Work, energy, power 02 | Work energy theorem | Kinetic energy | 11 | NEET | IIT JEE | Pace Series |

[@PhysicsWallah]

Watch Ad Free Videos ( Completely FREE ) on Physicswallah App(bit.ly/2SHIPW6). Download the App from Google Play Store. Download Lecture Notes From Physicswallah App(bit.ly/2SHIPW6) Notes Available at Home Page of the App(Home--Pace) PACE - Class 11th : Scheduled Syllabus released describing :- which topics will be taught for how many days. Available at PhysicsWallah App :bit.ly/2SHIPW6 Duration:-3months (Nov 2020 - Feb 2021) Free Batch Exclusive on our KZbin Channel:PhysicsWallah-Alakh Pandey Batch Details 1)Best Faculties across India for different Subject/Topics. 2)Complete & Relevant Syllabus Coverage of Class-11th within 3 Months- Fastrack Nov 20,2020-Feb 20,2021 3)Monday-Sunday : scheduled Classes everyday ( for each Physics, Chemistry,Mthematics & Biology) 4)FREE videos without ad available on app 5)Notes Link on Description Physics:Tues,Wed,Thur,Fri,Sat : 3:00 pm Chemistry: Physical & Inorganic Chem: Mon,Tue,Wed,Thur,Fri:7:00 pm|| Organic Chemistry:Sat,Sun : 9:00 pm Mathematics:Wed,Thur,Fri,Sat,Sun: 5:00 pm Biology:Wed,Thur,Fri,Sat,Sun: 10:00 am 4)Scheduled Syllabus released describing :- which topics will be taught for how many days. Available at PhysicsWallah App :bit.ly/2SHIPW6 Lakshya Batch-Complete Physics for Class 12th BOARDS/JEE MAIN/NEET Yakeen Batch-Complete Fastrack Course(11th & 12th) for NEET Accelerate Batch-Complete Fastrack Course of PCMB for Boards/NEET/JEE Mains Prayas Batch-Complete Fastrack Course of PCM for JEE Mains &JEE Advanced For more Details of the Batches visit PhysicsWallah App(bit.ly/2SHIPW6) New KZbin Channel : PhysicsWallah Foundation-9th & 10th: kzbin.info/door/phU2bAGmw304CFAzy0Enuw Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6

[@whysopuzzled6474]

Thanks you sir for all this

[@mohdalam2995]

Thanks for pace batch

[@subham_yadav]

40:17 Sir friction ka workdone ke liye apne 20/3 or mg ke workdone ke liye 4 Kyo ab ye mt kahna ki direction ke hisab se liya h 😁

[@subham_yadav]

Sir 3 se divide bhi nahi kiya 👆 isi question me Vase answer √58.66∞

[@subham_yadav]

41:56 RG SIR: AIR resistance ? We : neglected the air resistance 😁

[@authoryajat]

40:42 sir there is a mistake you accidentally ignored the 3 in denominator then the answer should be v^2= 176/3

[@mohitkr7428]

You are right

[@anujkuntal4135]

Yes sir it's a mistake. Sir you ignored the denominator 3 .

[@user-tw8nm1sv7g]

exactly

[@bhaumiktalwar5961]

Sir bhool gae

[@adarsh1854]

I'm also here to see who other mark the mistake.😂

[@saranshsharma8904]

Student: sir numerical aasani se kaise solve krae 🥺 Rohit sir: subsae phela kam sundar diagram 😁😁

[@aarvisingh4969]

😊 kzbin.info/www/bejne/gZW8YoN7hph9eck

[@SG-nd7hx]

kzbin.info/www/bejne/i3yXq4Wqd616p7s😁

[@nilesh3646]

maza aaya to thoko taali

[@onlymusicbeats3020]

Correct

[@empowerHour380]

👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏thoko talli

[@educationwithimranali9212]

Physicswala , the legend teacher that I have ever seen . Sir I solute to your struggles from Pakistan . love to see your classical video lectures of physics .

[@parthnalwaya4785]

hahaha tumhare yahan teacher mil bhee nhi skte

[@subhanahmadkhan]

@@parthnalwaya4785 bhai wo banda agar kuch respectfully tareef bhi karra hai toh tu uska mazaak kyu udaa raha hai?

