Numerical Discussions on NLM | NLM for JEE & NEET | Class 11

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Physics Galaxy

Physics Galaxy

Күн бұрын

Пікірлер: 39
@physicsgalaxyworld
@physicsgalaxyworld 3 жыл бұрын
Link to all lectures of Onion Physics of Kinematics - kzbin.info/aero/PLYVDsiuOZP5p6aY8hipMiTqqVbmdYAi0e Link to Block over Block and other PIM videos - kzbin.info/aero/PLYVDsiuOZP5oU1jL951EntybRn2j083Su Link to Concept Video Playlist of Motion in One Dimension - kzbin.info/aero/PLYVDsiuOZP5qJbEmuJy30qstS8fDQYXFQ Link to Concept Video Playlist of Relative Motion - kzbin.info/aero/PLYVDsiuOZP5pxfMHOVx-ziJnTziCQ5PTR Link to Concept Video Playlist of Motion in Two Dimension - kzbin.info/aero/PLYVDsiuOZP5rVbTWIWmdw7ZLgrpL5HUI2 Link to Concept Video Playlist of Newton's Laws of Motion - kzbin.info/aero/PLYVDsiuOZP5o87acfiquV9CMzi-rfIdQk Link to Concept Video Playlist of Friction - kzbin.info/www/bejne/pqvMm4eLoqaYaMU Link to buy Physics Galaxy Vol. 1 Book - amzn.to/3eVGUJd To see the content of all PG books, click - edyapp.com/physics-galaxy-books
@ayoungmuslim8223
@ayoungmuslim8223 2 жыл бұрын
Sir please give onion physics lectures for wok energy and power also
@Madhav-s2y
@Madhav-s2y Жыл бұрын
Sir Salute for your last question speed I Wish to command a question like you Thank You sir for your contribution in my jee preparatiin
@RajeshSingh-dz3fj
@RajeshSingh-dz3fj 3 жыл бұрын
To be honest sir, since the day I started following your channel i have leaved all the other teachers and just got stucked with the concept explained by you in all your physics series, mainly revision checklist by you and they're working as a charm for me..! Legend of physics with an extraordinary beautiful hand writting and diagrams ❤️❤️
@physicsgalaxyworld
@physicsgalaxyworld 3 жыл бұрын
Thanks a ton @Rajesh and wish you all the best
@aksaxena1000
@aksaxena1000 2 жыл бұрын
Respected Sir, I would like to deeply thank you for all your efforts. You have been a great help to all of us :)
@ketansharmag1
@ketansharmag1 Жыл бұрын
19:00 Here accn. would be gsin(theta) bcz we have to find component of g along the wedge which is only responsible for accn. of M.
@vaibhavgulati018
@vaibhavgulati018 Жыл бұрын
Ans to ques at 9:03 is √2 mg/M+m(2-u)....... At 10:11 ans will be √2 mg/ M+m(2+u+u’)
@vsfreefire4139
@vsfreefire4139 4 ай бұрын
sir your voice is so satisfying>>>{
@aartikushwaha6328
@aartikushwaha6328 3 жыл бұрын
At 17:40 why friction written as u.ma instead of u.N
@programingwithsohan8064
@programingwithsohan8064 3 жыл бұрын
coz N=ma as the only horizontal acting on the block is N and it is having a horizontal acceleration of a.
@nobarakugisaki_._
@nobarakugisaki_._ 2 жыл бұрын
Anya san!🤧 You're dumb in reality too... Just kidding! ..it's already been 1 yr by now.
@aartikushwaha6328
@aartikushwaha6328 2 жыл бұрын
@@nobarakugisaki_._ waku waku
@yogeshraj9974
@yogeshraj9974 21 күн бұрын
sorry Sir But at 4:39 block m connected with string will have tension of T...but as from diagram wedge conneced with string will have 2T tension. where iam wrong sir
@MishraAvdesh
@MishraAvdesh 3 жыл бұрын
