Software Radio Basics

  Рет қаралды 89,057

Pentek, now Mercury Systems

Pentek, now Mercury Systems

Күн бұрын

Topics include Complex Signals, Digital Downconverters (DDCs), Receiver Systems & Decimation and Digital Upconverters (DUCs) Transmitter Systems & Interpolation.
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Пікірлер: 46
@huutruongle
@huutruongle 3 жыл бұрын
It's a most perfect fundamental SDR presentation I've ever seen. Thanks for your contribution.
@kumark353
@kumark353 2 жыл бұрын
Excellent presentation of software Radio with much needed basics
@ChaplainDaveSparks
@ChaplainDaveSparks 2 ай бұрын
I absolutely *LOVED* this presentation! I graduated in 1976 with a BSEE, but all of this was a practical impossibility due to the relative slowness of existing compute power. Imagine trying to implement these ideas with an 8 bit microprocessor (think Z-80) running at a _”leisurely”_ 4 mHz.! And yet … all of the *COMPLEX MATH* was possible, just nothing fast enough to run it! Perhaps we ought to think ahead and create (theoretical) concepts, even if they have to wait *DECADES* to be practical. You know, the old humorous chemical equations that had a block labeled *_”An then a miracle occurs…”_* 😀
@prabhakarrao6197
@prabhakarrao6197 6 жыл бұрын
It's crisp and clear explanation of SDR and any lay man can also understand the modules required for SDR.
@richardphillips2405
@richardphillips2405 4 жыл бұрын
Hello. This video has been one of the best videos on IQ modulation and demodulation. Thank you.
@skidmoremusictech528
@skidmoremusictech528 4 жыл бұрын
Outstanding presentation! Presents a complex topic very clearly and in an easy to understand manner! Thank you!
@gauravpride1985
@gauravpride1985 7 жыл бұрын
The ultimate presentation I have ever seen on SDR. Thanks for your such a nice presentation.
@panduwilantara3070
@panduwilantara3070 4 ай бұрын
very amazing explanation, now i understand about SDR include I/Q Signal
@chihokang8839
@chihokang8839 3 жыл бұрын
Thanks a lot. This is the best explanations on SDR that I've ever seen. This is the real deal.
@maxsocial
@maxsocial 6 жыл бұрын
Thank you for this clear presentation. It was very helpful!
@elalsagala8460
@elalsagala8460 6 жыл бұрын
Thx for the explanation. It REALLY helps me a lot
@robertocosentino7616
@robertocosentino7616 5 жыл бұрын
great explanation! clear and persuasive. Many thanks for sharing and making understanding simpler ;)
@AbhishekKumar-xu9vk
@AbhishekKumar-xu9vk 5 жыл бұрын
Thank you for a clear explanation.
@georgeclooney8541
@georgeclooney8541 4 жыл бұрын
Good explanation to the basics. i would like to add that you also need another band pass filter at the RF stage to counteract the signals at image frequencies
@guygadbois8989
@guygadbois8989 4 жыл бұрын
This was extremely helpful. Thank you.
@TheSemtexCow
@TheSemtexCow 3 жыл бұрын
Thanks for such a simple to understand video, its helped me understand a new subject.
@phillipneal8194
@phillipneal8194 2 жыл бұрын
This is wonderful. I just found it on youtube. Thank you very much.
@baghdadiabdellatif1581
@baghdadiabdellatif1581 Ай бұрын
Thank you
@hassantj5775
@hassantj5775 3 жыл бұрын
Very impressive. & easy to digest. Really a wonderful job.
@tttuberc
@tttuberc Жыл бұрын
This video is really helpful for me. Thank you very much
@Anamika8
@Anamika8 3 жыл бұрын
Thanks a lot for the useful lecture!
@MH-ij9lx
@MH-ij9lx 3 жыл бұрын
Wow. Fantastic. Thanks!
@ilanyacobi2918
@ilanyacobi2918 3 жыл бұрын
Excellent explanation thank you so much
@hariwi39
@hariwi39 2 жыл бұрын
Clear explanation of presentation, thanks
@tempusFugit1337
@tempusFugit1337 3 жыл бұрын
Very good explanations.
@kozlovskyi
@kozlovskyi 4 ай бұрын
omg. Finally I got my answers
@lamarts1000
@lamarts1000 5 жыл бұрын
Excellent presentation!! Thank you!
@andreaquadri7890
@andreaquadri7890 4 жыл бұрын
Well done!
@robc3863
@robc3863 2 жыл бұрын
Looking for a detailed overview of the Tyloe quadrature demodulator that shows how the recombination of the 4 samples, 0/270, 90/180, results in the I and Q signals.
@russelm5107
@russelm5107 3 жыл бұрын
Perfect and Simple and Humble and to this and to tan and con and the back! Perfect Okay!
@ianventer4017
@ianventer4017 3 жыл бұрын
Hi, everyone just a question regarding the SDR transmission, where will modulation occur? I presume in the DSP stage but at what frequency? Why cant it be directly modulated onto the IF frequency avoiding the need for the digital upconverter? Any response appreciated
