Amazing Math Problem

[@AriosJentu]

All three methods are absolutely incorrect. First of all, you can't define infinity in absolute form: 1/0 is not +-inf, it's undefined. But if you look at the left/right limits, approaching to 0, it may make sense, but that's not the way this task described. You can check it by your wrong way of describing the division algorithm. 1/0 = 1 - 0 = 1... You've never taken a 0 at the end, because it's impossible. Even the infinite amount of steps doesn't give you 0 at all. So, that's absolutely impossible to have a solution in a way that this task described. You should introduce an infinity, give the definition of it, and then you can state that infinities can be a solution to this equation. The second method is absolutely wrong, because squaring provides extra solutions, what you found, but this solution does not solve the original one. The third method I can describe as the first one. You've created your own mathematics there, which has no intersections with the real one, sorry.

[@jneal4154]

@@AriosJentu These people didn't form their opinions by reasoning through the math, so I'm not sure trying to help them understand the math is going to change anything. They don't actually want to understand. They just want to argue.

[@Korrmet]

First of all, infinity is a limit...

[@FatimaFall-jn1iq]

​​@@jneal4154 Is that a judgement In math we can make error and learn about it so it's not arguing But TRYING to understand And at least he proposed something You too you can propose it's also a debate But your speech is a little evil 😔

[@jneal4154]

@@FatimaFall-jn1iq Wrong is wrong and idiotic ideas deserve being ridiculed if they are presented as legitimate, as they have been here.

[@jneal4154]

@@FatimaFall-jn1iq So yeah, you can bet your butt that's a negative judgement. I am judging the video creator very harshly, not because they made a mistake, but because they refuse to correct their mistake, doubling down on it instead. Someone that makes a mistake is just human. Someone that doubles down on their mistakes is an idiot. The creator doubled down. How do you not judge someone harshly for that?

[@Ken.-]

On the 3rd one, the two lines never intersect. They are never equal just as the left expression is never equal to the right expression. The equation is meaningless. The correct conclusion is that the equation _has no root_ .

[@FocusLRHAP]

10:20 Actually -1/2 is the solution for x+1=-x not for x+1=x

[@FocusLRHAP]

And if you square it you both equations you get (x+1)^2 = x^2 since (-x)^2=x^2 because (-x)(-x)=+x^2

[@BeenuZz]

-1/2 is not the solution of x+1=x no matter what twist you do. It has no solution.

[@FocusLRHAP]

@@BeenuZz I know. I was saying that -1/2 is the solution for x+1=-x But (x+1=x)^2=(x+1=-x)^2=(x+1)^2=x^2. So he get -1/2 because he was getting the x+1=-x version of (x+1)^2=x^2. That's why he got -1/2 as a fake solution -1/2 is a solution for (x+1)^2=x^2 and a solution for x+1=-x, but not for x+1=x

[@BeenuZz]

@@FocusLRHAP ah ok. Well yea, it's just ridiculously obvious. What a stupid video

[@ddelaiss5406]

X=-1/2 false. Your response exact.

[@АнатолийПивоваров-д6у]

x+1=Х 1=Х-Х 1=0 НеЗНАЙКА ОТДЫХАЕТ Евклид вздыхает, Лобачевский задумался , Риман усмехнулся: мел взял гений.

[@kassuskassus6263]

🤣

[@lvluf4s4]

Si a ± infinito le sumas 1 sigue siendo ± infinito. X + 1 = X ± infinito son las únicas respuestas posibles.

[@alajos-derek1669]

😀

[@konstantinchernyshevsky454]

😂

[@ВалерийГузей]

@@lvluf4s4 Бесконечность это теоретическая величина в математике. Реального значения она не имеет, так же как, например, математическая точка или - комплексное число. В этом примере X стремится к бесконечности, но в любом случае, знака равняется в этом уравнении не будет. Будет - примерно ≈ , близко к..., но не - равняется

[@adamsseidu1846]

Please sir, the solution from the second method doesn't satisfy the equation. When you put it into the equation you will get a positive half and not a negative half.

