Isomerism 10 || Optical Isomers 02 || Plane of Symmetry and Centre of Symmetry JEE MAINS /NEET ||

[@PhysicsWallah]

Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZbin) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 chapter 12 | ISOMERiSM 01 | Introduction : Chain and Position Isomerism IIT JEE MAINS/NEET kzbin.info/www/bejne/o6KUfWWmoamHqLc Isomerism 02 || Structural Isomers : How to Find Total Structural Isomers D.B.E. IIT JEE MAINS/NEET kzbin.info/www/bejne/lYPWp4R5a556p6c Isomerism 03 || Functional Isomerism , Metamerism , Ring Chain Isomerism IIT JEE MAINS / NEET || kzbin.info/www/bejne/b5jXmmiqi7B0rbs Isomerism 04 || Tautomerism 01 : |Condition to Show Tautomerism and Special Cases JEE MAINS / NEET kzbin.info/www/bejne/g5WlqYWLqp1kjZY Isomerism 05 || Tautomerism 02 || Percentage of Enol Content N Stability of Enol JEE MAINS / NEET || kzbin.info/www/bejne/nGqah6ufjcudopo Isomerism 06 | Stereoisomerism : Geometrical Isomers 01| Cis-Trans / E -Z / Syn-Anti JEE MAINS/NEET kzbin.info/www/bejne/eWimfpd-Z9xjrac Isomerism 07 || Geometrical Isomers 02 : Cycloalkanes , Allenes , Spiro , Biphenyl JEE MAINS / NEET kzbin.info/www/bejne/gWrJlo13Yt1joJY Isomerism 08 || Geometrical Isomers 03 || Number of Geometrical Isomers JEE MAINS/ NEET kzbin.info/www/bejne/i5zco5Wmqp5so80 Isomerism 09 || Opical Isomers 01 || Introduction : Chiral Centre and Enantiomers JEE MAINS / NEET kzbin.info/www/bejne/kJqzq5p9i693rLs Isomerism 10 || Optical Isomers 02 || Plane of Symmetry and Centre of Symmetry JEE MAINS /NEET || kzbin.info/www/bejne/aH3ElZJ8hpx-aNk Isomerism 11 || Optical Isomers 03 || Enantiomers , Diastereomers, Meso , Total Isomers JEE/NEET kzbin.info/www/bejne/oZewhaKFjc2jkM0 Isomerism 12 || Optical Isomers 04 : Wedge Dash and Fischer Projections with R-S Configurations kzbin.info/www/bejne/g5vKn5Vnebpmgqc Iomerism 13 | Optical Isomers 05 | Optical Isomerism in ALLENE , SPIRO and BIPHENYL JEE MAINS/ NEET kzbin.info/www/bejne/lZmuY2CNoLd0hZI

[@anujyouthoob]

Sir "Z" bhi Chiral hai Uska plane of symmetry nahi hai. You cannot superimpose it on its mirror image

[@skkurve1977]

Only 1st is OActive

[@m.a.muhaiminl.6494]

How can we clear doubts?

[@pranjalpagaria322]

In Which city u are

[@pranjalpagaria322]

@@anujyouthoob turn it 180 degree then u can superimpose it

[@sangitalala9133]

Only 1 will show optical activity, others are optically inactive as 2 has no chiral centre. 3 has plane of symmetry. 4 has centre of symmetry.

[@shahiddar2449]

Same

[@naveenbagra]

@@shahiddar2449 same

[@praharshupadhyay4087]

My answer is also the same

[@mohammadyasir1048]

Same

[@PrashantKumar-ji6nf]

My answer is also same

[@learningstudent5466]

47:05 if anyone had a doubt that COS lies at centre of two carbons then actually it is a double tetrahedral structure both the carbon have 4 bonds thus form two tetrahedral structure in 3D so when you measure the distance due to 3D structure and repulsion between groups of the two carbons the distance don't come out to be opposite and same at the same time. so no COS

[@satya_3]

Thanks bhai boht bada doubt tha

[@namangupta7210]

Thank you so much...

[@shivprasaddange5094]

Thanks

[@abhinavgaurav1795]

Then how can we judge centre of symmetry for other compounds , like the last question 4th option.

[@divyanshisingh9020]

thanks thanks thanks ....and thanks

[@tusharsaini8311]

Unacademy , vedantu==promote their paid course in starting 10 mins.. Alakh sir== Revise the previous lecture in starting 10 mins....👍👍❤️❤️

[@vishal2025]

This is the difference broh...😊😌😌😌😌💖💖💖💖💖❤...

[@tusharsaini8311]

@@vishal2025 yeah..........alakh sir rocks

[@raosahebrathod5954]

You are exactly right my dear bro and l really feel irritating .

[@tusharsaini8311]

@@raosahebrathod5954 ya me too ...........

