Overloading Unary Operator in C++ | C++ Tutorial | Mr. Kishore

[@NareshIT]

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[@gloryofgames1607]

//I get error #include using namespace std; class Abc { public: int a; ABC() { a=0; } void input() { couta; } void show() { cout

[@4.otechnologysaikumar829]

@@gloryofgames1607 me to broo...I have also error...

[@ahadsun1188]

i have never seen any videos with this much details,hats off you Sir.....Respect 1000

[@stockmarket_matrix]

The given example is post increment so the below is the way to write it: #include using namespace std; class test int a; public: { test() { a=20; } void operator++() { ++a; } void operator--() { --a; } void operator++(int ) { a++; } void operator--(int ) { a--; } void show() { cout

[@whoisnegii]

please explain why it has to be done like that ?

[@sunnyjain630]

Thank you!

[@lemonpooh1764]

thank you so much

[@shashankgupta6700]

Sir you are the best .....I have seen so many videos of opeator overloading but did not get the concept and then i watched your video all concepts are clear.Thank you so much sir

[@yuvrajsharma2134]

Your teaching and content is very good. Really feels good to be on your channel.

[@codingwithmx]

It was two errors in this code: you need to correct: void operator ++ (int){a++;} and void operator -- (int){a--;} because the unary operator has only one implicit and it also an integer.

[@JohnDoe-ej6vm]

thanks a lot . but plz exmplain why we face error , and how parameter is working in this function ?

[@shrishojha6490]

thanks , what sir is doing would be right if he would have been using pre increment operator

[@troopIine]

correct that's right

[@HarishKumarC007]

Wonderful, thanks a lot

[@ekambaramsainikhil9301]

we need to call the function as operator objectname eg: ++t where ++ is the operator and t is the object name

[@ajaykharat8689]

Generally operators are designed to work with pre-defined datatype. In order to use operator with user-defined datatype operator are overloaded. In operator overloading:- a. With Binary operator 2 objects are required(one implicit and other explicit) b. with Unary operator 1 object is required(one implicit on LHS) void operator ++() { a++; cout

[@arjumandayoub8483]

the reason for error can be explained as : The code you provided contains a compilation error because the `++` operator is overloaded as a prefix operator, but it is being used as a postfix operator in the `main` function. In C++, the `++` operator can be overloaded as both a prefix and a postfix operator. The prefix version of the `++` operator is declared by defining a member function with the signature `void operator++()`, while the postfix version is declared by defining a member function with the signature `void operator++(int)`. In your code, you have defined the prefix version of the `++` operator by declaring the member function `void operator++()`. However, in the `main` function, you are using the `++` operator as a postfix operator when you write `t++;`. This causes a compilation error because there is no matching overload for the postfix version of the `++` operator. To fix this error, you can either change the usage of the `++` operator in the `main` function to use it as a prefix operator (`++t;`) or define an overload for the postfix version of the `++` operator in your class. Is there anything else you would like to know?

[@iniyaviji2796]

Lovely sir thank u so much

[@jaypatel9392]

Thank u sir for providing your valuable knowledge ❤️

[@tayyabshahzad2747]

you are a good instructor. t++ //Error because compiler treat it as binary operator. if one wants to run this , he/she must use it as binary operator. #include using namespace std; class fun{ public: int a; fun(int x):a(x) {} void operator - (int i) { a=a + i; cout

[@darshkatare8896]

sir I scored good marks in practical exam because of you love u sir❤❤❤❤

[@lincycarolinesagayam6726]

It makes us feel easy

[@sushantgupta4757]

Thanku so much sir 😍😍

[@aishwarya2860]

Excellent sir

[@bs_it4975]

Thanks sir!

[@gopialavala8618]

sir in the place of a=0, with out using the zero it can be treated as the zero initial value

[@harshavardhantp8308]

When we are defining the constructor. Do we have to define default constructor or will it define itself

[@arslanbegmyradov3048]

whithout ERROR - Program should be: class Sample { int a; public: Sample() { //default constructor a = 0; } void operator++() { a++; // implicit } void operator--() { a- -; // implicit } void printValue() { cout

[@rambhaktuchihaobito7987]

Thank you bro

[@mohitsaud2071]

//Actually the program for the post fix is // #include using namespace std; class Test { int a; public: Test() { a=0; } Test( int n) { a=n; } void operator ++(int) { a++; } void operator --(int) { a--; } void show() { cout

[@ernisrisatyavennela3523]

can't we use pre increment operator for overloading?????

[@dharmadevi9817]

pls upload all java concepts.rly nice class

[@vaishnavidubeyit_0309]

Sir in unary operator if we have to increment & decrement in two different values means suppose a++ & b-- so how we can use it .

[@al-hadees6236]

there is small mistake in void main instead of t++ and t-- the correct way is ++t and --t

[@ashishmishra-yu1jr]

Sir here pre increment and pre decrement work not post increment/decrement

[@unknownchannel1924]

just change a++ to ++a and a-- to --a similarly for t also.

[@shubhampandey1073]

sir can we overload the += operator or not

[@amitkumargupta6722]

here is the code for this program..... #include using namespace std; class test { int a; public: test() { a=0; } void operator ++ (int) { ++a; } void operator -- (int) { --a; } void show() { cout

[@4.otechnologysaikumar829]

Here postfix oparator using to become error sir......then output become when the prefix oparating using.........whyyy this happend sirr

[@rakshith3458]

Can we refine "+" operator to subtract two operands instead of addition using operator overloading ?

[@milindmodi4762]

yes you can but only with user define data types.

[@AryanRaj-gm6pu]

yes you can do

[@viswanathgupta7406]

load sessions on function overload sir

[@rahmanullahshirzad7865]

sir this is towice run but error what is problem?

[@shubhampandey1073]

sir this programme show an error in ide

[@HarishKumarC007]

So in comment section, they have changed please go once, even I faced same thing

[@ravikishore1743]

Why & is present in the declaration of the Operator ++ overloading in the blow code sir? Complex &Complex::operator ++(){ } Please suggest. Also i saw some code where * is used instead of & like belo Complex *Complex::operator ++() { } Please explain.

[@venkatp9381]

& refers to reference, so a reference of class complex is the return type. If i t is *, it is pointer to class complex

[@sumanthkavikondala1036]

This code wont work, as you had overloaded the operator for prefix(pre-increment) and you were using postfix to call the overloaded function by ("t++") but instead "++t" would work. Where as postfix overloading is having a different syntax to do so by passing a dummy int as a argument. Sir please educate the correct information instead misleading the students. I understand that you are trying to educate students for free here but i feel its better not to teach at all instead of passing false information.

[@gamuchiraimureyani281]

actually the misleading person is you

[@sumanthkavikondala1036]

A concept is a standard which cant be manipulated by any individual apart from the creator. Because of people like you students are getting wrong information and they carry the same to others.

[@smarttube1141]

Yeah Correct bro...

[@adityadubey408]

yeah you are correct I found out the same error

[@adityadubey408]

shut the f*** up !

[@arjunmenonkandanat6328]

what he is telling is wrong. This program will be of pre increment operator. NOT post increment operator in main() , he has to write ++t , instead of t++