6 Pulley Problems

Physics Ninja shows you how to find the acceleration and the tension in the rope for 6 different pulley problems. We look at the free-body diagrams and apply Newton's laws to different pulley problems

[@Fahimsy3d]

Literally the best video ive seen on pulleys.

[@PenandPaperScience]

Yeah, it's really good :)

[@JohnVKaravitis]

Scare to think that there are people out there who live for KZbin vids re pulleys.

[@notreallydavid]

You can scrub 'literally' - it isn't doing anything. Please kick me. All best.

[@cortwill4085]

​@@notreallydavid, shut up, your being rude! @#$&!

[@umarmuzammil7332]

I agree

[@nathan6798]

You just cured my life time phobia of pulleys and FBDs. Thank you.

[@shutupimlearning]

honestly a lifesaver man, i look at problems like these and think "theres no way i can solve this". Thanks for the video!

[@opufy]

You must be adored by your community, need more ppl like you in this world

[@generalkickass9237]

Love the way you explain and speak . These little things help ALOT

[@corndawg5197]

You are amazing. I was strugling to understand this concept and you just explained it so well I didn't have to watch the full video. Thank you man.

[@fundamentalbighead6584]

You da goat

[@abdelrahmanmohammed3561]

Thank you very much. This is such a systematic and organized way of thinking and solving.

[@PhysicsNinja]

Thank you for the kind words! I greatly appreciate comments like yours

[@CaliCity10]

This is such a good explanation that you now have a new sub.

[@keishakwok4333]

@Titus Solomon these sites don't work

[@mariadragonbreath7130]

Your video made these pulley problems so much more understandable and simpler! Thank you so much for explaining the solutions clearly and in an organized way.

[@Zavenge]

This video actually helped me understand pulleys better than my own class. Thank you so much!

[@hamida.1054]

Great method. I used to be afraid of choosing downward as positive y-axis. Now I am not. Great job!

[@PenandPaperScience]

Being brave enough to be flexible with your coordinate axes is a crucial skill to have in mathematics and physics :) It oftentimes reduces problem's difficulty enormously.

[@numberone6955]

@@PenandPaperScience you good

[@PenandPaperScience]

@@numberone6955 :D

[@bhuvneshbhaskar2431]

​@@PenandPaperScienceikr it would feel like a silly fear but as a beginner we all have been through these phases

[@ludi1787]

THIS VIDEO HELPED ME A LOT , COULDNT UNDERSTAND WHERE EACH FORCE COMPONENT CAME FROM BUT NOW I KNOW , THX SO MUCH

[@bellt4682]

this is soo good it makes me wanna cry.....helped a lot and i have a test tomorrow tnxxx

[@SISKCERTWaJaVlogs]

pully problems were my kryptonite in physics class but with your videos, this helps resolves it keep up the great content

[@calebtourangeau9777]

you have no idea how much you saved my grade. tysm!

[@noonecandefeatme7866]

You can find acceleration easily by this trick Here : Net Force on the system / Total Mass of the system Tho you can't find the tension. Btw great video 👍

[@fatimaarif8392]

May god bless you physics ninja. this had helped me a lot in solving past papers.

[@adityajha4936]

Of what???

[@fatimaarif8392]

@@adityajha4936 physics

[@adityajha4936]

@@fatimaarif8392 Hmmm

[@mattspence5963]

Man you are a life saver. I have been acing calc 2, but I was struggling so much with pulleys lol

[@PhysicsNinja]

You got this!

[@AbdurRahman-wo7ro]

honestly , the best pulley video on the platform ... mister it will more useful if you have explained the x y direction and cos thing more in depth 👍

[@menglimarrero4296]

I like the animation. the lecturers intonation is not sleepy to hear. Very well explained how and why

[@ganizanijosephy7873]

One of the best tutors 🔥 🔥

[@subat9349]

Just wonderful. Easiest way for solving the pulley problems..watching from BANGLADESH

[@salih3191]

4:20 why did we Substracted the weight from the tension how did we know that the weight is bigger because it might be the other way around because the inertia of the first object is bigger then the second object so the tension force would be bigger then the weight

[@re1ive456]

He defined the downward direction as positive, and since the mg vector is downwards (positive) and the T vector is upward (negative), the equation is mg -T = ma (which can also be written as -T + mg = ma).

[@ibrahimabbas3728]

Thank you so much for this video sir. I was struggling with these types of questions for a long time, I’m solving ib past papers that have to do with pulleys and I’m finally getting it.

[@afrinahmed1620]

I liked your channel to make the total number of likes divisible by 3 made with three consecutive natural numbers including the smallest of the set. I liked then when this happened. For thinkers the number is 123 which I liked and made for his video. I am an IIT JEE aspirant and these problems I did in my first basic paper solving of nlm for pulley mass systems during my preparation. Edited to say thank you for helping me refresh and revise a bit. I am still preparing and hope to get selected the next time. Please pray for me😊

[@rahulsharma9671]

Bhai aapka JEE ka exam ho gya??

