Pseudo Force & its applications | NLM for JEE & NEET | Class 11

[@physicsgalaxyworld]

Catch the perfect explanation of Pseudo force in 3min: kzbin.info/www/bejne/i3XNi2xpq86rmKs Watch Pseudo Force Application & Reference Frame for JEE & NEET: kzbin.info/www/bejne/poDYaYenndloitk For views, queries and suggestions about upcoming videos on our channel, viewers can reply to this comment. All replies to this comment will be answered soon !

[@PrinceGupta-kr6qz]

Sirrr please increase the frequency to 6 in a week plsss ssss pls sss sirrrrrrr

[@vinay3726]

Sir plzz increase the video frequency , 1 lecture everyday will be very helpful for 2021 aspirant or u can plzz cover the more topics in 1 video its a request sir 🙏🙏

[@madhavdhage1643]

28:09 there should be a Tcos(θ) rightwards↦ in calculation of a wrt wedge right???!

[@vishalpandey5326]

It's more interesting when you know the concepts..

[@soumodeepchatterjee3248]

Yes sir that's correct. And I think that's why sir tells to watch the concept videos already before watching the onion physics lecture although I just read the theory part from book and even that helped to improve my understanding.

[@bodiminds6571]

Agreed , used abj sirs lectures , solved a few problems in competishun sheet and now watching this gold

[@krishnajadhav9527]

Thanks sir ...your this free teaching like at home is going to a help a lot for those students who can't afford coaching like me!

[@RajKumar-rz5ww]

Tu toh bhikhari nikla

[@akashkumarsaha5191]

Haa bhai,ma bhi.❣️👍

[@carryminnnnati]

bro what doing now ??

[@undisputedrush8463]

He is not only an teacher 😃 but also a mentor 😃😃.

[@loser3357]

Huehue 😋😋😋🤩🥳😘

[@varunbaggan1912]

Every Time Same answer comes both with pseudo force & Eq. of Motion method 👍 Thnks Sir ❤️

[@gravitational6642]

Done last problem with ground frame ❤ Love you sir

[@sahilshrivastava5398]

24:40 yes sir, i have got the answer from traditional method too🙂🙂🙂

[@rishabhpalsingh2644]

Hello brother can you tell how to do it by traditional method B ki fbd smjh nhi aarhi

[@granth6665]

how

[@MaheshHemanth-s6t]

That method comment karoo

[@MaheshHemanth-s6t]

I also want that method broo

[@SchrodingerCat90]

S3: Let b be the acceleration of block and acceleration of system be a F=7ma For blocks: mb=T+ma 2mb=2mg-T Adding them: 3mb=2mg+ma Now they are rest realative to C, b=0 2g=a Hence F=14mg

[@TanushKarkade]

Yes sir got the answer by traditional method too Thank you sir

[@hayatkhan4700]

Sir please explain, in the last case, why in horizontal direction tere was no relative acc of block of mass m wrt mass 2m?

[@244maneerafsan2]

sir onion physics is amazing

[@Chonk707]

30:57 a = gCosØSinØ/(7-4CosØ)

[@advaitk624]

same answer with traditional method too sir :) 25:00

[@CarmotiveXD]

S3 2mg = ma as mg is balanced by N and a=2g so f=7ma which is 140m

[@iitbombay51]

24:53 I got the same answer with traditional method:)

[@YdvSyAero]

Amazing amazing and amazing

[@abhinavarya7752]

S3 ko traditional method se kaise solve karey?

[@sujaykarmakar7349]

23:07 sir why normal force don't pass through the centre of the block... pls explain sir

[@mdsohelraja285]

It's perpendicular to the centre of block. Sir has just drawn the arrow sign a little downward so as to keep the diagram neet and clean.