[@renitsu1]

Itti dikkat hoti h to skip krliya kro 🤡

[@Sami_Abbas]

58:00 (1) Optically Active Reason: It has one Chiral centre ( 1- Chiral Centre -Confirmed=OA) (Chiral centre;- Sp3 hybridised C, All 4 Valency has different groups) (2)Optically Inactive Reason;- It hasn’t chiral centre ( Bcz of 2 same Br group) (3) Optically Inactive Reason;- It has Plane of Symmetry (pos) (4) Optically Inactive Reason;- It has Centre of Symmetry (cos) ❤️❤️🤙🏻Luv u sir😘😘

[@deepalimangulle7805]

Thanks a lot 🙏

[@chandrag3594]

4 is optically active kyuki isme ch3 wedge or dash ke form m h

[@kininagothu2526]

@@chandrag3594 41:46, sir explains the same.

[@SIqbal21]

@@chandrag3594 that's the reason it's inactive. Due to dash and wedge form the distance of both methyl group from center is same. Thus it has a Center of Symmetry. N hence optically inactive.

[@Sahilyadav-wu5is]

Right bro

[@zaidmansoori7887]

Doctor patient se apna fayda chahta hai. Neta log public se fayda chahte hain. Lekin alakh sir apne student ka future Acha chahte hai. Thank you so much sir 😊😊

[@mizanur1232]

Nice line

[@aka5617]

Aap pta nahi konse doctor ke pass chle gye (PVT) Jisne aap ka faida uthha liya

[@ayanmallick3385]

@@aka5617 mzk mt bana bhai Tu v wahi khet ka muli hai 😂😂😂

[@zaidmansoori7887]

@@aka5617 hahhahha bhai

[@sahilrana4092]

Don't disrespect doctors, its exception that some doctors don't know their jod and their objective

[@pooja2023]

Sir I have watched approximately all of videos and I have been ur subscriber since day one.i never got a reply from you nor do I expect because u have so many things to do instead of making videos. I wish that I could meet you and touch ur feet and thank u for all things that u have done for us. Luv u sir and keep going....

[@yashusharma4107]

Same here

[@Basicbiology.]

Neet 2019 Mark's?

[@falgunirout6404]

Apna reply ayega

[@Aaditmorking]

Guru sishya ka pyaar.💅💅💅👌👌👌👏👏💖💗💝💞💕💖💗💝💞💕💖💖

[@rupendrasingh8996]

@@Aaditmorking sooo deep 🙇🏻‍♀️🙇🏻‍♂️

[@harihardhik3293]

Revision of previous video 2:05 Class Starts 11:20 Centre of Symmetry 36:50

[@Aloopetis]

dhanyawadd bhai

[@sagniksinhamahapatra4694]

P - Persistent H - Humble Y - Youthful S - Supportive I - Intelligent/ Inspiring C - Captivating S - Sincere W - Wise A - Admirable L - Loving L - Lovable A - Amicable H - Honest 🏆This is our "Physics Wallah".... greatest among the greatest 🏆

[@poetrywithshreyasharma2604]

Great

[@ajaykumartiwari5646]

Superb....

[@BoardWallah07]

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[@ChandanGupta-lr9zm]

Please let me tell you that how can I live happy

[@ahuman4]

Kitna khali h re tu

[@syedsajid3994]

Sir I am from Pakistan, well done. I am also a teacher, but I never found a teacher like you.

[@faisala6117]

tum nachne gaane kam karo tumhare desh me ,gaane nach chutiyagiri bhot hori .yahan hum india waale tarakki karre education me .tum nachne gaane me reh gaye

[@pranavbhat7262]

@@faisala6117 Bro why you wanna be toxic for no reason? He just spoke his thought and was not offensive in any way. Jai Hind!

[@NishchayG]

@@pranavbhat7262 ye true that kid’s salty

[@saurabhbala877]

@@faisala6117 be calm bro after all we’re Indians and a real Indian always support the good cause 😀

[@durganshyadav5009]

@@faisala6117 are tareef hi to kar rhe hain vo , respect karo thodi yaar.

[@akcreation481]

At 47:00 compound me sir centre of symmetry h n.......Distance equal h? Please reply sir

[@bhaiinnaa6535]

Same doubt

[@patelbandhan867]

@@bhaiinnaa6535 same dought

[@AryanKumar-pz7ds]

Same doubt

[@abhaydixit82]

same doubt !!

[@deepjyotichakraborty8684]

Same doubt yaar... Sir kindly clear this doubt..... Plzzzzzzzz Sir

[@vineettiwari5473]

During pandemic u helped us a lot for free........god bless you sir🙌❤️

[@manojrai7267]

Yo ❤

[@harmansandhu3129]

47:09 pr hai to Shi centre of symmetry agar centre se opp direction me jaaye to same group mil rhe hai

[@chandrimaartgallery8489]

Same doubt

[@jee9988]

Same yar.