[@SaidMohamed-j2v]

exactly ......i also see that . and i wonder why didnt he prove it of negative half is a correct ansewe

[@DrBenway97]

@@SaidMohamed-j2v It's because negative half is not a solution. There in NO solution to this problem. None...

[@radupopescu9977]

@@DrBenway97 Why you restrict solutions to reals? Infinity is not a real number, but Infinity is also a transfinite number, and infinite more that a number.

[@vaclavkrpec2879]

99.5% of people correctly deduce that the equation has no solution (as it’s equal to false tautology of 0 = 1). It seems that you belong to the exceptional 0.5%…

[@engjayah]

Squaring both sides meaning solutions from the 2 points of intersections graphically. But these 2 parabolas will intersect only at one point giving a solution of x = -1/2 This is the solution of x +1 = -x Meaning not the solution of x +1 = x

[@Ken.-]

The 2nd method introduced a "Fake" root, or extraneous root. Extraneous roots can be introduced when both sides of an equation are multiplied by a quantity containing the unknown or when both sides are raised to an even power (for instance when both sides are squared). It's always a good idea to check your solution by substituting into the original equation, but when extraneous roots could be involved, you _must_ make suck a check.

[@freedomhawk772]

More false math click-bait. It's alarming that so many different people are pushing 1/0 has a solution besides the empty set in various ways.

[@tomtke7351]

X + 1 = X 1 + (1/X) = 1 1/X = 0 X = infinity

[@saidelmenjaoui4216]

جيد ، تحليل لا ينجزه إلا أصحاب الخبرة الرياضياتية.

[@MaheshKumar-lx1ku]

When backbencher becomes a math teacher 😂😂

[@yungdkay1008]

You are the backbencher here. You clown

[@onlineMathsTV]

🤩😂😂😂😂😂

[@boddunarayana4831]

@@onlineMathsTV look who is laughing

[@tochukwuapugo-nwosu2289]

You can't be serious

[@spacer999]

Never mind the fact that parallel lines in Euclidean geometry don't ever converge, not even at infinity. It is completely BS to claim x=-1/2 is a solution of x=x+1.

[@angeericdjebi943]

1/2 not equals to -1/2

[@onlineMathsTV]

Yes, 2nd method is wrong

[@jneal4154]

@@onlineMathsTV And the first... And the third...

[@DavidLopez-gi5qb]

There are no solutions.

[@ivanballeram6112]

A simple answer made into a mess.

[@ericmariaud8237]

La seconde méthode donne le résultat de l'égalité des valeurs absolues: | x + 1 | = | x | x = -1/2

[@RyanLewis-Johnson-wq6xs]

x+1=x x has no solution

[@engjayah]

+-inf +1= +-inf Meaning x value approaches infinity This makes sense

[@SamuelDonald-pr2uu]

Dis problem has no solution. Stop proving wat doesn't exist in the world of Mathematics sir

[@SamuelDonald-pr2uu]

Can't u see dat the second solution doesn't satisfy the equation sir? Nobody will ever ask you to solve a problem like this in the first place.

[@guptaa]

no real solution because infinity is not a real number

[@hervehum6454]

D'accord pour dire que l'infini n'est pas un nombre réel, donc les nombres irrationnel sont imaginaire !

[@tsunny5172]

He should be sacked if he is teaching in any school or college and revoke his teaching license - sorry for you.

[@victoradamenja9032]

1/0= becose of you can't devide by zero by rules. If zero not true zero but only ->0 then lim 1/0=inf but inf isn't a number that grooup of numbers with unf exponent.😊

[@tambuwalmathsclass]

All the three methods make no sense Mathematically. 1/0 is not infinity but undefined. Remember you're not dealing with limits When two lines are parallel, no matter how far they will never meet, therefore you can't just imagine a solution.

[@AndreS-em1kt]

Он, вообще, понимает ,что такое найти корни уравнения? Бред сивой кобылы!

[@karthick100]

X = Infinity. Infinity +1 = Infinity

[@CYBRROKR]

First of all Infinity isn't a number.