[@blockybunny]

Thanks you man you are best from all our indian teachers You explained it very easily

[@PhysicsNinja]

So nice of you

[@Pro_gamer69420]

thank you soo much for this explanation, I couldn't understand my teachers explanations at all, but thanks to this I have been enlighten.

[@kusumareddy3115]

This channelll is underrated ✨ wish a few billion subscribers ahead! 😌

[@jelly1761]

I really enjoy physics but the time that it was taking to figure out every single concept was concerning as my teacher is a bit... unclear? Finding your channel has given me hope in not dropping the entire subject! :) Thank you!!!

[@mayurpol]

Please upload more videos for also other topic it very helpful sir liked it

[@galaxi6585]

Thank you so much, my school uses these models all the time and this will help massively

[@aarohinuniwal7087]

Thank you for such a great explanation!!

[@Player-pj9kt]

Thank you so much I had difficulty understanding tension and this video cleared it up

[@Hackers-wrld]

You can feel the Tension between the blocks in his vohhice great video.

[@williamgriffith2822]

The best video i have ever seen on pulleys, appreciate from brazil

[@pessexe8591]

Sir your voice is so cool! I can hear it all day🛐

[@spaceeDolphin]

Your explanations made it so easy to understand these concepts, thank you so much!

[@dissaishara]

wooooow !! thanks p6ninja

[@jayt675]

who would not like it. you are very helpful. Thanks alot

[@PhysicsNinja]

You're welcome!

[@clashofmagicofficial256]

Can't understand why you have only 17.9k subs only

[@PhysicsNinja]

I think that quite a lot for a physics channel. Thanks for the the support. I'll get there.....eventually.

[@tshepangmashapa4415]

Thank you very much Great explanation 🤝

[@ninaayu8597]

thankyou for helping me. it's awesome.

[@PhysicsNinja]

Thank you!

[@daveber7000]

@@PhysicsNinja Sir may I ask. Sir at 6:18, shouldn't the answer be in m/s? instead of m/s^2?

[@manfredvonrichtofen3863]

Thank you so much, this video is very helpful!

[@chilukurileelavathi749]

Sir, your are great In my class room ,I am responding in good way why because I am listening your class Thank you sir

[@natevegh4602]

Awesome video. Thank you!

[@dankastik6477]

Thankyou for the short and sweet explanation ! Do you have a full explanation of this Topic?

[@ashfa4558]

This is soooo helpul cause its free

[@panch2oo2]

Awesome 👍 thank you so much for all the work you're doing 😌

[@spartaatrus5302]

Sir thanx u for helping; importantly the last question is such hard problem I appreciate it ❤

[@PhysicsNinja]

So nice of you

[@tda8649]

I have a physics olympiad in 2 days and this really helped understand pulleys :)

[@PhysicsNinja]

Good luck! You’ve got this

[@adityajha4936]

Is it good for International Olympiads???

[@adityachandrasingh615]

❤️ from india 👍 fabulous video it clear all my doubt

[@ahmedkadry7717]

Thank you so much for this video!! It's really helpful ❤❤❤

[@yasmeenibrahim7104]

May Allah bless you and your family this is sooooo helpful

[@jenojosephinmariya317]

The best✌

[@aradhyagaur9691]

Thank you brother. I am in 11th grade and your explanation is good. Kindly bring us some high level problems. BTW, all problems were pretty simple.

[@WritersDigest-b8f]

I like your teaching of physics. Could you cover problems from various aspects of physics with an aim to perfect mechanical comprehension. Improving mechanical comprehension through problem solving in physics would be a huge motivation to contnually learn physics. This approach would stick physics principles in mind and prompt the mind to question what why where how and reach the right conclusion. Thanks

[@nayrasadawy2098]

now this is a masterpiece 🌟

[@imrandeshmukh1956]

thank you so much

[@afrinahmed1620]

You can also include the infinite pulley problems and the concept of equivalent mass.

[@selamalemayehu6212]

You really helped dude Thank you so much🙏🙏

[@lidiauni6057]

Thank you sooo much! You explain very well :D

[@PhysicsNinja]

Glad it helped!

[@jisotico1172]

in question 6a, would there be a difference if i wanted to lower it a constant speed of 8m/s instead of 2m/s?

[@CereaLover123]

Exactly what I was wondering, same with the question before it, like the speed value was never used in the problem.

[@wiktoriaklimczak7775]

good explanations, just wish you added the force of frictions as well.

[@shobharani76]

Thank you for clear visualized explanation

[@HoodTrampoline]

Incredibly helpful, thank you!