[@araishkhan9819]

Same doubt

[@exticntspecter7836]

I think that there will be no cos becoz take the first carbon as center and other carbon and what is attached to it another R....now if you'll see it is sp3 hybridised so the R gr will be in different plane say outward and hence can't be opposite

[@shinchan1._.]

@@exticntspecter7836 my thought is also same...

[@sharmaanushka2473]

Only 1 is Optically Active 2 has two bromo group 3 has P.O.S 4 has C.O.S

[@karankumarsharoff5637]

Hii same answer

[@physicslover2802]

Absolutely right

[@karankumarsharoff5637]

@@physicslover2802 thay

[@karankumarsharoff5637]

@@physicslover2802 thanks

[@sauravchaudhary9044]

3 pos kaise

[@sujatamishra2783]

That line "Hello Bachoo" is just 🔥🔥🔥

[@purna...........9156]

Correct

[@saksheegautam9029]

That's true

[@sumithmourya3206]

Irritation

[@anuskaaditi2511]

Odisha🤞

[@madhumitanayak6407]

@@anuskaaditi2511 I'm also from Odisha 😊😊

[@HangingQueen]

In future,like in 2050 Students will learn P.W as one of the universal abbreviation i.e Physics wallah

[@Vlog-x8k]

Kuch bhi

[@Lily_little_girl]

Physics wallah is emotion ❤

[@Raman_Respect]

How you know 😮

[@rot1869]

This is for those who complain about ADs. You get such a quality education for free, all you pay is for internet. ADs help sir economically and in turn helps to make video therefore if you want videos don't complain about ADs EDIT: Sorry for bad English

[@dynanananaay8774]

English is perfectly fine

[@Acetrainerred_02]

1- optically active 2- optically inactive 3- optically inactive 4- optically inactive

[@neetuskitchen7470]

Why 2nd one will be optical inactive?

[@rahulsinghrollno50ee64]

Because two Br is attached and angle between all four group is 109 degree 28 min toh Cl ki jagah Br laga do koi farak nhi padega aab sir ne Aapne video me pos dikhahi hai aise comp ki. OR Board ke andar diagonally Jata hua ek plane banao Jo dono Br ke beech me ho

[@jaismineagarwal2767]

I think 1 st will also be optically inactive because of (D) this is duterium as similar to (H).

[@evolvingbud]

@@jaismineagarwal2767 No, sir has told us about this ,that isotopes of hydrogen has to be considered different !

[@jaismineagarwal2767]

@@evolvingbud ohk thank

[@Death_Dealer07]

58:13 1:Optically Active (Chiral centre) 2: Inactive (same br group) 3: Inactive (pos√) 4: Inactive (Cos√)

[@Karnnidhi...24]

1:- 4 valency with different groups. ( Optically Active) 2:- 2 same group attached with 1 carbon ( optically inactive) 3:- plane of symmetry ( Optically inactive) 4:- centre of symmetry ( optically inactive)

[@lataminhas7087]

Play coc ?

[@pritamdatta.6240]

​@@lataminhas7087yes I am

[@ty-1063]

Sir I'm in Class 12 studying in Allen, the teachers are teaching Organic Chemistry now and Optical Isomerism and I couldn't understand even a bit... But sir aapke padhaane ke baad ek bhi doubt nahi aata. 🙌🏻

[@sayeezanzane8500]

Allen meih hokar bhi abhi start hua heih!!!

[@SahilKhan-ll3lc]

Allen m gaye hi kyo

[@bablusinghchauhan8781]

@@SahilKhan-ll3lc 😂😂😂

[@SahilKhan-ll3lc]

@@bablusinghchauhan8781 😜😜😜

[@Pratyush_Srivastava24]

Pachtawa Nahi hota

[@saimanideepv4876]

Answers 58:01 1) It is optically active bcz there is 1 chiral carbon 2) It is optically inactive bcz POS is present 3) It is optically inactive bcz 2 same groups are present (Br) 4) It is optically inactive bcz of COS and POS (COS u know and POS is when we bisect the molecule through 2 methanes

[@pritamdatta.6240]

58:00 Ans is Opt.- 1

[@tejassingh6451]

Yeah👍

[@hitoshichourey8277]

Yes

[@mahanshaditya5162]

At 49:27 the second one could have COS from the centre of bond to CH3 group , I think

[@RAHULKUMAR-sn9yj]

Write bro

[@RAHULKUMAR-sn9yj]

Right bro

[@siddharthrana233]

Sahi kaha

[@kosiyash]

I too thought

[@kosiyash]

If u get answer from somewhere please reply

[@carguy7480]

Timestamps: 2:00 revision 14:20 disymmetry 36:35 COS

[@mohan4679]

Good review friend

[@praveenyadav7747]

Lakhya 1.0 ❤

[@mimascookingworld]

Ha bhai❤

[@Mrudula123]

Sir.. I am currently preparing for neet 2024 and without you I don’t know how I would have coped with the syllabus and the pressure. You made it a piece of cake for me sir… all the concepts are crystal clear after watching one video of yours, thanks a lot sir.. ❤hope to meet you soon…

[@blinkxarmy6495]

preparing for mains 2024🤗

[@Mrudula123]

@@blinkxarmy6495 all the best😄:)) hope you’re preparing well:)))

[@AyushKumarSingh-12]

Thank you , Sir jii. Answers to question , जो आपने दिए हैं। 1) is optically active by chiral center and no plane of symmetry. 2) is "NOT optically active" as it has POS along H and Cl 3) is also not o.a. due to p.o.s. 4) is also not o.a. due to c.o.s.