[@mnrztn293]

We talk about infinity when approaching solutions, in case of limits but NEVER to resolve an equation, please remind this. Sorry for my bad English

[@comic4relief]

Actually the third one makes sense, for it shows that there is no real-number solution. The two lines are parallel and therefore do not intersect in the Cartesian plane .

[@JakubPicho]

He should to get nobel for this solving.

[@Ken.-]

Hyperreal Numbers (Nonstandard Analysis): Even in systems that include infinitesimals or infinite numbers, the equation x+1=x remains problematic since it suggests adding something (no matter how small or large) results in no change, which still implies 1=0.

[@rizkysoemanagara2494]

X=Xmen--xavier,wolverine

[@chitranjantiwary9506]

Solution obtained from 2nd method is not acceptable as it does not satisfy the equation. Please do not try to mislead.

[@MaheshKumar-lx1ku]

No solution...!

[@N.y.sh.403]

X is infinity

[@walterwhite210]

No

[@PeterPan-ev7dr]

A math cascadeur!

[@mithubhattacharya6156]

X is infinite

[@savazi2004]

Videos like this one are the reason that causes young students to do horrible errors in their process of solving math problems. From the beginning to the end of your explanations you made error after error. You mustn't explain math.

[@MorbusSollistimus]

X = ∞ , but any infinity + 1 is the same again

[@mnrztn293]

Please don't blame him a lot, he is the fruit of education systems who made students as stupid robots repeating resolution of exercises without understanding the deep meaning of mathematics. Believe me, once I had a conversation with a middle school mathematics teacher and he was enable to make difference between unidentified value and infinity ! Sorry for my bad English

[@HinduHeads]

On the surface, the video may seem meaningless, but if you watch it sincerely, it teaches you how maths work, or doesn't work sometimes.

[@azizbeknasullayev9110]

Solving equation is to find its roots or showing that it has not any roots. So if you just write down empty. This is solution. Non infinity nor -1/2 are solutions.

[@radupopescu9977]

Seeing a lot of comments against what you said, maybe it's a good idea to explain a little bit what Infinity means. I agree that this wouldn't be a 15 min presentation, but it might help. To put it simplistically: imposing any condition on Infinity, make Infinity not infinite anymore. Hard to grasp, indeed. Still this is Infinity.

[@123vaporize]

its a stupid problem unless we say x approaches infinity then we get into limits, calculus etc. How he comes up with the nearly correct solution of x=oo is in my opinion fuzzy math. The correct solution is x--->00 or X goes toward or approaches infinity. That is all

[@西崎古一]

'No solution' is the only answer of this problem.

[@Al-Capone]

+-Бесконечно большое + 1 = +-Бесконечно большое.

[@virgilhouston2936]

Here’s a simple solution - empty set.

[@guntramschlemminger7383]

No way. x+1 is never equal x! But the limit for(x+1)/x for a endless increasing x tends to go to 1. But it will never reach 1.

[@JangirBK]

And in second solution.. you just wrongly interpreteded.. a^2 = b^2 doesn't always mean a = b, it could be a = -b as well !!

[@victorchoripapa2232]

No solution in R

[@caimayquat]

cảm ơn , lý giải thuyết phục

[@ksiomega]

The 2nd method gives X=-1/2. But if set it into the equation you won't get -1/2 on the right. Because -1/2+1=+1/2 The 3rd method doesn't shows there is no interconnection between Y=x+1 and Y=x. These are parralel steaight lines. They don't interconnect even in infinity. The first method is mentally right. If to add 1 to +/- Infinity it still be +/- Infinity.

[@victoradamenja9032]

The main proplem is 10/2=5 because of table multiplication that everyone should know in first grade. But 8/2=4 for the same reason.😊

[@Ghorbani-pt5ph]

excellent

[@AmitDey-el6mn]

In binary number system, 1+1=1, so x=1

[@benjamintosin5576]

The identity element for addition (+) is zero (0) not one (1). Your equation is not correct mathematically and practically.

[@xololomejor]

This equation doesn't have real or complex solution

[@robertosanna2372]

Fantastic THE LORD OF RING... EXIST

[@dragonbool1226]

ما هذا الهراء 😮😮

[@SidneiMV]

SECOND METHOD FAILED

[@dimitriosbetsis1509]

Division by zero is not allowed!