[@ShadiFallahi]

awesome ,thanks

[@DennisKlein-jh4ui]

you are the man

[@vincentbanda4181]

Thanks so much for you have improved my knowledge

[@BensonRoman382]

Thanks

[@rupom_1670]

Is tension force anyway related to friction force?

[@srinivassrinu4389]

Great.....😊😊😊

[@NamanSinha69]

This was better than my class. Thanks for the video Sir

[@PamelaBoshtani-pt7gm]

Can you help me with this problem:In a container of negligible mass, there are 100 grams of water at a temperature of 80 degrees Celsius, 150 grams of water at a temperature of 10 degrees Celsius are added. After the thermal equilibrium is established, a piece of ice at a temperature of -25 degrees Celsius is added. Find the temperature of the water before adding the ice. , the heat needed to melt the ice, the final temperature of the water in the glass.

[@lisandrolisandro8100]

great video

[@PhysicsNinja]

Thanks!

[@yagmurkaymakci]

thank you so much for this 🙏

[@PhysicsNinja]

Thanks for your support!

[@ravangaming3078]

Amazing lecture🇮🇳

[@cliffmo6707]

In problem 5 & 6, what is the meaning of speed 2.0 m/s, any relation to the Tension force ?? Would it be the Tension force is the same when speed is 1.0, 2.0, 3.0 etc. ?? Does it mean the block can move for a long time if friction force in this force system can be ignored ??

[@omrmmmdzad6849]

T1 not= T2, because in the past we've been assuming that the tension in the rope is uniform everywhere. In this problem the rope is not slipping and the pulley is not massless, the tension is not constant in the rope. The tension depend on the mass. If Mass1 > mass2, tension 1 > tension 2 in the rope.

[@ericmora6287]

For problem 3 shouldn't the acceleration of M be negative since it's going to the left? Shouldn't it be Mgsin(theta)-T=-Ma?

[@aradhyagaur9691]

Bro signs are just to represent firection, so no there will be effect if the sign is positive or negatuve here because there is acceleration in one direction only, if acceleration was in two different directions then sign plays an important role.

[@arslanyaqoob9534]

Can you explain your point please ​@@aradhyagaur9691

[@shyamgovani262]

Thank you!

[@spurti]

Hii I have a question why we don't consider the rotational motion of pulley in this video???

[@shiqizhou4468]

for problem 6, what if two of the pullies are NOT connected to the block itself? Would it only be 4*Tension applied on the block then?

[@_BickromSaha]

For problem 5a, isn’t 14.7 N is the minimum force required to keep the block stable?. When we want to move the block to 2m/s and 10m/s or 15m/s force should be vary. Isn’t it?

[@partyprop]

We should double if 2m/s

[@partyprop]

Multiple with the speed

[@arslanyaqoob9534]

How to take directions for Tension T, weight mg, as positive and negative, please someone explain. Should follow the conventions of positive x axis and negative axis or direction of expected motion??

[@sltraveling7330]

very useful lessons

[@aox9558]

what a an amazing teaching way . thank u so much u have been wayy more perfect than my actual doctors lol

[@PhysicsNinja]

Wow, thank you!

[@adityajha4936]

Is it enough for physics olympiad??

[@sanjaytiwari2587]

This videos help me to understand the concept of pulleys question

[@graceanmelbonga430]

Hello! Thank you for making this video. But I have a question. In problem 6, letter a indicate that we should lower the mass with a constant speed of 2.0 m/s, hence a=0 m/s^2 Then the net force should be Fnet =ma =0 Fnet = 0 Mg - 6F =0 since the mass is lowered... Mg = 6f

[@graceanmelbonga430]

Just like in problem 5

[@mohitkhatri74]

Thanks a lot@👍👍👍👍

[@teksight9714]

In the first example i don't see how there can be any acceleration at all. If you hang a one pound weight from a ten pound weight sitting on a table with some friction the ten pound weight shouldn't move at all.

[@ya_papug]

Well that was very interesting Thanks a lot!

[@ianjohnmontalbo3033]

You're the best sir!!!

[@sibusisomavuso2942]

May please also calculate the time

[@gigi0858]

In the first example the two objects are in static or motion??

[@PhysicsNinja]

Has to be in motion because there’s no friction

[@gigi0858]

@@PhysicsNinja I have a picture of this problem with its solution and the writer analyzed the force in a different way ,can I send it to you to check if the solution is correct or not?

[@taslimbenalamprotik2013]

In problem 5, Which cable will experience the highest tension if there is frictions with constant frictional co efficients in all the pulleys??

[@peterlindquist2236]

In case 1,there can´t be any movement at all whit the weight 10 times more than the smaller weight!?

[@partyprop]

I think answer of problem 5 a) is29.4 as 14.7 is only force and for 2m/s force would be double

[@5xitz469]

What we should do if there is Friction