[@joydipdas3203]

47:00 wale me jisko bhi doubt hai sir ne 49:00 me explain kiya...is you find this helpful hit like......

[@harshdoshi5923]

Seriously thanks broo! I had the same doubt

[@sakshibhagat2337]

Thank u

[@shriganeshayenamah3422]

Thanks

[@mranjaan5193]

Sari duniya ki dua qapke ooper press like if u like PW

[@saifyusuf1361]

1&4

[@shakuntaladevi8881]

Aise hi karke tumlog like batorte ho.shame shame.

[@shakuntaladevi8881]

@@pankajbisht8630 to whom you replied

[@BoardWallah07]

kzbin.info/www/bejne/m6bFf2SvjK-airs

[@dhairyasharma7782]

58:02 Answer - (1) is optically active because it has a Chiral centre (2) has no Chiral centre (3) has POS (4) has COS So 2,3,4 are optically inactive

[@haxer4283]

47:18 is compound me centre of symmetry (com) hai, but sir ne kha nhi hai. Pls explain someone to me

[@dhairyasharma7782]

@@lavanyasaxena4326 Yes😊 A member of BTS ARMY and PW family 😌💟

[@fschandu9937]

42:20 sir it also have plane of symmetry. The plane passing through the vertices having ch3.

[@mystigodgaming4292]

Yeah I was about to comment the same

[@abhijeetattri3483]

1. Having one chiral centre shows optical activity 2.no chiral centre no optical actually 3.two chiral centres but having plane of symmetry so it'll not optical activity 4.having no chiral centre often having centre of symmetry so not showing any optical activity... If I am wrong then please give your helpful feedbacks ...

[@satyaratna1807]

even i hope the same

[@umamishra7757]

Sahi h bruhhh!!!!

[@arunjyotisahoo-lj3px]

58:03 2 , 3 , 4. Are optically inactive 1 is optically active and shows optical isomerism

[@beinggenuine9523]

Hit like who love Alakh sir. 😊😊

[@NetBio-Senpai]

i dislike,,,,heah

[@patelnimisha4429]

I also dislike

[@Vishal-kk6dr]

I also

[@aniltakrani4156]

Hari Om yes they should lol👎👎

[@Unique182]

Who is here after rohit agrawal sir's class and didn't understand anything

[@786mom]

Kuch kuch to samj aaya 😅

[@Hey_zen]

Ohh Bhai 🤪😂

[@gamerhunter9861]

Me

[@royaltouch3143]

Haan bhai😅😅😅😅😅😅

[@itspurple73]

Kch kch samjh mein aya but confusion hai 😅

[@ArjunDzn]

So awesome Explanation sir ❤ 1) Optically Active ( due to no POS/COS/PRESENCE OF CHIRAL CARBON) 2) O.INACTIVE DUE TO PRESENCE OF POS (BR-BR WAALI SYMMETRY) 3) O.INACTIVE DUE TO POS 4) O.INACTIVE & NO POS BUT COS PRESENT {Wedge-dash wale mein POS NHI BUT COS HOTA HAI THATS Y ITS INACTIVE, ACTIVE HONE KELLIE COS & POS DONNO NAHI HONE CHAHIYE!! THANK YOU SO MUCH SIR FOR THIS AWESOME EXPLANATION 🙏😊🥹

[@Jhingalalahuhu23]

Brother agar kisi bhi compound mein wedge-dash formula ho to vo optically inactive hota h kya?

