(Organic CHEM) CH 7 Alkyl Halides and Nucleophilic Substitution Part 1

[@kondwelaniphiri8304]

Thanks man. It's because of you that I now understand alkyl halides. Keep up the good work.

[@sheila558]

you explain things really well. please put out these same videos for organic chemistry semester 2 chapters!!!

[@AbacherBbwaami]

Powerful and interesting lesson. It's because of you that I now understand alkyl halides better ❤❤

[@ChemistryProfessor_unStoned]

Glad it was helpful!

[@natokevin5711]

Good work, I love your work, you've changed my life🙏👍

[@kishan-dt2el]

Thanks sir for providing that type of video 🤞🤞🤞🤞🤞 love from India ❤️

[@galileachavez4953]

How is chloride the best leaving group with a pka of -7 while Iodine has a pka of -10 making it more negative meaning more stronger acid which has the weakest conjugate base = the best leaving group...I'm confusedddd

[@ChemistryProfessor_unStoned]

It isn't. Someone else had brought this up recently. I must've been looking at HCl at the top and H3O+ at the bottom, thinking there's a trend (best LG at the top and worst at the bottom). But clearly that wasn't the case here. Honest mistake.

[@immy6796]

Firstly, thank you so much for this video, it’s helping me understand this unit a lot better! I had to go back to the basics of alkyl halides to relearn SN1 SN2 E1 and E2 rxns 😅 also a question: in 7.7a you drew the N (in the product) with 3 methyl groups, but shouldn’t it be 3 ethyl groups?

[@ChemistryProfessor_unStoned]

Thank you! Yes that's definitely an oversight. Instead of methyl groups, the substituents should be ethyl.

[@THE-BEAT-BENDER]

Thank you very much for this video it very helpful 🙏. And On 35:00min the better leaving group should have been iodide looking at the pka values and not cl if not would love an explanation on that one 🙏🙏🙏?

[@ChemistryProfessor_unStoned]

You're correct! HI is the stronger acid which means I- is the weakest base and therefore the best leaving group. I must have been looking at Cl- and H2O.. honest mistake.

[@muhete10]

Thanks a lot sir!!! can I get some videos on addition reaction and chemistry of aromatic cpds please!

[@maythamal-taie3824]

This is the best explanation for alkyl halide, could I get the lecture as a pdf please

[@mirjanavrdoljak899]

very nicely explained, thank you. I would like to ask you for help with the following chemical equations, I am not sure what the products of the reaction are: a) (CH3CH2)NH + HCl b) HOCH2CH2NH2 + CH3I(in excess) c) piridin + CH3CH2Cl. thanks !

[@alissarosea]

why were there no lone pairs around I- for problem 7.6 (c) ???

[@ChemistryProfessor_unStoned]

Hi there! It is implied that there are 4 lone pairs around it with the negative charge. Typically in organic chemistry, lone pairs are not shown in the structure but just be aware that they are there.

[@symphonyalvarez3122]

thank you!!!!!

[@sadafabdulwakil2824]

why there is a lone pair on Hydrogen in question 7.10 d? why not on the Carbon because it is electronegative element.

[@ChemistryProfessor_unStoned]

Good observation! If a very strong base reacts and deprotonates an alkane, the lone pair will be on the carbon atom, giving it a negative charge. It would not be on the hydrogen as shown in the video. However, a carbanion (negatively charged carbon) is still a very strong base (like the hydride ion), which makes it a poor leaving group.

[@alderamin1402]

For the example b in 24.20 min, how can we proceed a substitution reaction for a secondary alkyl halide? I thought that there is a steric hindrance preventing an SN2 reaction so making an elimination reaction instead

[@ChemistryProfessor_unStoned]

Secondary alkyl halides are tricky when it comes to Substitution and Elimination Reactions, because they can go SN1, SN2, E1, and/or E2. It'll depend on what's "attacking" the alkyl halide. Since this video is specifically for Substitution Reactions, I only show Substitution products.

[@alderamin1402]

@@ChemistryProfessor_unStoned Would it be better to do an elimination reaction if it was not stated that we had to do a substitution reaction? Thank you for your answer Professor

[@ChemistryProfessor_unStoned]

It's not that a Substitution reaction is better than elimination and vice versa, it's the type of reagent you're using to react these 2ndary alkyl halides with. A strong non-nuclephilic base will definitely favor elimination over Substitution. Using a strong nucleophilic base leads to both en elimination product (E2) AND a Substitution product (SN2) - a mixture.

[@alderamin1402]

@@ChemistryProfessor_unStoned I got it 🤩👌 I cannot tell you how much you help me endless thanks✨ btw I am so excited for your new videos

[@NaveedHussainJunejo]

nice effort

[@mainzamatongo428]

can either the leaving group or the nucleophile deprotonate the product from the substrate

[@Duckytaro]

I was wondering, do you have a website or anything where you might be uploading the pdf for all your organic chem semester 2 videos? 🤔

[@alderamin1402]

Hi Professor! Could I learn about when you will start to record new videos? I am waiting for them so bad 🤣

[@ChemistryProfessor_unStoned]

Several new videos for CH 12 will be published within the next 2 to 3 weeks!