Partial Recursive Functions 3: Composition

  Рет қаралды 11,110

Hackers at Cambridge

Hackers at Cambridge

Күн бұрын

Пікірлер: 12
@BelegaerTheGreat
@BelegaerTheGreat Ай бұрын
One of the best educational video series on the internet. You should do this for life!
@user-nc4sj5ht2s
@user-nc4sj5ht2s Жыл бұрын
Man, you saved my life.
@taniushkaaa
@taniushkaaa 6 жыл бұрын
Very well explained. Thank you a lot!
@lucianoferrara4781
@lucianoferrara4781 3 жыл бұрын
Thanks for the great video series. Could you share the book title used throughout the course? You explained the topics very simply and my hope was to find the rest of the course on the book you used at your University. Thanks
@saravananm2280
@saravananm2280 4 жыл бұрын
You made this concept really exciting. Thank you very much
@lolomimama193
@lolomimama193 4 жыл бұрын
Brilliant. Was needing this.
@ivanoval1
@ivanoval1 6 жыл бұрын
Thank you for work. it's very good material feed.
@joseville
@joseville 3 жыл бұрын
7:37 how would one actually define add in this system? I know how to do it in lambda calculus using n-fold composition on the successor function, but not sure how to bring that over to this system?
@davidgao3005
@davidgao3005 Жыл бұрын
It is in the next video
@lucianoinso
@lucianoinso 6 жыл бұрын
Thank you!
@joseville
@joseville 3 жыл бұрын
3:17 I was a bit confused at first why you're defining composition in this way which is so different than how I've seen it defined, but then I realized the composition I'm used to is just the case where n=1 f ᐤ [g1]x = f(g(x)) Can n be 0? I.e. f ᐤ [] = f() would be a the composition of a function that takes no arguments (such as zero^0) with 0 functions).
@mohammednurhussien3285
@mohammednurhussien3285 5 жыл бұрын
please do for us another examples of composition
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