[@nyonkavincenttafeli7002]

Hmmm, one of your solutions(x= -1/2), so are you saying -1/2 + 1 = -1/2?

[@vasantakumarpai3195]

Only in balancef chemical equations it is possible, 2H2+1O2=2H2O, 2+1=2

[@iam4907]

У Вас красивое решение получилось) 4-е, но единственное, имеющее смысл.

[@АмаЭльд]

Чем ближе Х к бесконечности ±~ , тем вернее равенство . В противном случае 1≠ 0 и не нужно , столько времени мозги засорять , просто , надо включить логику .

[@יקירון]

In order to solve the equation X + 1 = X ... X must be either a real number or a complex number. Infinity & - infinity are neither real numbers nor complex numbers. If X +1 = X then 1 = 0 which is a complete nonsence. Therfore X is undefined or X = {}.

[@njabulowisemanndzimandze2978]

1st method The first assumption made is that x is not zero, otherwise dividing by X will e undefined. Method 2 LHS = x + 1 = -½ + 1 = ½ RHS = x = -½. Hence -½ is not a solution! Method 3 Graphically there is no solution, x+1 and X are parallel lines, why then do you say ± infinity since they won't meet.

[@lwandomakaula3574]

Yes this is so accurate wonderful!!!

[@vasantakumarpai3195]

Thank God,Euler,Gauss,Srinivasa Ramanujam, shakuntala devi ,fibinacci are not alive to watch the video

[@DrBenway97]

LMFAO.. thanks for that.

[@krishnamoorthypalanivelloo8854]

😂

[@krishnamoorthypalanivelloo8854]

On you right 1 disappeared. So x must be huge enough to vanish the 1 on RHS. Thus x must be infinite

[@vasantakumarpai3195]

@@krishnamoorthypalanivelloo8854 please read the book the man who knew infinity, Infinity is not a number,it is not a set,it is not a set of set, but it is a beautiful concept

[@kacheshwarpakhare4438]

😂😂😂😂😂😂😂😂

[@vits1560]

Only modulus of the left hand side can be equal to the modulus of the rt side.As modulus of - 1/2 = modulus of 1/2

[@АнтонКалугин-ж7г]

Finding solution for x+1=x is the same as saying 1=0, they are not equal so there are no solutions. But if we put absolute value in one of the parts, we will have solution when x=-1/2.

[@berhesimon2827]

Sir Could you please change the equation into x+1= -x; so that x=-1/2 can be the solution

[@RyanLewis-Johnson-wq6xs]

-(1/2)+1=1/2 not -1/2

[@masoudnasro3233]

None of x= 1/2 or x= -1/2 satisfies the equation x+1= x See If x= 1/2 then x+ 1 = 1/2 +1 = 3/2 not = 1/2 If x=-1/2 then x+ 1 = -1/2+ 1= 1/2 not =-1/2 This is because originally when you propose x+ 1= x then no real number can satisfy this equation, which implies the solution set is the empty set. But let us assume that x is a complex number, which implies that there are y, x real number such that x = y+ i*z where i^2= -1 Then x+1 = x becomes y+i*z+1 =y+i*z this leads also to no solution

[@satyapalkhera]

For x+1=-x, x=-1/2 -1/2+1=-(-1/2) => 1/2=1/2

[@xysam]

How come that x=-1/2, it is wrong, - 1/2+1=1/2 not - 1/2. To say that there is a mathematical solution for a linear equation means there is just one unique solution to it.

[@PaulBSimpsonJr]

OMG! What has happened to the education system?