[@parthnalwaya4785]

Pakistani ho? Btw ok i respect it

[@subhanahmadkhan]

@@parthnalwaya4785 indian hoon bhai

[@subhanahmadkhan]

@@parthnalwaya4785 waise bhi mere desh se kya matlab

[@armanmehla8543]

After completing the video Sir : Ab btata huun us macchar ko 🤣🤣😂🤣😅

[@nabeelkhan8518]

Yes😄

[@subham_yadav]

41:56 RG SIR: AIR resistance ? We : neglected the air resistance 😁

[@parth7553]

We can neglet if the speed is slow but in this speed is 20m/s so it will not be negligible you can see from answer 😁😅😅

[@MayankSingh-ow1dd]

kzbin.info/www/bejne/imbYanp_jbunq5o

[@mayankpandey5079]

MY TEACHER -- EXPLAIN SPEED OF LIGHT...⚡⚡ Me -- IT IS THE SPEED WITH WHICH COMMENT GIVERS COMES AT PACE BATCH..🔥🔥💥

[@SG-nd7hx]

kzbin.info/www/bejne/i3yXq4Wqd616p7s👍👍

[@ashishsingh3194ydhaw]

kzbin.info/www/bejne/nJ3Nc5Swm8ilZ7s

[@hellokumar1936]

@@ashishsingh3194ydhaw nikl

[@mayankpandey5079]

@@ashishsingh3194ydhaw Shanti ka daan de...

[@mayankpandey5079]

@@ashishsingh3194ydhaw matlab ki bhai bina matlab me kyo lad re ho dono..

[@hellspawn5193]

The intro music is : Island ( NCS) 😬

[@blyezone4430]

kyu baukala raha h be

[@diedforu]

@@hellspawn5193 tum yaha pe kya kar diye ho bhai??😂😂

[@bruhify5269]

Haaggg diya bhencho

[@cms.177]

@@bruhify5269 😂😂😂👍

[@Atomixx6886]

@@bruhify5269 😂 bruhify copy

[@alamsheikh5025]

Legend is always legend!👍🏻

[@time4935]

JUST 30 MINUTES AGO I WAS ATTEMPTING MY EXAM OF SCHOOL AND THIS QUESTION if kinetic energy of a body is increased by 300 percent its momentum will increase by I WATCHED THE LECTURE FOR 40 MINUTES BEFORE XAM AND WAS ABLE TO ATTEMPT THIS QUESTION SPECIAL THANKS TO ROHIT SIR😉😉✌✌

[@divyanshsrivastava2314]

Waah bhai ,waah

[@blyezone4430]

"kismat ka khel h babu bhaiya kismat ka khel"😂😂😂

[@thinkofkick6051]

@@blyezone4430 ladki chakkar babu bhaiya😱😱😱😂

[@blyezone4430]

@@thinkofkick6051 ha lakin yaha kismat ka chakkar*😉😂😂

[@thinkofkick6051]

@@blyezone4430 kismat k nai ladki k chakkar babu bhaiya😏😂😂😂😁

[@prateekyadav5578]

19:40 bhoot bhi sundar diagram bna rha tha 😂

[@dhruv9618]

🤣🤣🤣🤣

[@devchauhan1627]

😂😂😂

[@MayankSingh-ow1dd]

kzbin.info/www/bejne/imbYanp_jbunq5o

[@leisuregaming7627]

maine khuch nhi pada koi important chapter ya topic btado physics se jise mai bass pass ho jauu plzz

[@rahulattri9142]

Really Rohit sir is not less than Alakh Pandey sir.. Understood the whole concept in the First attempt.. loved your way of teaching 🌹🌹👍

[@mananarora4583]

Sir is bringing revolution with full speed . Thank u sir🙏🙏

[@SG-nd7hx]

kzbin.info/www/bejne/i3yXq4Wqd616p7s👍

[@kuldeepmishra7568]

kzbin.info/www/bejne/nn_dhHiGarp7a5o (physics wallah fan video)

[@hellokumar1936]

Nikl

[@sumit2162]

41:19 sir apne 64 ko 3 se divide ni kiya....

