Permutations Combinations 3 | CAT Exam Preparation 2024 | Quantitative Aptitude

[@sumidhasrivastava1845]

anyone studying for 2024 cat

[@saurabhjaiswal5413]

Yes bro +1

[@ashtron1585]

yes

[@parthshah4536]

Yup

[@satishganthagoru990]

Bro anyone have rodha sir notes of all concepts please share

[@simplethings7000]

yes bro

[@nishantadas5937]

Sir your free contents are way better than so many Paid contents. Thank you

[@Aadhiran24]

Dai summa iru da…

[@Pookie_jaat0408]

Anyone studying for CAT 25

[@gayathri6951]

Sir, you teach from the bottom of your heart with lots of patience so that any person irrespective of his/her IQ levels can understand the concepts. Thanks for being a great teacher ! 🙏

[@sriramkrishnamurthy4473]

iq ki hi zaroorat hai mujhe abhi

[@shalinishukla3810]

your each video make me feel confident about QA .heartly thanks for your hard work.thanks alot for making it available at zero cost,i really needed.thanks sir

[@sarvottamsingh1859]

sir i love the way you are teaching

[@ramanasurada1171]

In question number10, the digit 6 will appear more than 100 times in between 600 to 699...check the 3rd method

[@bobghosh8313]

Bro 666 will be taken as 1 , then 662 will be taken as 1 , u did not understand the question

[@Anurag_Sharma_Captures]

@@bobghosh8313 but during 1 to 100 he , the 60 to 66 part he counted 66 as a + 1. According to that the digit 6 should more than 100 times between 600 to 699.

[@divybansal2886]

@@Anurag_Sharma_Captures he wrote the Q wrong, the Q should have been how many digits contains 6 not how many time

[@vinitashukla9346]

Why are we dividing it by 2! In the last question ..if anybody could please explain

[@mahakparate7065]

hey pls explain this question im confused​@@bobghosh8313

[@avinash85940]

sir in q11 can we do this by subtracting from total - 3 digits having 8 atleast once

[@deepaksharma23456]

And sir here from 601-700 there are only 99 number But from 501-600 there are -30 number instead of 19

[@Cholghuri96]

I am preparing for upsc where csat is consider as a barrier but when i found your videos my preparation in that portion became easier and understandable.thank you.

[@rahulpratap4613]

Apka CSAT qualify hua 23 ?

[@Vicky__0701]

Sir 10 th question is How many numbers instead of how many times and answer also according to how many numbers

[@bhuwan6796]

Same

[@GauravDedhaa]

CSAT ke kuch questions ho jynge kya is playlist se?

[@abeginnerspov5968]

26:22 What I understood is: Eliminate the bigger n-r count for numerator and choose the smaller r-value for denominator

[@nipuntaunk2842]

Sir i have completed more than half of this playlist,Is this 280 videos playlist enough to cover all the cat syllabus,please reply sir!!!🙏🏻🙏🏻🙏🏻

[@Rodha]

keep on doing. I am adding

[@sumitbhagat3779]

Did you make it in iim 😊

[@harshrawat2404]

yes IIMA @@sumitbhagat3779

[@INSIGHT_D]

By his aura I assume he didn't​@@sumitbhagat3779

[@TonyStark-dl9hp]

From 600-699 ,we would get 110 6's + 19(normal case six) = 129. Then add in remaining that is 171+129 = 300 Its not related to 10 th question its should be actually 6 th question.

[@sakshihiwarkar3179]

Sir for 66 you counted two sixes making it 20 times. but in 600 to 699 you didnt consider situations likes 606, 666, 660 etc..why?

[@Ankur33Goyal]

atleast once vale hi count krne h bro

[@mahakparate7065]

​@@Ankur33Goyalbut in 66 he counted it 2 times!?

[@namanbatra8639]

Great teaching sir! I have studied from 3 different paid instituitions but no one can match his level of depthness in the concepts. Free treasure.

[@cumulusmusic100]

Thank you Sir 🙏, The way you explain numbers, it becomes really easy to understand.

[@deepaksharma23456]

Sir here you changed the question from many many numbers have digit 6 to how many digits 6 will appear? The both make different sense as in first me mention only how many number have 6 atleast onece and in second we have to count number of 6 that appeared it will be more than the number that have 6 in them

[@Swatisinghh]

Thankyou so much for your content, its so much better and clear

[@kayr5064]

Just 2 words, Great Teacher😎

[@amitbasu9201]

#sndeymath1 sir in question 10 .is it how many times or how many numbers 6 will appear.i think it should be in how many numbers.thanks in advance.

