Op Amp Non Inverting Amplifier Design | Operational Amplifier Circuit

[@RC-Flight]

Informative and too the point! Thanks so much for taking the effort to making this wonderful video!! 🇨🇦

[@ElectronicsNotes]

I am really glad it was helpful!

[@DICEStudio-vq6gu]

First of all: wonderful, clear, insightful video, congratulations and big thanks from the bottom of my heart. I got just a few questions, when calculating the value of C1, we use the value of R3 in the equation. To calculate C2, which value of resistance should I use? and to make it clear as water, when using a TL071 opamp that operates on a single power supply (+V and GND), do I still need to create the half supply point you mentioned on 5:00 or is it all right to connect pins 7 and 4 respectively to +12V and GND? Hope I made my questions clear and hope I get some much needed help😅 Once again, congrats on the video, it's as masterpiece.

[@ElectronicsNotes]

To calculate the value of C1, the breakpoint is calculated using the values of R3 in parallel with R4 - the input resistance of the op-amp is very high and can be ignored.. As these are normally the same, the value will be half that of R3 or R4. This is because the resistance acting with C1 is the input circuit and nowhere else.The low frequency breakpoint occurs when the reactance of C1 is equal to the input resistance, ie R3//R4. In terms of the supplies, yes, connect the high voltage to V+ and the low voltage to V-. I hope this helps.

[@sorh]

great quick tutorial. many thanks.

[@ElectronicsNotes]

Glad you found it useful.

[@linkydoink]

Thanks for the great tutorial. Wish my lecturer could explain concepts in a clear manner like you.

[@ElectronicsNotes]

Glad you found the video useful. It is great when we are able to help.

[@jablonczyk]

Thanks for the video - very clear and informative! I'm still struggling to wrap my head around the significance of the C3 capacitor - why is it necessary to put it there? Why can the ground potential be bad for the inverting input? (I thought the ground has potential of 0). Cheers!

[@ElectronicsNotes]

When running an op amp from a single rail, it is necessary to keep the two inputs at about half the rail voltage. If C3 was omitted, then the inverting input would be linked both e zero volts line and would cause a large differential voltage to appear at the input. The output would then amplify this difference and head towards the rail voltage. This would render the amplifier useless. Hope this helps.

[@ari097]

Clear and very useful!

[@ahmetozdemir7173]

Hi, in theory the gain ratio is unlimited in the non inverting op-amp amplifier circuit. Is it actually possible to make a profit in this way? E.g; Can a 12mv sine signal be amplified to 12v with 1000x gain?

[@ElectronicsNotes]

Unfortunately, while an op amp has a very large gain, it has very limited bandwidth. The use of negative feedback enables the characteristics of an overall amplifier circuit to be tightly controlled, but because of the roll-off of the frequency response of the basic operational amplifier chip itself, I would not want to approach gains of 100 for an amplifier with a bandwidth of, say 3 kHz even, and generally go for very much less.

[@guitarguy3688]

Im confused about high & low pass filters i know that high pass filter blocks the low frequency & only allows the high frequency & vice versa but i dont know how to use them & where & when to use them can you help me Do you have any video about this

[@ElectronicsNotes]

No problems, as you suggest this might be an idea for a future video - we don't have one at the moment, but it is a good idea. As for where and when yo use them you might like to see our op amp filters haves: www.electronics-notes.com/articles/analogue_circuits/operational-amplifier-op-amp/high-pass-active-filter.php and www.electronics-notes.com/articles/analogue_circuits/operational-amplifier-op-amp/low-pass-active-filter.php Filters like these tend to be used in audio and other low frequency circuits as the bandwidth of the op-amp general limits them. Applications might include a high pass filter to only allow frequencies in an audio amp above mains frequencies, a low pass filter may be used where the top frequencies need to be reduced in level. They are used in digital to analogue and analogue to digital conversion to prevent a phenomenon called aliasing. I hope this helps

[@samsami9014]

very useful dear, keep going we will support to the maximum we can, if possible to do more complicated circuit calculating for OP-AMP, like the best way to make a transformerless power supply for OP-AMP with relay 24V, for example.

[@ElectronicsNotes]

Thai you for both of your comments. I plan to do some more op-amp circuits in the future, but I am currently heavily involved in a new spectrum analyzer video and a series on using oscilloscopes. After that I will try to get some more op-amp videos done.

[@samsami9014]

ElectronicsNotes ElectronicsNotes appreciate your reply... and a spectrum analyzer and oscilloscope tutorial is a very very useful for any electronic designer... I'm waiting it definitely... and also I'm at your right hand to help any anyway... currently will do my best to widely share all your videos 🖒

[@ElectronicsNotes]

I really appreciate you sharing the videos - it really helps. Many thanks - keep up the good work.

[@weanichsanchol7876]

About C2 how to calculate it? thank you

[@ElectronicsNotes]

As suggested, use exactly the same logic as used on the input capacitor. The breakpoint occurs when the capacitive reactance equals the old impedance assuming the source impedance within the op amp is negligible. The frequency at which the capacitive reactance equals the old impedance is the break point. I hope this helps.

[@nurulaini3571]

can I ask why we should add capacitor? what if we dont?

[@ElectronicsNotes]

The capacitors are used to isolate the DC voltages on a point. If there is DC then the lack of a capacitor will cause the circuit to work incorrectly or not at all.

[@nurulaini3571]

ouhh.. i see.. tq for the answer. appreciate it :)

[@santoshdebakikrishna381]

Best

[@ElectronicsNotes]

We are currently working on a lot more videos to appear over the coming weeks and months. Thanks for your comment.

[@zer0b0t]

can i use low values for r1 and r2 like 10ohms and 100ohms?

[@ElectronicsNotes]

They strike me as being rather low, but you can always try.

[@faizd1330]

I keep calculating C1 to be 15.9nF, where am I going wrong?

[@ElectronicsNotes]

Not sure where you are going wrong. For a break point of 100Hz and an input impedance of 1K the reactance of the capacitor must be 1K at 100Hz. C=1/ (2 pi f R) = 1000000 / 2 pi 100 1000 uF. Take 2 pi as 6 then C = 10 / 6 = 1.6666 uF - we can use a 2uF capacitor.

[@merrittderr9708]

@@ElectronicsNotes A little late here, but when using a calculator that has a set value of pi to 16 decimal places, the result is 15.9 nF. The difference is probably not worth worrying about.