Palindrome Number | Leetcode problem 9

Palindrome Number problem.
Leetcode problem number 9.
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[@roqyaquran241]

Great job, thank you👍😊

[@daylanbueno]

Great solution. nice work.

[@vickykarma2846]

Your explanation is excellent😊

[@puneetpal1466]

Well explained...

[@SumitChouhan-ss5tt]

I just have a silly questions?? How much time the loop run ???

[@nilesh_dac841]

you are doing very nice work mam ,please upload some more videos on array 🙏🙏🙏

[@thefourhourtalk]

super easy explanation thanks

[@saishankar5005]

Very good explanation madam!!

[@AhmadRaza-ff1rk]

hey, it's not reversing the example -121 ad 121- , by logically it's also not possible because we are dealing with number no with string int x=154; int temp=x; int rev=0; while(x!=0){ rev= rev *10 + x%10; x =x/10; } System.out.println(rev); if (temp==rev){ System.out.println("Yes"); }else{ System.out.println("no")

[@TechnosageLearning]

Hi This problem is to check if a "number" is palindrome or not .so it ll work for numbers only

[@sumitSdhondikar]

vs code me public boolean method write kiya to code run nhi huwa kiyu

[@AjaysFrictionLab]

thank you mam

[@nikhilnanhe3410]

Cool

[@harshojha6118]

what is the recursive solution of this

[@zohebansari6429]

Can you tell why it is not wrking for negative number ??

[@TechnosageLearning]

Because negative numbers are not palindrome numbers...if yoh reverse -131...Reverse would be 131-....both are not equal...so its not a palindrome number

[@zohebansari6429]

​@@TechnosageLearningcan you tell me what I had to make changes in code so it work with negative number public boolean isPalindrome(int x) { int rem = 0; int temp = x; int rev = 0; while (temp != 0) { rem = temp % 10; rev = rev * 10 + rem; temp = temp / 10; } if (rev == temp) { return true; } else { return false; } } }

[@MaheshKumar-mt5wp]

@@zohebansari6429 public boolean isPalindrome(int x) { if(x

[@amanparmar1170]

Can we also solve the same problem with help of for loop

[@reon_fernandes]

While loop?

[@empty_peace]

*why it's wrong??!!!* (c++) #include using namespace std; int main() { int x ; cin>>x; int n = x ; if(x > 0) { int rev = 0 ; while(x > 0) { rev = (rev*10) + (x%10) ; x /= 10 ; } if(n == rev) { cout

[@DOINGSOLUTIONS]

IT DOES NOT WORK AS 1234567899 IS NOT A NOT IN RANGE

[@TechnosageLearning]

It will return false in this case!

[@samadkhan3703]

if number is 11 then it will throw false

[@TechnosageLearning]

No..its returning true..Please try!

[@JS_shorts_dev]

this is not going to work on all test case like number 10 and you didn't solve on leetcode...next time show your leetcode code also

[@TechnosageLearning]

It is working for all the scenarios..I have tested on leetcode..please take the code from git and then give it a try..and in recent videos i am showing it on leetcode as well

[@dohongquank15hl39]

if (x