@Frankey2310
@Frankey2310 10 ай бұрын
Yeah, sorry if it's there and I've just missed it, but but how seems like you left out something major, i.e. HOW does this "digital complex mixer" get I and Q from just the sampled amplitude values? From what I could gather from the source code of uSDX (seemingly the only source on the subject), what it does is sample at 2 * Fs, treating even samples as I, odd as Q, but linearly interpolates the Is, replacing each one with the average of it and the next one. What this clearly does do is shift one of the streams in time by one sample period, so that the synthetic Is coincide with Qs. While the thing does work in the end, - the device does seem to receive SSB, which is the only use for the I/Q data there, as far as I can tell, - I can't possibly see a) how can those I values be correct beyond the simple assumption that both domains are (-1; 1), and, more importantly, b) any basis for the downright strange assumption that a shift by one sample in the array is equivalent to a 90 degree phase shift. This technique, which quacks like a dirty hack for the anemic 8-bit MCU it's written for, is called a "Hilbert transform" in the comments. Whatever. Correct or not, the whole transition from amplitude samples to I, Q pairs doesn't seem like an "implementation detail" you can just omit here, especially when the end result of the formulation is supposed to be a general SDR, and not some special case transceiver.
@superbcutter16
@superbcutter16 2 жыл бұрын
is there anyone who can help me how to design a GNSS/GPS receiver using Simulink or GNU Radio
@terjeoseberg990
@terjeoseberg990 6 ай бұрын
At 7:40 I believe that’s only true when you don’t care about the negative frequencies.
@bennguyen1313
@bennguyen1313 5 жыл бұрын
So the reason you multiply/mix the input by an analog RF tuner, is only to bring the signal to the area of the band-pass hardware filter? Would Direct-Sampling remove this Intermediate-Frequency requirement, and if so, why isn't it the preferred approach? However, it still feels like a free lunch that you can sample and get a *single* ADC value, but then digitally mix (DDC) to get 2 baseband samples (the cosine (Q) and sine data (I))! After-all, couldn't more operations be done on the same sample to get even more bandwidth?
@SerBallister
@SerBallister 4 жыл бұрын
Because of the low sampling rate that original waveform is being sampled with large gaps, so the phase shift allows you to sample that missing part.
@Mr_ASIC
@Mr_ASIC 4 жыл бұрын
you can but you need expansive ADC , the circuit would be antenna -->LNA->BPF->ADC
@phillipneal8194
@phillipneal8194 10 ай бұрын
Excellent presentation. But the devil is in the details. Where do I get an ADC and a DAC breakout board at a cheap enough price( < $20) that will handle 200 MSPS ?
@thomaskosvic6103
@thomaskosvic6103 2 жыл бұрын
The term bandwidth is used profusely in this presentation but is not defined mathematically or graphically in this presentation as far as I can see.
@zynthos9
@zynthos9 5 жыл бұрын
At 4:45 you say sin of f2 is real and cosin of f2 is imaginary, but in the previous slide this was reversed; sin was imaginary and cosin was real. Can you explain this discrepancy?
@m1geo
@m1geo 4 жыл бұрын
It's wrong. cos is real (i), sin is imag (q). The slide is incorrect.
@AM-tu1rc
@AM-tu1rc 3 жыл бұрын
@@m1geo Thanks, I was totally confused until I read your comment
@deqortestowy
@deqortestowy 3 жыл бұрын
Very nice presentation but... 5:12: there is a mistake in the first formula. You say: cos(f1)sin(f2) = 1/2*{sin(f1-f2) + sin(f1+f2)} which is wrong. It should be: cos(f1)sin(f2) = 1/2{sin(f2-f1) + sin(f1+f2)}. Second one is OK. Both formula should be presented in this way: cos(f1)sin(f2) = 1/2{sin(f2-f1) + sin(f2-f1)} cos(f1)cos(f2)=1/2{cos(f2-f1) + cos(f2+f1)}
@elnoggernog
@elnoggernog 4 ай бұрын
Actually this is not really wrong since a negative frequency in the cos is the same as a cos with the positive frequency. Negative frequencies get "mirrored" up in the spektrum. Its only better to undertand in this case.
@zsbali
@zsbali 3 жыл бұрын
5:35 I don’t understand what you mean on simplify it by removing the high frequency component. Why don’t you simplify it by multiplying by 0? That would be more simple.
@elijahdrug2931
@elijahdrug2931 6 жыл бұрын
Thank you
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