[@rabiakhatoon5840]

Answers: 1 -optically active 2,3,4 -optically inactive ...and thanku so much sir

[@pokemonofficialhindi6149]

(1) Optically Active Reason: It has one Chiral centre ( 1- Chiral Centre -Confirmed=OA) (Chiral centre;- Sp3 hybridised C, All 4 Valency has different groups) (2)Optically Inactive Reason;- It hasn’t chiral centre ( Bcz of 2 same Br group) (3) Optically Inactive Reason;- It has Plane of Symmetry (pos) (4) Optically Inactive Reason;- It has Centre of Symmetry (cos) ❤❤🤙🏻Luv u sir😘😘

[@aryanagrawal2057]

36:10 ....POS h sir ...........agar vertical plane le jisme dono ch3 aa jay yo to ho jayga pos

[@shashankly9544]

Ek methyl grp upar hai aur ek niche hai isliye no pos

[@apkaagnibhai3464]

@@shashankly9544 nahi yara

[@apkaagnibhai3464]

Same doubt

[@shopelectronicsdaily]

Only one plane of symmetry is enough to destroy optical isomerism carrier

[@LegitGamer2345]

Aryan agrawal 40:22 fir tho yeh bhi POS hoga according to u but sir ne kaha Isme POS nahi hai then 36:10 Mai bhi nahi hoga(not perfectly identical)

[@samarthk.s9765]

At 58:03 the answer is 1... Because 2 has same group that is bromo group, 3 has POS , 4 has COS...Therefore 1 is the correct answer as it has Chiral carbon and also it does not have POS ans COS

[@m.n.5]

First is optically active only, second has no chiral centre, third has pos and fourth has cos....🙂

[@ritikraghuwanshi91]

@47:05 this is the Fischer projection of that compound and in Fischer projection the horizontal lines are actually wedge lines coming out of plane towards us....and vertical lines are actually dash lines shows groups going away from us inside the plane....so both bromines are above the plane so while drawing a line Bromine to bromine it doesn't pass through centre...that's why there is no cos in this compund

[@ritikraghuwanshi91]

And also there is a rule...that in Fischer projection there is no cos always....that's it ..

[@kaif7455]

Why there is no cos. Distance from middle of c-c bond to opposite br. I think is equal . Pls reply

[@ritikraghuwanshi91]

@@kaif7455 yes it is equal but to find centre of symmetry always try to draw a line connecting the same atoms present in opposite directions ,,,and the condition is ,,,,that this line should pass through the centre of the compound ,,,.. To yaha pe jo equal atoms present in opposite directions and equal distance from centre ko join karne vaali line compound ke centre se paas nahi ho rahi hai ya uss point se paas nahi ho rahi hai jisse hum cos kahna chaahte hain......to vo line normal line hai ko br aur br ko jod rahi hai Achcha kab jota ye beech vala point cos ....to ye tab hota jab socho ki dono br usi plane pe hote .jispe cos vala point hai...tb dono ko connect karne vali line cos vaale point se bhi paas hoti aur centre se equal dist pe opposite directions mein hame same atoms ya same grow mil rahe hote.....

[@ritikraghuwanshi91]

@@kaif7455 hope u will get it

[@kaif7455]

@@ritikraghuwanshi91 thanks

[@awesomevid5447]

Sir thank u for your support to us.... I am totally dependent on u and didn't understand from coaching... But after watching ur vedio I get very easily... 🙏🙏🙏

[@a.s.jshorts4206]

same mujhe bhi mere coaching meh ki chemistry bilkul samajh nahi aata...

[@Sachin_Meena.]

Mujhe coaching mei sab samjh ata magr phir bhi Meine saali coaching ko hi chorr diya abb sirf alakh sir se padhta hu 👈👈🇮🇳🇮🇳🇮🇳🙏🙏😊😊

[@anilnautiyal7500]

Thank u Sir ,it was just a perfect lecture .May GOD bless u 😘😘😘😘😘👍👍👍👍🙏🙏🙏🙏🙏

[@sardartejas]

Can u pls tell at 47:30 the 2 example shows COS (and all groups show cos) can u justify why it will not show cos ?

[@anilnautiyal7500]

Look in 2nd example there is no plane of symmetry becoz both the Br are on different sides and for such types of compounds we do not check center of symmetry ( aisa Sir ne ek video mai bataya tha as far as I remember .I don't remember the video now) Now since there is no plane of symmetry ,ie, the compound is unsymmetrical so the compound will be optically active

[@sardartejas]

@@anilnautiyal7500 Yes I understood,but how it is not showing centre of symmetry?pls tell

[@sardartejas]

@@anilnautiyal7500 but sir said we have to check both cos and pos if one remains it can't be OA

[@anilnautiyal7500]

These types of structuers are known as fischer projection.Always remember a trick that for fischer check only pos ,do not check cos for them .But for all other types of compounds other than fischer check both pos as well as cos .I don't know the exact reason .But u can remember it as a trick.U can go through the other comments below,may be u find ur solution there

[@AyushSingh-jo7kw]

20:28 Sir letter Z does not have any Plane of Symmetry because they are not identical mirror images

[@unknownguy4240]

To be honest there will be no questions in jee mains or neet where u would be asked to find optical activity of alaphabets 😂😂😂😂😂

[@ajaysaxena7041]

No it will show

[@aradhymishra1861]

@@ajaysaxena7041 nope

[@avinashkumaryadav2150]

Hoga bhai Z ko phele 180° ghumake dekho phir uskr mirror img pr rkho

[@ahuman4]

Avinash Kumar Yadav Sahi kha

[@parthgupta4530]

In homework ques only structure 1 is optically active and rest are optically inactive....as Structure:1(1chiral centre + no POS+no COS) Structure:2(yes COS+yes POS+ no chiral centre) Structure:3)(yes POS) Structure 4:(yes COS+ YES POS) Major criteria for a compound to be optically active is absence of POS and COS and AAOS....with essentially a presence of one chiral centre...

