Hardy cross method

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Pavika fluid says Tawi

Pavika fluid says Tawi

Күн бұрын

Пікірлер: 50
@jagdeepheer9204
@jagdeepheer9204 3 жыл бұрын
You saved my midterm Sirji, Love from Edmonton, Canada
@hammadkhattak3290
@hammadkhattak3290 4 жыл бұрын
outstanding teaching....aisa teacher ho to kon class bunk karega
@liverpoolalloverworldfans7425
@liverpoolalloverworldfans7425 Жыл бұрын
Acha G. Tek hh. Likn Kuch khas nai is lectures main. Banda khod pansa huwa hh. Apko kia samjaya ga
@liverpoolalloverworldfans7425
@liverpoolalloverworldfans7425 Жыл бұрын
@Shoukat ullah battani from UET Peshawar Bannu Campus
@beere_taran
@beere_taran Жыл бұрын
You're a lifesaver sir God bless you!
@You-ul8ku
@You-ul8ku 4 жыл бұрын
Very nice explanation better than my stupid professors.
@sherzakir
@sherzakir 3 жыл бұрын
Great explanation , great art of teaching
@AdityaSingh-gh6th
@AdityaSingh-gh6th 4 жыл бұрын
Thankyou sir for explaining this complicated topic in easy way 🙏
@ritikhatwar1558
@ritikhatwar1558 2 жыл бұрын
thank you sir this video helped us alot thank you very much
@sandipbudhathoki5737
@sandipbudhathoki5737 3 жыл бұрын
Thankyou very much sir ,it helped me a lot
@saqibnabi5782
@saqibnabi5782 2 жыл бұрын
excellent explanation
@asharai9538
@asharai9538 3 жыл бұрын
Thank you sir jee for this crystal clear explanation. However, if deltaQ=0, then then middle term of the equation should be 0 as well right? That is 2*Qo*deltaQ=2*Qo*0=0
@rafiahmad4793
@rafiahmad4793 2 жыл бұрын
Bro delta Q can't be zero The value of detla Q tends to zero means very less Let value of delta Q is 0.2 Then square of delta Q is 0.04 This value if very less compare to Q that's we have neglect that portion
@nawaratnarajasajun9031
@nawaratnarajasajun9031 4 жыл бұрын
darcy equaton is = fLv^2/2gD right ? why did u put 4 in front of the equation ?
@theunboundedspirit3313
@theunboundedspirit3313 4 жыл бұрын
That's modified darcy equation.
@gangadharijyothsna9761
@gangadharijyothsna9761 4 жыл бұрын
flv^2/2gD mai f hotha hai friction factor. Aur f=4f' (f' = coefficient of friction). therefore it is modified to be 4f'lv^2/2gD. (people usually denote with f and it doesnt matter until you substitute a value for it.)
@mujahidfaraz9127
@mujahidfaraz9127 4 жыл бұрын
Thank you very much sir. You have really good explaining skills.
@BACVBalagi
@BACVBalagi 4 жыл бұрын
More then my teacher .... rispect sir👌👌
@HELLO-ys1wt
@HELLO-ys1wt 5 жыл бұрын
sir plz sink source doublet pr video bnaye plzz
@rahulbhati4749
@rahulbhati4749 5 жыл бұрын
Sir plss kro n upload fixed beam k numerical or unke concept
@youtubeshort5978
@youtubeshort5978 3 жыл бұрын
Hardy cross method, is suitable for long and narrow pipe?
@arandomchannel56
@arandomchannel56 4 жыл бұрын
Best explanation
@ditanshushah4035
@ditanshushah4035 4 жыл бұрын
awesome explaination keep up!
@aadityaojha1003
@aadityaojha1003 Жыл бұрын
4 min ke gyan ko 26 minute tk khinch diya👍
@amgo6838
@amgo6838 Жыл бұрын
Tho usme konsi badi baat hai , 1 ghanta ka video bi pura dekhne ka baat , 5 min ka gyan hi hota hai..
@HariPrasad-ox5ri
@HariPrasad-ox5ri 4 жыл бұрын
Thanks a lot sirji!
@animeshdhara997
@animeshdhara997 5 жыл бұрын
awesome sir thank u
@AKHILESHKUMAR-sf1yz
@AKHILESHKUMAR-sf1yz 5 жыл бұрын
Well explained sir
@76abhishekpandit
@76abhishekpandit 5 жыл бұрын
Thanks Man From IIT K Civil saved me on last before exam
@harleylord2752
@harleylord2752 5 жыл бұрын
Do u guys also study day before exams?? 😂
@jashwantsingh3907
@jashwantsingh3907 4 жыл бұрын
😂😂
@Hya_vaihalxa1123
@Hya_vaihalxa1123 5 жыл бұрын
But in my book formula for head loss is given as 4flv2 by row g d... Or flv2 by 2gd....
@TheClinchMagazine
@TheClinchMagazine 5 жыл бұрын
4f is Darcy friction factor where f is coefficient of friction. if (flv²)/2dg is used it means they used friction factor ie, 4 times the coefficient of friction If (4flv²)/2gd is used it means they are using coefficient of friction In short Friction factor = 4 times Coefficienr of friction
@ganeshbahadurlamichhane9112
@ganeshbahadurlamichhane9112 5 жыл бұрын
Thank you sirrrr
@shyamsundaryadav8752
@shyamsundaryadav8752 4 жыл бұрын
Videos clear nahi aarahe hai, sir, Thora clear bana nae ka kosis kariyae plz sir
@mahzaibnasir917
@mahzaibnasir917 3 жыл бұрын
if we assume Q0 correct just as our actual Q and get delta Q =0 then should not we get 2Q0deltaQ =0 as well as 0 multiply by anything is 0
@shivdannaruka9388
@shivdannaruka9388 5 жыл бұрын
Thank you
@sarbagyaadhkari6159
@sarbagyaadhkari6159 5 жыл бұрын
Thank you sir
@Abhishek-ml2tm
@Abhishek-ml2tm 5 жыл бұрын
sir plz upload water resource enginee.... videos
@MickyOnline
@MickyOnline 3 жыл бұрын
∆Q = 0 hua to poori equation mai change hogi na value. Apni marzi se kahi bhi change krloge value?
@purbayoneast
@purbayoneast 2 жыл бұрын
you look like Vidhan from 2 foreigners in bollywood
@shivekumar9906
@shivekumar9906 5 жыл бұрын
Thanku sir
@vishnuvijayakumar160
@vishnuvijayakumar160 5 жыл бұрын
Do class in english
@ayushmasharma2857
@ayushmasharma2857 5 жыл бұрын
tx sir
@shahfaisal1599
@shahfaisal1599 5 жыл бұрын
If delta Q zero then summation of r2Q delta Q will also be zero plze someone explain...???
@terguliruk1118
@terguliruk1118 5 жыл бұрын
Actually ∆Q is not zero it is very negligible as compared to Q( assumed discharge) hence ∆Q^2 was neglected..
@prashantkumarranveer3867
@prashantkumarranveer3867 2 жыл бұрын
∆ Q zero to € r^2 Q ∆Q bhi zero hona chahiye
@MickyOnline
@MickyOnline 3 жыл бұрын
Hardy and cross were two different scientists not One !
@kralkirpi6345
@kralkirpi6345 5 жыл бұрын
please use the language that you speak on title it is embarrassing
@mehranahmadyousafzai
@mehranahmadyousafzai 4 жыл бұрын
Thank you Sir
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