Electric Field from a Ring and a Disk

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Күн бұрын

Пікірлер: 35

@otuahbekoe8625 10 ай бұрын

Once you said it took you a while to get this, i knew i was at the right place. Cos people like you know how to explain it in the simplest of terms since you have been in our position before. Thank you. DOn't stop what your're doing

@affection231 2 жыл бұрын

sir you ended my nightmare about these topics. Best of luck for you and your family in the New Year 🎁🎀🎄🎄

@SuperSyntax-s7w 2 ай бұрын

Absolutely fantastic teaching

@noctao4163 Жыл бұрын

I liked how well this was explained I just started learning about this and it helps a lot.

@PhysicsNinja Жыл бұрын

Thank you!

@amandaliu7409 3 ай бұрын

omg these saved my life please keep making videos like this thank you so much

@PhysicsNinja 3 ай бұрын

Will do!

@Iwonder493 6 күн бұрын

5:01, Why can we assume angle theta will be the same for any dq on the ring? If dq was to be exactly on the x axis, wouldn't theta be 0?

@jojoo_aah8072 Жыл бұрын

Omg, the best explanation i had see so far!

@khaulamohammed19 2 жыл бұрын

Thank you so much, this was such a saver. Keep on coming more content!

@Pomegrante460 3 ай бұрын

Would the total charge Q be the area of the disk, if so why would it be the area & not the volume?

@johngordon8513 Жыл бұрын

i was your 420th like, youre welcome.... also thank yoooou, these vids are the bees earlobes

@godisgood2482 2 жыл бұрын

Are there any experiments video showing electric field due to ring? And is the ring always going to get uniformly charged if we try to charge it

@vaibhavgowda6725 2 жыл бұрын

If the ring is perfectly conducting/metallic then yes it will have uniform charge distribution regardless of how we charged it. Unfortunately I couldn’t find any videos showing field due to a ring irl.

@Patatas-p7u 8 ай бұрын

Doesn't x change depending on the distance of the point we're choosing to calculate the electric filed for?

@DoofEvil 3 ай бұрын

i have an exam tomorrow, please help!! how come in the first problem you integrated with respect to Q? when doing the same problem but with a vertical rod instead of a ring, i integrated with respect to y using lambda = Q/Y dQ = lambda * dY and plugging that in for q, which is how i was taught. because, they say, Q is not a geometric quantity. why did you integrate with dQ? how do i know when to integrate with respect to Q or Y? does the ring not still have a charge density lambda = Q/(2piR)?

@Gamernotgamer1996 Жыл бұрын

How did you modify the new limits?, any video or explanation on that.

@lucassarappa3327 Жыл бұрын

Hello friend, the video is very good, but I have a question with a similar exercise: I need to find the electric field at a known midpoint of 2 charged circular loops like the ones in the video (each with a different charge, both positive). I have to apply the formula that you show in the video for each of the circular loops, and then my question is: Should I add or subtract each of the results to obtain the electric field at that point? (taking into account that both charges are positive). Thank you so much

@ashqawala 2 жыл бұрын

Which type of gussian surface we will take in order to find E field due to a hollow capsule like object which have both hemisphere and cylindrical symmetry?