Plz sir provide answer also of last given home work questions
@programingwithsohan8064
@programingwithsohan8064 3 жыл бұрын
Sir the day in which I first found your channel have proved to be a boon in my life,from that day I have been following each and every videos of onion physics and concept videos as you have said.So sir I am really grateful to you and entire PG team. It will be very kind of you if you please guide me in how to follow and when to follow the PG advanced illustration book.Right now I am in class 11.I am aiming for JEE Advanced and Physics olympiads. I am thanking you again for your support in my life....may God bless you and give you eternal peace and happiness. Sir,i would be eagerly waiting for your reply.
@singva7506
@singva7506 Жыл бұрын
Read 20 illustration.... And after some time (1 hr) attempt all those illustration without seeing solution
@MayankSharma-lo3bw
@MayankSharma-lo3bw 3 жыл бұрын
Sir please start onion physics lecture of class 12 for jee 2022 bcz we don't have enough time. 🙏
@bhu-pesh6620
@bhu-pesh6620 3 жыл бұрын
Help !!! For last question x = y cot(theta) Then double diff. a = g cot ( theta) How does g come?
@tilakmusic7735
@tilakmusic7735 11 ай бұрын
like upon differentiating, accn of M = accn of m * cot theta. so accn of m is g downwards
@ae86edits
@ae86edits Ай бұрын
Sir why do you always take directly the limiting case of friction
@mrfayeezium6313
@mrfayeezium6313 7 ай бұрын
Thank you pogi😂
@Anshu_18.
@Anshu_18. 2 жыл бұрын
sir ' s pogi is too smart
@celebrationpariwaar4733
@celebrationpariwaar4733 2 жыл бұрын
specially at 9:10
@ritiknarang7050
@ritiknarang7050 3 жыл бұрын
Sir, yours pim videos are best😀😀☺😊🙂
@dbdoxbxb
@dbdoxbxb Жыл бұрын
Acceleration of m:-√2mg/M+2m+(mu)m
@vaishnavisingh6654
@vaishnavisingh6654 Жыл бұрын
18:17 sir according to the relation a >=g/friction coefficient as a increases friction coefficient will decrease and mg is constant so if we will increase acceleration will the block fall?
@harshalkolekar4384
@harshalkolekar4384 2 жыл бұрын
Sir a=g tan theta chayein na
@Surya-vl7gx
@Surya-vl7gx 3 жыл бұрын
Sir if possible can you pls take up pyqs of jee advanced
@anantgyansinghal3140
@anantgyansinghal3140 2 жыл бұрын
25:56 shouldn't be a=M'g/M' +M+m
@apratimtewari4288
@apratimtewari4288 Жыл бұрын
yhh i thought so too
@boncoderz1430
@boncoderz1430 Жыл бұрын
Nope cuz now m ka mass is moving separately from the system, q mai diya Hai na ki free fall mai hai
@anjalipatel7053
@anjalipatel7053 3 жыл бұрын
sir ne 20:53 pe acceleration ko sirf gsin(theta) hi kyu liya M kyu nahi multiply kia hai ? pls explain
@vaishnavisingh6654
@vaishnavisingh6654 Жыл бұрын
Kyuki M multiply krne pr vo force kehlayega F=Mgsin(theta)
@dbdoxbxb
@dbdoxbxb Жыл бұрын
Mgsin(theta) force hota hai acceleration nahi M×gsin(theta) where gsin(theta) is acceleration.
@vaishnavisingh6654
@vaishnavisingh6654 Жыл бұрын
Sir block se jo string attached hai uspe ko T lg rha hai vo bhi to cancel ho jyega to wedge pe mg+T kyo ?
@samarthsamrat8378
@samarthsamrat8378 Жыл бұрын
T cancel ni ho raha h
@offline8200
@offline8200 3 жыл бұрын
😀😀😀
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