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Hi viewer Today I have covered complete physics mcqs with answers for the class 11th & 12th. these Mcqs are very important for All upcoming Exams.
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[@mushtaqali5981]

Nice mcq

[@studyRoom31]

🌻

[@johnsonworldwings7899]

Very good

[@studyRoom31]

Much love ❤️

[@FatimaBashir-r4s]

Least count of Vernier calliper is 0.1mm

[@studyRoom31]

🌻

[@wordsinpaperjournaljournal]

Q12 explanation??

[@studyRoom31]

The percentage error in a measurement quantifies how much the measured value deviates from the true value, expressed as a percentage of the true value. The formula to calculate the percentage error is: Percentage Error=(∣True Value−Measured Value∣True Value)×100\text{Percentage Error} = \left( \frac{|\text{True Value} - \text{Measured Value}|}{\text{True Value}} ight) \times 100Percentage Error=(True Value∣True Value−Measured Value∣)×100 Given: True Value = 2.60 m Measured Value = 2.58 m Let's plug these values into the formula: Percentage Error=(∣2.60−2.58∣2.60)×100\text{Percentage Error} = \left( \frac{|2.60 - 2.58|}{2.60} ight) \times 100Percentage Error=(2.60∣2.60−2.58∣)×100 First, find the absolute difference:

[@studyRoom31]

@@wordsinpaperjournaljournal 2.60−2.58∣=0.02|2.60 - 2.58| = 0.02∣2.60−2.58∣=0.02 Next, divide this difference by the true value: 0.022.60≈0.007692\frac{0.02}{2.60} \approx 0.0076922.600.02≈0.007692 Finally, multiply by 100 to get the percentage: 0.007692×100≈0.76920.007692 \times 100 \approx 0.76920.007692×100≈0.7692 So, the percentage error is approximately: Percentage Error≈0.77%\text{Percentage Error} \approx 0.77\%Percentage Error≈0.77%

[@Toor-Makhamy-15]

Sorry sir Question no 12 correct answer option A

[@studyRoom31]

Yeah, I understand