[@architchhajed1900]

There is no COS in (2) but there exists a POS in (2). Please correct your answer.

[@nanu9424]

ANS.... 1.IS..OA..2.3..4..ARE..OI....AM. I RIGHT.. PLS TELL. ANY.. ONE

[@kapilbali]

Yes bro

[@vatsalsoni5809]

Nhi Bhai 1.2 are OA and 3.4 are OI

[@himanshiarora4954]

@@vatsalsoni5809 2 is nt O.A bcoz 2 Br are added(same atoms)....no choral centre present

[@vikashjaiswal5158]

Yes

[@Cric_sam1734]

Yes

[@tamannakaushik1733]

Sir we pray for your diamond button

[@vikashbaghel2155]

Achha tujhe bahut padi hai modi tu hi de दे

[@akshatsharma5197]

Pehle gold to aane de

[@tamannakaushik1733]

@@akshatsharma5197 gold to bina pray kai bhi aa jayega

[@aniltakrani4156]

Tamanna kaushik what diamond button

[@anubhav7558]

1 is optically active 2 is inactive because br is same groups 3 is also inactive because we have POS 4 is also inactive because we have COS thanks sir ♥️

[@bipinsaun4789]

1: Optical isomerism 2,3,4 optical inactive.

[@Sachin_Meena.]

Ans : 1

[@mayankroat4676]

Right broo

[@akanksha5261]

54:11 right sir ye lectures Mai 3bat dekhi hu isse yhi samjh aaya ki AAP k ek ek words bhott important hai ek ek word , coaching me sir inhi SB Ko bda chada k btate hain, 3sri bar dekh k samjh gyi sir aap quality wise padhte hain n ki quantity wise, u r great sir , ek ek words Mai note krti hu kyoki aap 15 din coaching k lectures ko ek notes dete hain 1hour lectures not lectures it's amazing notes!

[@Crazy7speed]

Aapko notes 🍌 chahiye tha ..... Agar aap notes bnati to 3 bar dekhne ki jaroorat hi nahi padti

[@itzsabirkhan798]

Sir you are world the best teacher

[@BoardWallah07]

kzbin.info/www/bejne/m6bFf2SvjK-airs

[@kedarjadhav4951]

ye jyada nhi ho gya?

[@NetBio-Senpai]

@CWP -royale YT ,jiadah grammr ke dhurindhar mt bano,,galat bata rha hai,,u r the world the best teacher ye bhi glt h,,,,,,,,,,,,,,,,,,,,,,,,,,,correct is,,,,,,,,,u r the best tevcher of this world or u r the world^s best teacher

[@anujyouthoob]

@@kedarjadhav4951 Its her opinion. Spread Love bro

[@aniltakrani4156]

MD SABIR yes true sister

[@HarshKumar2904]

H.W question-1st is optically active and rest compounds are optically inactive..

[@jatinbhatoya8420]

Sir aap great ho because u r working selflessly for future of many students in this selfish world

[@viresh_koliz]

36:00 sir if we cut the compound from plane of both ch3 group then we will get POS.Correct me if iam wrong.

[@devanshverma1441]

haa ,, main bhi yahi soch rha hu,, or answer dhundne ke liye comment section mai aaya ,, lekin kisi ka bhi comment nhi mila iss topic pr,, bs aapka mila ,,

[@user-im4op8yl5c]

POS & COS dono h

[@10cakashkushwaha59]

no anhi hoga. carboh ke h ka configration alg alg hoga

[@TheBigSnek]

20:32 sir z doesn't have plane of symmetry:D

[@2005ji]

yes you are right senki

[@shivanisuraj6425]

It has one pos Check it carefully Cut z horizontally

[@Abhishek-ns9wg]

1) Yes. 2) No (as there is no chiral center). 3) No (as there is plane of symmetry). 4) No (as there is center of symmetry).

[@IAMHERE_BABY]

India is proud to have the best teacher of the World ❤🔥

[@Shubhamtiwari2533-b4d]

49:27 me carbon sp3 hybridsed hai so Br aur CH3 me kisi ko plane ke in or out me hona hoga so if dono Br plane ke out ho jane per ve ek dusre se opposite nhi rh jayenge

[@tanmaybro3812]

At 47 :30 ,acc. to me compound have COS in the middle of two carbons.

[@sauravmajumdar5443]

ha bhai vahi to

[@sarveshbhaspale9825]

same doubt

[@niveditaverma9088]

@@sarveshbhaspale9825 same

[@aasmamazumdar2750]

@@sudhishsivakumar1509 where will we get this concept .....