[@hellspawn5193]

Haa

[@saurabhdeulkar888]

+++++ (❁´◡`❁)

[@vishalbhagat2124]

Ha

[@ananyakumarnayak1540]

Haa bhi mera bi wohi he Ans is 64/3=21.3

[@dhruvkumarkanaujia]

sponcer krdo yeh channel

[@imsahil37]

Now we've crossed the DoE class physics today😂 Congo🎉

[@SG-nd7hx]

kzbin.info/www/bejne/i3yXq4Wqd616p7s

[@ashishsingh3194ydhaw]

kzbin.info/www/bejne/nJ3Nc5Swm8ilZ7s

[@Samadkhan-mv9hw]

@Haniya Khan DoE kon hai?

[@aishwaryapatel7393]

DoE mtlb?? Date of enauguration.

[@imsahil37]

@@aishwaryapatel7393 Nope Department of Education Tumhe nhi pta...edudel ki daily live classes chl rhi h on youtube .. @Core Academic Unit

[@prix_07]

Best best best best best bestest lecture even whole series....I love it ..thank you rohit sir hats off 👏 👌 🙌 padhlo chahe kahin se selection hoga yahin se....I m aakash institute student but but ...now u know well 😌🤗🤗🤗🤗

[@krishxjee]

I'm also a student of AAKASH but now.... you know it😉

[@shinchannohara2924]

i was stuck in these percentag echange questions of work,power & energy. i searched a lot on internet.......finally this was one stop destination. awesome explanation.

[@sahidurrahaman314]

Rohit sir : kinectic energy directly proposal to m when v constant and indirectly proposal to m when p constant .......I think 😅😅

[@sameertolani4447]

Proposal nahi Hota Vo.. Proportional Hota h

[@aadilyaseen7848]

What about Separate sessions for question practice in physics like that of maths

[@SG-nd7hx]

kzbin.info/www/bejne/i3yXq4Wqd616p7s😘

[@aadilyaseen7848]

@@studentaccount2100 he is nice , but it will be good to practice more questions

[@abhijeetrajpoot529]

Sir Maja aa gya numerical solve kr k aaj thank youuuu so much sir ❤️❤️❤️❤️❤️ pahle physics se bahut dar lgta thaaa pr ab Aapne isko bahut easy Bana Diya h ..........thankuuuuuuuuu sir jb ye pace batch start Nahi hua tha to sooch rahe the k kaise khatam karange itna Sara syllabus bilkul bhee Nahi padha tha pr ab vo bhee complete hone laga h dhere dhere

[@ndajaihind932]

At 40:58 sir had done calculation by mistake wrong so you have to understand by your own becz sir didn't take 3 in divide...... How many of youh notice👍👍 Thoko Tali👏👏

[@harshkumar__6915]

Very good teacher thanks Sir alakh sir thanks🌹🌹❤🌹❤🌹❤🌹🌹🌹🌹😊😊😊😊😊😊😊

[@harshkundu8196]

28:28 "acha macher kar raha hai ye " 😂😂😂😂🤣🤣🤣

[@sauravgarg7193]

For all of you here at 12:41 I have very interesting formula to find percentage change invented only by me abd it's super easy So it is like : If x is directly proportional to y^t and change in x is given by x% then formula is ((1±(x/100))^t-1)×100 Try this in all example sir did and it is satisfactory So everyone please share this to your friends with name of Saurav formula But no copy right because it is very obvious formula that every can find And also I have to conclude here that ± sign in above formula shows that if change is negative than you can use- and if change is + then same Also if you have given that x is thrice or twice you can replace 1±.. with that in above formula only Thanks

[@aatifsayeed8408]

Kya mast padhate hai rohit sir❤🙏 lajawaab🙏❤ bemisaal🙏

[@shivamarora2969]

30:18 Sir my answer comes out to be 2√15 m/s.

