Parallel plane waveguide

[@ChandaKumari-id8jm]

its like im watching a story.... everything is soo understandable.. thanku sirrr

[@naumanali1595]

you are the best teacher who explain physics very beautifuly with the help of mathematics ...great sir .. lov efrom pakistan

[@paxtonguillermo3924]

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[@josezeke8808]

@Paxton Guillermo Flixportal =)

[@paxtonguillermo3924]

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[@josezeke8808]

@Paxton Guillermo glad I could help :)

[@subrahmanyannamboothirykk3544]

Thanks sir for your great effort to explanation

[@negargh4208]

Thank you.you make it easy to understand

[@joshithmurthy6209]

53:00 was eye opener

[@sripavani6328]

best one I have ever watched

[@Dhruba99]

What would happen exactly, if the distance between 2 parallel plates isn't integer multiple of m? (It is something like impedance matching, that otherwise it would have a reflection (or distribution)?

[@chhavichaudhary8870]

Amazing

[@anime_gaming__007]

At theta equal to π/2 propagation will be parallel to wave guide then in that case it should be maximum but as cos theta is equal to m times lambda divided by two times d then at theta equal to π/2 wave will not exist. Please someone explain.

[@sharmaji5298]

See, there are two parts in the equation of E(electric field). First one is standing wave [Sin{BxCos(theta)}] and another part is travelling wave {Sin(theta)}. It is given that, theta is equal to π/2. Here we can see that travelling wave consists of sin term which will immediately take the highest value and becomes zero but for the standing wave part, the overall term becomes zero. The inner cos will become zero making big theta 0 for Sin term and hence overall zero for standing wave part. Now comes the equation part of E(Electric field) where standing wave and travelling wave are in multiple fashion and we already know that anything multiplied by zero will become zero. Hence it is advisable to not use parallel incident wave in parallel plane waveguide because the E term for that wave will become zero automatically making it non-trackable at another end of the waveguide.

[@anime_gaming__007]

If theta is 0 degree then according to you propagation will be max but then group velocity will be minimum and at theta = π/2 the group velocity will be c . And what will happen if I increase my d and keep theta = π/2?

[@mr.rachetphilanthrophist601]

I calculated average Power using Poynting vector whose expression was directly propotional to (sin squared of theta) times (sin squared of (beta ex cos theta)). So, in Both cases either you put theta= pi/2 or theta =0, you will get Average Power flow in z-direction as zero, so you will have to sent wave at some Inclination to the interface as sending, either parallel or Perpendicular to it, both propositions won't work.

[@mr.rachetphilanthrophist601]

@anime_gaming__007: What you are saying at theta =pi/2 (parallel) to conducting interface, yes wave will travel but It will be simple Uniform plane wave travelling in z direction in medium 1 with its intrinsic Impedence eta 1. In waveguides we need two Waves interferring with each other(Where is second wave? At theta =pi/2 there is none, so it is just like earlier lectures Simple UPW propagation in a medium you can find power and everything as you find for A travelling wave and it would work.) Such that it guides Energy alongwith it, how ? In the form of Surface current on conductor interface itself i think. So energy travel in Periphery in the middle everything is hollow where you are proposing to launch a linearly polarized wave. But waveguides by way of interferance Create energy to travel on those boundaries not in the middle, which you can't achieve by doing theta = pi/2. At theta =0 one wave only bounce back and forth up and down creating standing waves along x direction. Components of magnetic field will cancel out and wave would not be able to travel again in z direction. So in both cases either theta = 0 or pi/2. There is no powerflow occuring as warranted accordingly by Waveguide (on conducting surface, not in the middle).

[@toshakrajuprety6747]

Awesome

[@rgudduu]

Parallel plane waveguide

[@gouravtripathi3663]

Currently I'm the only one here in 2024..🫠

[@mr.rachetphilanthrophist601]

Chup be lomdhu.

[@mr.rachetphilanthrophist601]

Back clear karata hai sabka khaali.