[@camkx]

you cannot square the equation without checking the redundancy. 2nd method is wrong

[@brunobuzzacchi1108]

For 2nd solution we have x² + 2x + 1 = x² Going through 3rd solution on this we have y = x² + 2x + 1 and y = x² that are two parabolic curves that touch each other on x = -1/2 and never more. But the value x = -1/2 doesn't solve x+1=x -1/2 + 1 = -1/2 1/2 = -1/2 ❌ (fail) but doing ( )² on both slides (1/2)² = (-1/2)² 1/4 = 1/4 ✔️ (good) When squaring both sides we are removing the negative part, like x + 1 = x |x+1| = |x| y = |x+1| and y = |x| will also touch each other on x = -1/2 but the module equation doesn't guarantee the original one, like squaring both sides. x = ∞ or x = ±∞ is also not a real solution, because ∞ is not a number (can be seen as "∞ is somewhere"), ∞ does not belong to |R. The ∞ doesn't behave as a number, and ∞ + 1 = ∞ because there is nothing bigger than ∞. We can se that y=x+1 and y=x for any x is distant (distance from (x,x) to (x,x+1) is always equals 1), but going to infinity, for a extremely large number of x, the distance of 1 is not significant, that is, "on infinity they will touch", the distance between each other is practically zero. But "on infinity" is not a solution in |R.

[@pakarmyzindabad2092]

x+1=x (x+1)² =x² x² +2x+1=x² 2x+1 =x² - x² 2x+1 = 0 2x = -1 x = -1/2 But it is extraneous root Solution set = { }

[@CYBRROKR]

@@pakarmyzindabad2092 what happen if we cube both side or ^4, ^5, ^6, .....? I don't think this (x+1=x) equation makes any sense.

[@saidelmenjaoui4216]

Attention, la question que l'on pourrait poser c'est : QUAND ON A L'ÉGALITÉ x+1=x ? Le x² _ x² n'a pas de sens quand x tend vers l'infini. Tu élèves le tout au carré. Bien, Si tu élèves le tout au cube. Que va t'il se passer ? J' espère que tu me comprennes. Voilà, je ne comprends pas l'anglais, heureusement le calcul mathématique est indépendant.

[@amehachewa4757]

In mathematics, this is an acceptable way and confusing for those beginners.

[@nshylaja2007]

X=1

[@saurabhgarg9935]

-0.5 is complete incorrect. Bad video

[@alexandroyassuhiro6514]

1/x = 0 X•0 = 1 X•0= 0(R) X(R) 1(error)

[@flipperpluto_BG]

Second method FAILED ! 😅

[@PROTAGONISTRoMeL]

Isn’t the equation x+1=x a contradiction? There is no solution. x+1=x 1 = x-x 1 = 0

[@AntoineVanGeyseghem]

=O

[@AbdelkaderBouchoucha]

ممتاز good

[@eugengrzondziel1706]

😂😲 It is so simply, what to loose so many words? If 1/x =0 then x= infinity

[@АндрейЛюбавин-э4щ]

Бесконечность

[@GIFPES]

1/0 is not a real number but a limit proning to infinity for infinity is not just a number.

[@RajendraKhwairakpam]

Sir, infinity is not a number.

[@ElvisSaturn]

Yes. It is a pol!

[@jneal4154]

@@ElvisSaturn Infinity is not a number in the reals. PERIOD. Not only does the limit not exist, ∞ is not a real number and therefore cannot be a solution to a algebraically closed equation. a+b=a IFF b=0 The only additive identity in the real numbers is 0. The equation is nonsense. Asymptotes don't change that. In the equation \frac{1}{x}, there does not exist a number x that will give you ∞. 1/0 ≠ ∞ Demanding that it does makes it very obvious that you are struggling to understand basic Algebra.

[@ElvisSaturn]

@@jneal4154 “YES” in my answer to @RajendraKhwairakpam means: confirmation that infinity is not a number.!!! You only know school math. (only real number!) At university you learn what "poles" mean. I do not claim 1/0 = ∞. NEVER! but I know: if a->0, then 1/a -> ∞ and then 1/a is one POL!!!! If you don't recognize the difference, then I can't help you either. Sorry.

[@jneal4154]

@@ElvisSaturn The irony of accusing me of not learning math beyond the real numbers while you struggle to describe asymptotes using your 9th grade math vocab is pretty hysterical.