[@sujaykarmakar7349]

@@mdsohelraja285 okay

[@sujaykarmakar7349]

@@parthpariwandh okay thnx

[@RajnishKumar-jh9ql]

23:46 yes sir i am getting the answer in ground frame

[@adrito_pratham]

Why didnt sir equate N(A) = mg and N(B) = 2ma, in this case acceleration is g/2 instead of 2g

[@nikitasharma7209]

21:24 same quest come in jee mains 22

[@rashimamittal2281]

mujhe sir se zyada acha sir ka poogy laga

[@jaishreeram5808]

THANKS AND LOVE YOU SO MUCH SIR...MJA AAGYA ✍🏻✍🏻✍🏻✍🏻✍️

[@Mohit-eq3hz]

I have solved it by traditional method, I noticed the total force on A in right direction it is (T+ma) and the total acting on B in downward direction it is (2mg-T) these must be equal So, ma = 2mg Hence a = 2g and putting it in F = 7ma we got the answer 😊😊😊😊

[@RaghavBhandari-y8o]

Maine bhi kar liya :)

[@7_thala_for_a_reason]

yes I have got the same answer using traditional method pulley system question

[@sujaldebnath01]

Sir why you write 2mg in downward direction?

[@Abhishek-vu4yh]

sir also start for class 12

[@Physicslover1729]

30:58 Sir ground frame se bhi kia but 4 eqns and 4variable arahi hai and use solve krne me thodi dikaat hui!

[@shivannagk7537]

Eqns type karke bhejdo please 🥺

[@bijaykryadav7906]

How we will get acc of both block as we can't use a and 2a as acc of block as sir said it is with reference to each other

[@chiragbirla5606]

Best level

[@poojasonawane7181]

24:00 done by traditional method

[@ishangosavi-e8j]

error at 21.00 ans is 60/root3

[@CarmotiveXD]

Actually 60/root 3 is 20 root3 so there is no mistake

[@RohitRajChaudary]

Sir but in non inertial frame third law is valid 4:56

[@xc8684]

sir apne to bola tha pseudo force is the force on A wrt B. So agar block wedge pe h or usko wedge ke respect mai rest mai rhna h then. block ka net acceleration wedge ke respect mai 0 hoga to pseudo force to 0 aega.

[@karankumarsharma_4410]

Same doubt

[@TMT05]

being in rest means net force is 0. pseudo force is one force that acts on block when seen by viewer on wedge. other force that acts on block is gravity. components of gravity and pseudo force along incline cancel each other and thus net force and net acceleration on block=0. as seen by viewer. this is where condition comes that magnitude of acceleration of wedge must be certain value for pseudoforce to = gravity component

[@Anurag_30]

Same doubt Aaj clear ho gya 11th Mai hu Abhi 🤠

[@aakankshajain8988]

Thank you sir Please sir thoda adv 2021 le baare mai bhi btaye

[@yogijnuite]

H.w IL2 answer =15kg

[@i.anupamalok]

Yes ,I have got the same result, sir

[@rudranshsharma6913]

a=2gsin(theta) /7 2a=4gsin(theta) /7 N=mg/7[cos(theta) (7+2cos(theta)) -2] T=[ 3mgsin(theta) +mg sin2(theta) ]/7 The answers to the last question....

[@dbdoxbxb]

2gsintheta/3 hoga shayad

[@TMT05]

hi. can u revisit this problem please lol when i solve with pseudoforce i get a=2gsin(theta) /(7-4cos theta) but with conventional method I get a=2gsin(theta) /(7-2cos theta)

[@ShauryaAggarwal24]

@@TMT05 what process did you use for the convential method? beacuse i got the same answer as you using psuedoforce

[@krishnajadhav9527]

Thanks sir!

[@granth6665]

21:56 cant get ans by normal method

[@Akash-wb9mq]

28.18 how the TT got cancelled????