[@sanketsharma2951]

same doubt

[@tanyashankar9685]

exactly

[@prachi4419]

yes it is in how many nos. that question is in continuation from previous video.

[@amitbasu9201]

Prachi yes .thats the fact.

[@jatinmehra1565]

question ask for number of times 6 appear and method is for counting total numbers in which six appears

[@rajeeomar6674]

I have same doubt

[@prachi4419]

yes it is in how many nos. that question is in continuation from previous video.

[@PrayagGupta516]

600-699 ke beech m v toh 19 numbers aur aayenge na, unko kyu nhi count kiya h

[@prateekbirthal9649]

600-699 m 100 numbers aayge. Sabme 1 6 hai

[@boridofz]

From 600-699 isn't there will 119 times 6 (100 times 6 at hundredth place and 19 other)? 5:00

[@yashselukar1846]

that was for AT LEAST 1 ..so only 100 will be considered

[@Ankur33Goyal]

@@yashselukar1846 wow yeah nice point, ty ty

[@shivanijethliya263]

Why 11th question can't be done by subtracting no of no's in which 8 appears from all possible no.s?

[@bhaveshpawar2716]

It can be solved. (900-252) here 252 is achieved by adding (72+72+81+8+9+9+1) where 72,72,81 is achieved for no.s having 8 only once. 8,9,9 for no.s having 8 only twice and 1 for 888.

[@hahakumar7709]

Why u are taking 72 72 why not 81 81 81

[@dishanisaha4754]

sir, in question no 11 y in 3 digit no "0" is not possible in hundred place?

[@ArpitaB2007]

coz if u take 0 in hundredth place ,it becomes two digit number.

[@youtubesixmonths9357]

because we have to take from 1 to 1000, 000 is nothing but 0 so 0 is less than 1

[@abeginnerspov5968]

n C r

[@suryanshprakash3092]

Sir I can't thank you enough for giving such content to us

[@alokj2099]

sir aapko alphabets ki numbering bhi yaad h ....... how many more ways will you amaze us sirrr

[@charmimeswani2168]

You are the boss !

[@poojakhattar4241]

hats off sir

[@likhithareddyt2374]

In quedtion 3 attitude why t is take has one and before sufficient why we cant take F as 1

[@kshitijbalonie4361]

Thankyou sir

[@varunjaiswal2253]

Sir you have solved wrong the que nu 11 answer will be 728.

[@prateekbirthal9649]

Sir is right.

[@Abcnews18]

Sir apne konse school mein padhte the.?

[@sudhanshushekhar4710]

When does n(n-1) and n(n-1)÷2 formula is used.someone tell me

[@Conk-bepis]

This is summation formula which comes in Sequence and Series

[@Karan-wz7pt]

Thankyou Sir.

[@MamtaKumari_._]

Amazing session sir🥰

[@minuupadhyay99]

Just wow.

[@sulochanavookoti4482]

Sir,in qs 11can we get the and by subtracting the total no available - no which have digit 8

[@malayswarnkar2261]

Yes you can do that way too

[@aayushi7874]

If you mean 1000-271 then you can't do that. 271 if for 1 to 1000 but q11 asks for only 3 digit no.

[@praveenkumar-qo9nl]

We can solve like this too for question no.11 8 will appear 20 times from 100 to 200 so 8 wont appear 80 times from 100 to 200 so 80*8(that means from 100 to 900)=640+8(that is from 900 to 999)=648 exclude 1000 because it is a 3 digit question. therefore (80*8+8=648)

[@AdityaPandey-ns8kl]

Brilliant explanation sir!

[@tonymartial1211]

tysm sirrr

[@RamKumar-uq6sg]

How many 6between 600to699

[@ritikagaddellu1704]

699-600+1=100

[@amann_bhardwaj]

what about 666?@@ritikagaddellu1704

[@applepie4891]

CONGRATULATIONS FOR 1M SIR!!!

[@vins686]

legendary!

[@VivekKumar-cj2gm]

Confidence ke sath galat bol jate hai aap kabhi kabhi

[@shishir6340]

dont judge on 1% when you are gaining 99%

[@pranavkottappurath6806]