[@rishishah5564]

Fisher projection me cos dekhna bohut tough Hota he isliye iska Tum Newmann bna lo answer Mil jayega

[@vanshagrawal9741]

AT 47:27 I think the compound have COS b/w the C-C bond

[@PriyaSingh-ul3qb]

Cos br -br m b to lgg rha h shyd

[@sumitkatkar7371]

56:44 answers are - 1 is optically active & 2,3,4 are non-active if it is right like it or if it is the wrong dislike jai PW

[@shubhashreesa]

👍

[@DivyanshuSingh099]

In the 1, Will Deuterium (viz a isotop of hydrogen ) not be identical to hydrogen?? Just clearing my doubt, if you know !!

[@ipsitasingh5777]

Wah wah sir.. Apka notification dekhke to maza hi aah jata h

[@lakshaybansal5702]

47:50 has cos

[@gaurishsoni6407]

I guess that is applicable only to cyclic compounds only

[@abhaykumarbitsindri4940]

cos nii hoga..same group hona chahiye..in opposite direction from centre..

[@जयश्रीरामजयश्रीहनुमान-झ1य]

Noo its sp3 bro listen first sir then comment 🙏🙏🙏

[@saheb1009]

@@जयश्रीरामजयश्रीहनुमान-झ1य are cos kyuu nhii hoga do br GRP toh opposite hain

[@saheb1009]

@@abhaykumarbitsindri4940 hannn hain toh fir cos kyu. Nhi hoga

[@Neha-ft1uv]

Only 1 show optical isomerism 2.two bromo group 3. POS 4.COS

[@deepalirajdev1385]

(1) is optically active (2) it doesn't have chiral carbon (3)it has P.O.S. (4) it has C.O.S.

[@maahiverma9761]

The actual video starts at 11:50 as just before it was a recap of the previous one.

[@GAURAV-zt3ey]

thanks

[@jacobblack2544]

I know, right?

[@kalyanasishdas762]

Thanks a lot friend 😊😊 🙏🙏🙏

[@sumitkumar-jz2ny]

1-optically active and other three are optically inactive

[@JetZone11]

58:04 the answer of this question is 1) is optically active, optical isomerism due to non super imposable image formed and non cos , non pos❌

[@marampuzhamazha]

1 is optically active, had no POS and COS 2 had two bromine , had POS 3 is a meso compound 4 had COS

[@Drbeast132aa]

sir 48:32 mee tho second compound ko centre of symmetry he na sir tho oo kaisa optically active banega????

[@mathematicsdeewane6248]

Only 1st are optically active . Rest are optically inactive. Reason:1st has only one chiral centre. 2nd has no chiral centre. 3rd has pos. 4rth has cos. Is this answer is correct. Is this Explanation is right.

[@shalinigoyal5100]

Bhai 3rd m pos kha h 😂

[@xb57sufiyanezami19]

Sahi h bhAi

[@harnoortuli5066]

Bilkul sahi h bhai

[@carlmascarenhas4124]

Yes

[@manjiritammewar8699]

Sir told dont go on chirality

[@OctopusMom]

In 42:04 there is pos, if we take plane of ch3 and h of both side

[@neetuskitchen7470]

My physics teacher in school teaches by cheating your notes and watching your lectures but still she isn't that much capable of teaching in your level. I don't find any kind of benefit happening to me by school learning. Every student deserves teacher like you sir. May God bless you. You are the true definition of teacher. ❤ aur saari school teachers sir ko copy krna bnd kro because u can never be like him❤❤

[@AHBAFNAN1020]

😮

[@rasbiharimeher2370]

First of all say me that, Tou are from which collage

[@prasanuniyal9647]

🤣🤣🤣🤣it's really funny

[@smartstudy1769]

😂😂😂 very funny

[@Daredevil662]

Optically active 1 Optically inactive 2,3,4. 2- no chiral carbon 3- plane of symmetry (meso compound ) 4- centre of symmetry

[@kajalyadav4820]

Only 1st is optically active becoz of chiral centre 2nd has no chirality 3rd has POS 4th has COS

[@hrittikariya]

1 . Optically active only one chiral centre 2. Optically inactive POS is there 3. Optically inactive two bromines nd most imp pos is there 4. Optically inactive as COS is there…… ThnQ sir ❤

[@ISIBANGLOREMATH]

36:09 Trans 1,3 -dimethyl cyclobutane has one POS too... Am I right? Edit: I am right 😅😅

[@manikantanalla937]

Yes

[@p.spushpam9598]

Yes bro..

[@sk-tq6zt]

❤️❤️May Allah Give his blessings and Hidayat To you For doing such selfless Work❤️❤️ U will be always Our Favorite Sir❤️

[@agricossrushi921]

Thank you sir

[@fazil5648]

Ameen

[@noorfathima1884]

ameen ..