[@dbdoxbxb]

Opposite directions and acting on same body

[@julichaudhary8491]

Thanks sir 👍

[@Pixelpawn90]

This is what real study is not the physics wallah teachers doing entertainment in class😂

[@himanshuacharya215]

Thanks sir

[@PrinceKumar-le8nd]

Yes sir I got the same result 😁😁

[@AyushYadav-tc4xt]

24:40 sir done using traditional method !

[@subhamsouravbehera4091]

Hey bro tumne traditional method se kese solve Kiya can you please 🙏🏻🙏🏻 help me ??? I am unable to solve all problems in traditional method please bro !!!!

[@rohangupta3363]

sir who is pogg1? app kise thanks bolte hai bar bar? btw very poerful lecture

[@armanagrawal5548]

jo board clear kar rha hai

[@anayraj3315]

sir i m jain how can i consume ur content

[@subhamsah1601]

Sir non lnertial frame me Newton's third valid hota he

[@Alphamatics1234]

Non inertia frame ma Newtonian laws kam nahi karta

[@borntobehuge]

30:00 anyone got the same equation of block by traditional method ?

[@Zero22f0]

I got the equation for wedge but I’m unable to get the right one for the small mass m. What about you?

[@vaishnavisingh6654]

Got it by traditional method

[@vishnuksharma]

13:30 what if force is more than (M+m)gtan thetha?

[@insanefacts8190]

sir without pseudo ho gaya

[@Vidy884]

Ye pogi kon h yr bich me ud ke Jo aata h

[@LakshmiDeepakChalla]

Poji is a fictional character in Ashish sir class

[@abhinavarya7752]

No one has dare to solve S3 by traditional method. If anybody has dare then write.

[@prince.j.]

Very true😂

[@abhinavarya7752]

@technicaldreams2509 you too need to worry about your future bro. So you too kindly solve.

[@abhinavarya7752]

@technicaldreams2509 Mee too bro. Look when I commented!

[@Amishgoyal-m5y]

It is easy to solve with traditional method you just need to take T = 2mg from block B as there is no acceleration in vertical direction then fron block A ( T = 2MG ) ma = 2mg as there is no force acting on block A other then T so then if we solve both equations we get ( a= 2g ) and then put a and m of whole system in eq. F = MA And you have your answer buddy ..

[@solenoid6545]

Bsdk apne kaam se kaam rakh na. Sabko challenge kyu kar Raha h. Sab teri tarah nahi ki ho jaae to comment karke sabke saamne hero ban ne ki koshish kare.

[@dhruvgupta8146]

Kya koi batayega ki relative acceleration wale question mein kyun aisa koi pseudo ka concept nhi hai

[@StudyMan-g3z]

29:39 virtual work se answer nahi ha raha 👎

[@xyz...8475]

Yes bro I use work tension method to find a and I get different acceleration

[@yasharora6772]

Jee main 2022 que 21:28 thanks sir

[@hyp-en]

24:43 able to get the answer by traditional method ❤

[@JatinKathoria]

Yes yes i have got the answer s3

[@naitikkk0]

Pseudo force fayda: 4to8 marks in jee main and adv.😅😂

[@TheAditya-zt9pb]

Yes i am getting same result with traditional method

[@aryangupta904]

sir pls itna clear krdo ki If a block is kept on a moving wedge (with accelration a) then if we have to draw the Free body diagram of block i) with respect to ground will we consider pseudo force? ii) if ques asks to draw the free body diagram of block with respect to wedge(moving with acc a) will we consider pseudo force now? sir in dono ka ans dedo pls

[@pallavigupta4408]

1st case me no 2nd case me yes

[@avneeshyadav6814]

I got same result

[@sandeepshah101]

Sir poji kon... 🧐😐

[@manthansagar200]

Bhoot

[@ambujyadav5978]

sir ka sex slave

[@Freezeali]

Sir very punctual about ur time

[@ramtokas0001]

Sir ji kbhi has bhi liya kro 😂

[@loser3357]

😋😋😋😋🥰😍🤩🥳😘

[@yogijnuite]

H.w IL1 answer =20kg