[@cristiansotocanto8582]

Technically, the infinity we study when dealing with real numbers is a symbol meaning that any real number is smaller or bigger (depending on whether is positive or negative). The video is atrocious:1/0 has no meaning because 1/0= x iff x times 0 is equal to 1 but x times cero is cero for any given real number. In the context of real Numbers x+1=x iff 1=0 which doesnt make any sense: it is not a valid mathematical expression.

[@thomasharding1838]

"Mathematicians" who ssy that X/0 in not infinity are those people who cannot fathom numbers that cannot be expressed on their fingers (or lack of fingers). As a positive denominator decreases to, and including zero, the resultants increase to, and including, infinity.

[@alajos-derek1669]

Ennek az egyenletnek még a komplex számok körében sincs megoldása. Esetleg a hiper komplex számkörben. De legalább jó sok hozzászólást kaptál. Emelkedik a nézettséged. Mi lesz, ha a gyerekek tőled tanulják a számtant?

[@god_bika]

lim(1/x) -> gives us infinity, you cannot divide by zero

[@SaidMohamed-j2v]

i wonder why didnt he prove it if negative half is a correct ansewer

[@alexandroyassuhiro6514]

(X+1)/X = 1 (X/X)+(1/X) = 1 1/X =0,5 (X/X) ≠ (1/X) (X/X) ≠ (1/2) X+1= X (error)

[@bucharipts9143]

infinity not defined to real number. your equation not have solution in real number set

[@abrdds]

1/0 = undefined, not infinity

[@shaijuthomas789]

You wrongly answered This equation has no solution You shows the graph give correct

[@Birol731]

My way of solution for this interesting question ▶ x+1= x if x is equal to x+1 then, the square of both sides must also be equal to each other ? 🤔 x+1= x (x+1)²= x² x²+2x+1= x² 2x= -1 x= -1/2 ⇒ -1/2 + 1= -1/2 1/2 ≠ -1/2 ❌ ⇒ x+1 = -x The value of x= -1/2 is only correct for the equation: (x+1)²= x² b) Let's try the third power for the both sides: x+1= x (x+1)³= x³ (x²+2x+1)*(x+1)= x³ x³+x²+2x²+2x+x+1= x³ 3x²+3x+1=0 Δ= 3²-4*3*1 Δ= 9-12 Δ= -3 √Δ= i√3 ⇒ x₁= (-3+i√3)/6 x₁= -1/2 + i√3/6 x₂= (-3-i√3)/6 x₂= -1/2 - i√3/6 ⇒ -1/2 + i√3/6 +1 = -1/2 + i√3/6 1/2 + i√3/6 ≠ -1/2 + i√3/6 ❌ ⇒ 𝕃 = ∅ is my answer ! P.S. Regarding your solution, let's consider your third method y₁= x+1 y₂= x Let's find the x value at the point where these lines intersect (if such a point exists). To do this, set : y₁= y₂ y₁= x+1 m= dy₁/dx= 1 y₂= x m= dy₂/dx= 1 ⇒ Since the slopes of the two lines are equal, they are parallel and will not intersect, therefore: 𝕃 = ∅

[@LILIANAVARGAS-lz5sl]

🤔🤔🤔🤔

[@xniyana9956]

Interesting video but this feels wrong. Infinity IS NOT a number so it cannot be a solution to an equation.

[@Xjxtimvbhf-ujnjdmczrdjqyt]

В третьем методе НЕТ КОРНЕЙ!!!

[@AdetunmiseAgbakosi]

Infinity or Indeterminate

[@olgamuradov]

Согласна , если к бесконечности прибавить 1 , все равно будет бесконечность Если от бесконечности отнять 1 все равно будет бесконечность .

[@xnttflm]

X can be infinity ♾️

[@Knightday1973A]

If x is equal to infinity it works. I don't see any other solution.

[@googolian]

Infinity is not a number 😢

[@carlossummers4992]

X+1=X, 1=X-X, 1=0. 🤭👍

[@tgx3529]

God Is Infinity

[@ronpfeiffer9157]

And Infinitely more

[@urubatandurval5245]

Impossível

[@danielntoko2117]

Prove that.verify it!