[@MohdAnas-fi9bn]

Ameen allah sabhi ko aapne aapnr maksad me kaamyab kre tumeh bhi

[@Sigmamaths722]

Sir iss lecture ko 5 saal ho gye or stilll bache yeh dekh rahe hai , isko please kabhi delete mt krna , hm apne bacho , poto aur parhpoto ko bhi yahi lectures dikhayege , kyonki ham apne school se jyada apke lectchro se sikhte hai , thank you , sir ❤❤❤❤❤❤

[@MohdAnas-fi9bn]

Bhai teacher kesa bhi sahi wo hmesha ye student ko maximum knowledge dene ko kosis karta h all teachers are best l👍👍👍

[@engineeringsingh4671]

U r great ❤️... U teach students without money Which help students a lots....

[@tanmoy6276]

Thanks

[@tanmoy6276]

Money doesnot matter ...Study well and make result

[@KAMALJITSINGH1201]

Plane of symmetry is present in trans-1,3dimethyl cyclobutane if we cut diagonally through methyl's.

[@sakhishopee]

One Concept point - If no Chiral Centre then Optically inactive and then dont see C.O.S or POS

[@mdtauseefakhtar6316]

Thanks Savita Mitkar

[@Rahul-qb2gu]

Thanks a lott savita , now can esily decide , i was feeling difficulty in checking poc nad cos 😊

[@shreshthborkar1907]

Sir bata chuke hai

[@abhishekbhadauriya8424]

kzbin.info/www/bejne/aIq2eGijaMSXe9k

[@AdityaKrishnan17293621_Osaka]

But there are compounds without a chiral centre that show optical activity, like certain substituted biphenyls and allenes

[@CristicMesper]

Answer of Homework Question:- 1) 1st has chiral centre so it show O.I. 2) 2nd has no chiral centre so doesn't show O.I. 3) 3rd has POS so it also doesn't. And 4) 4th Have COS it also not.... And as chemistry is a home of ••Exceptions so if any thing have exception so I cant say about it. Thank YOU for Reading. All the very Best!

[@nishikarawat1046]

sir i'm in class 12th and my 11th was spoiled especially chemistry but now i'm able to understand the concepts very easily. Thanks a lot sir. I wonder, that if this channel and you were not here then how difficult it would be for me..... : )

[@pratapstudios3665]

Khubsurat sa apna physics wallah

[@Westkanye2112]

ans to the hw question: only the 1st compound will be optically active

[@ashanasinha]

At 47:42 The compound has COS

[@ayushhhhhh781]

😢 i guess usse 3d mai dekhoge to cos nhi hoga bcz mirror image h aur sp3 hybridised hai

[@rushiikeshjadhav]

Option 1 is optically active Option 2 & 3 have POS Option 4 have COS Thank u so much SIR for explaining isomerism so beautiful Hat's off 👌

[@dhyeytank2572]

54:00:00 par 2nd structure mein CENTER OF SYMMETRY hogi toh fir enantiomer kaise?

[@chhotelalyadav-uu9dg]

Bhai 3d structure different hai

[@talhaahmed290]

See 49:00 sir explained

[@rishishah5564]

Fisher projection me cos dekhna bohut tough Hota he isliye iska Tum Newmann bna lo answer Mil jayega

[@chanduudarapu7906]

Homework question Answer is 1 2 has no chiral centre 3 is symmetrical 4 has Centre of Symmetry(COS)

[@madhusuman9744]

Never explain your talent in words what sir you deserve

[@kabeerkooksandlifestyle7135]

This lecture begins at 14:15

[@pranjalpagaria322]

47:29 centre of symmitry toa hoa skti hai na ismein

[@4_alokk]

Think in 3D. One of them is outside the plane and another one is inside the plane, So no centre of symmetry is possible.

[@phychembio9263]

Bhai zaruri thodi h ki plan m ho ..

[@phychembio9263]

Opposite & equal distance pr honi chahiye kese bhi

[@deepjyotichakraborty8684]

Same doubt!!!

[@deepjyotichakraborty8684]

@@4_alokk Doesn't matter whether it's 2D or 3D Bhai... Condition for COS is that same group should be present in equal distance and opposite side from a centre....

[@MusicalMedicoChayanikaSamajdar]

47:37 Has COS ... I think ... sir please clarify it ....

[@varshachaudhary5357]

47:00 cos to hai na iske paas.🤔🤔.. agar dono C ke beech khade ho jaao to opposite direction mein same atoms/groups mil jaayenge

[@sudiptoboral6427]

Jyasa ki sir ne bola , ye sp3 hybridised hay too Inka 3d may structure alag dikhega aysa plane Nehi

[@madhusingh8564]

Only 1 is optically active Thank you Sir for teaching us.

[@jaismineagarwal2767]

I think not