Parallelogram in three dimensions (Exam Question 8 of 10)

[@uroki_obshestvoznania]

Привет! А какую программу для уроков вы используете?)

[@harshgupta8726]

Love from India🇮🇳🇮🇳🇮🇳

[@arvindgupta7798]

Love you sir from India 🇮🇳🇮🇳🇮🇳

[@mrigayu]

I believe you equated the vector PS to the vector QR, not the way you've written it. Although, either if consistently approached would yield the proper solution as you've done.

[@jursamaj]

I did the 2nd method, and found it to be very low cognitive load. I started with P-Q and R-Q to get 2 adjacent sides. I added those together get QS. Adding Q to that gets S. The net result is S=P+R-Q. This was all thought out symbolically, then I filled in the values. Now that I think about it more, it could have been simplified by noting that P+R=Q+S (diagonals of a parallelogram both average to the center).

[@reubenmanzo2054]

In regards to which vectors should be compared, how do we know which point is opposite S in the parallelogram?

[@adrianpilot159]

when a shape is named the points are always named in clockwise or counterclockwise direction in alphabetical order. so in shape ABCD, A is opposite C and B is opposite D

[@dogpinetree9315]

I'm a little bit confused with this solution; it seems like it requires a priori knowledge of where the points lie. For instance, why cant the parallelogram be drawn with P in the lower right corner of the parallelogram and S in the lower left?

[@adrianpilot159]

when a shape is named the points are always named in clockwise or counterclockwise direction in alphabetical order. having p on the right and s on the left would mean it would be named PRQS (starting from P going counterclockwise). its a naming convention used to avoid confusion

[@riteshpatil4711]

Great 💯💯

[@arirooz6240]

Well done. Thank you so much

[@Alessandro-sg5eg]

Love from Italy!

[@peglegpaul2091]

What class level is this for?

[@programaths]

In Belgium, we give that to 13 years old.

[@miikey_lol]

Can't you just do OS + QR

[@denissssss8579]

Nice

[@rajak4768]

Super

[@PatrickPecoraro]

First?