Hello madam. I'm french so i apologize if i do mistake with my english. Instead of looking for (-2)^x=2 , i tried with (-2)^x=4. Obviously we know the answer x=2. But doing the same demonstration i found x=2ln2/(iπ+ln2). Why this is a real number? Why this is equal to 2?
@arvindkulkarni6580Күн бұрын
Good evening mam
@LaxmanKumar-yi4cvКүн бұрын
Good morning
@themieljadida445914 сағат бұрын
Minus minus two........ Good bad good.bad bad ....
@olafvanditzhuyzen483015 сағат бұрын
1
@Nikioko18 сағат бұрын
(−2)^x = 2 x ⋅ ln(−2) = ln(2) x = ln(2) / ln(−2) x = ln(2) / [ln(2) + ln(−1)] x = ln(2)/ln(2) + ln(2)/ln(−1) x = 1 + ln(2)/(π ⋅ i)
@nicolasfonteneau03108 сағат бұрын
x = ln(2) / [ln(2) + ln(−1)] x = ln(2)/ln(2) + ln(2)/ln(−1) ? Are you sure that a/(b+c) = a/b+ a/c... I think it's (a+b)/c = a/c+ b/c
@Nikioko6 сағат бұрын
@@nicolasfonteneau0310 Yes, you are right. x = ln(2) / [ln(2) + ln(−1)] x = ln(2) / [ln(2) + π ⋅ i] I was a bit sloppy.