khalsahamed1435 жыл бұрын
Thank you sir... Your lecture is so easy to understand
@koushikvs79284 жыл бұрын
Sir realy ur chanel is very helpful to understand the complicated concept very easily... 🙏🙏
@mahmudulhassan43496 жыл бұрын
it'san awesome lecture,Sir.jajakallah
@sridharpalukapati18045 жыл бұрын
Simple and easy to understand
@petchfreedomlife7533 жыл бұрын
Thank you very much for explaining to me this matter.
@jacobzetterfeldt365211 ай бұрын
God explanation. 👍
@jeetadityabiswas48195 ай бұрын
Sir how can fouriers law be used in unsteady state diffusion heat equation because fourier law can be applied only in steady state condition
@bikramsaha54063 жыл бұрын
Amazing 🔥
@bikramsaha54063 жыл бұрын
11:42 tell me one thing that T1>T2 and Qx -Q(x+dx) should be a positive term !?but u take it Q(x+dx)-Qx =+ve why?
@Dr.AmitMandal3 жыл бұрын
It is negative
@shuvroasman6 жыл бұрын
Woww. Thank you Sir
@engr_batoorkhan96606 жыл бұрын
great sir
@gopendarbhukya7970 Жыл бұрын
Sir please make 2 and 3 dimensional conduction equation video quickly i have sem exam upcoming 5days..
@Dr.AmitMandal Жыл бұрын
Derive like same seperately in all three directions and add.
@navjotsingh.37662 ай бұрын
Derive one dimensional time dependent heat conduction equation with internal heat generation and variable thermal conductivity in Cartesian coordinate system. Iska kya matlab hai
@Dr.AmitMandal2 ай бұрын
केवल कंडीशंस अलग हैं, वैसे ये derivation btech में नहीं पूछा जाता नॉर्मली...
@nathanvanpelt72165 жыл бұрын
the partial derivatives should be normal derivatives no? ie. what are the multiple contributing factors to the differential volume distance (dx) ?
@nathanvanpelt72165 жыл бұрын
wouldnt dx only depend on the length "x"? ohh... wait. its a variable density?
@lakshmim59854 жыл бұрын
Here we are deriving for 1 dimension
@Vaibhav_91504 жыл бұрын
Hi sir Can You make a video on Cooling load Calculation
@exploringtheworld4860 Жыл бұрын
Sir, when ∆x tends to zero, ,why ∆Q/∆x is remaining.