PHY x51 Deriving Polar Form of Ellipse from Std Form 20201003 165202 v01

[@pedrocapitao9268]

I wish you everlasting health

[@tanishtyagi1301]

u da real mvp

[@georgefoxphysics]

Thank you.

[@MrSzybciutki]

Thanks, just what I was looking for

[@georgefoxphysics]

You are certainly welcome. I'm glad it helped.

[@emirc5932]

Thank you very much, great explanation

[@georgefoxphysics]

EmirC, you are very welcome, and thank you for your comment.

[@Gaayathri_Ganesh]

Would it be possible to turn the polar form of an ellipse to the coordinate form?

[@georgefoxphysics]

Gaayathri, I believe it to be simpler than going from rectangular to polar. Recall that e = f/a, r = (x-f)cos(theta), r^2 = (x-f)^2 + y^2, f^2 = a^2 - b^2. Starting with polar form, substitute to get rid of cos(theta) first. Then substitute to get rid of r. Then substitute to get rid of f. Now it's just a matter of putting the equation in a familiar form. If this is not enough, I recorded a video of the process (kzbin.info/www/bejne/aXuUnnaaaceYpLM)

[@shirsenduroy19-7]

With @MrSzybciutki, Thank you , just what I am looking for

[@HeyKevinYT]

nice

[@georgefoxphysics]

Thank you