[@friskygaming6737]

The answer of the question a block of mass 2kg is kept on a rough table of coefficient of friction 0.2 to a force of 20 Newton's act on the Block are the angle of 37 degree with the horizontal find the speed of the block after the travel a distance of 5 m and the solution of this question is V is equal to under root 72 m per second

[@1MinTakeAway]

Work energy theorem :- The change in kinetic energy of a particle is equal to work done on it by net force . 1. For constant Force :- work done is W= FS i.e ∆k= W . 2. For variable force :- work done is W= integration xi to xf f(x) dx i.e kf-ki = W .

[@bruhify5269]

Hag diya

[@prashantraj8241]

Dono sahi hai 1st wala jab velocity constant hai 2nd wala jab momentum constant hai

[@harshjain3812]

Ty for providing education 🙏🙏❤️

[@kvathishpranav4112]

22:20 omg u guys are spending lot for our studies😯😯😯 THANKS A LOT SIR WE WILL MAKE U FEEL PROUD

[@ashishsingh3194ydhaw]

Sir hindi medium ke liye bhi course jaldi start karo

[@rihanshmishra..6415]

Gajab sir SABSE PEHLA KAAM SUNDAR DIAGRAM....!!! guys see the Rohit sir T SHIRT...

[@SG-nd7hx]

kzbin.info/www/bejne/i3yXq4Wqd616p7s😘

[@jeeaspirants2161]

Sir plZ lounch hindi medium course for jee🙏

[@akshra2135]

Sir you are teach very best in all world mujhai pahle physics me interest nhi tha but aab physics aapki wajah se easy ho gai thanks sir

[@nidhigupta799]

First physics vedio in pace batch in which Rohit sir laughed a lot😂😂😅🤣

[@arpitdadhich4921]

Hloo

[@rajsharma-lu9gr]

At the 41.31 min ke question par sir apane 3 se divide nahi kiya hai tobhi 3 cut kar diya hai. Or pura solve kiya to 4 m/s nahi ,, √ 58.6 m/s aa raha hai sir!!!!👍👍👍👍👍

[@abhijeet7629]

3:16 Ans- 2√15 m/s

[@subhechhasahoo8297]

sir in 40:57 80-64/3 = v*2 v*2 = 176/3 v*2 = 58.66 v = 7.66 m/s THANK YOU !!!!!!

[@veerpatel2598]

Thanks Rohit sir for hard numericals and there easy explanations with sundar diagram 😂😂

[@chinmaydeo3711]

*_sir, at _**_41:22_**_ the work done by friction force will be -(3.2)(20/3) so the answer is coming out to be : v^2 = 176/3. am i going wrong somewhere?_*

[@pratibhakushwah7445]

Right

[@ashishsingh3194ydhaw]

kzbin.info/www/bejne/nJ3Nc5Swm8ilZ7s

[@Cal-C_007]

quote on Sir's sweater "PEHLA KAAM SUNDAR DIAGRAM."😁😀😂🤣🤣🤣 👇

[@asheeshkumar791]

30:25 N=5g-20sin37° So, f=u(5g-20sin37°) so answer is V=2√4.2m/s

[@himstitute9030]

40:55 sir yaha pe aapne 3 chor diya denominator me jiske karan 4 jo answer aaya wo glt hai so right answer is rootunder176/3 m/s

[@jitendra3446]

Yes bro 👍👍

[@diyaagrawal5048]

Wah wah sir 😳 Jazab,thanks

[@abhayverma8446]

ALAKH SIR A=Adorable than other L=love for all A= adulate K=kind hearted H=high in demand

[@Nisha-ym2to]

Oooooo 😯😯😯😯 niceeee

[@abhayverma8446]

धन्यवाद

[@Nisha-ym2to]

@@abhayverma8446 welcome

[@imsahil37]

53:45 After 2s... As the particle comes again to x=3 and the given force is conservative... Work done is zero.

[@daaneshsingh8684]

40:58 sir by mistake forget about 3 in the dinominator that was 20/3 sir take it as 20 only, by mistake. No problem sir.

[@sudhanshubhatt5040]

Sir question ( 41:16) me final answer (80×3−3.2×20)÷3 hoga or velocity √58.66 hogi ❤️❤️❤️❤️

[@priyam503]

35:54 😂✌️ Headlines ban jayega

[@juniorrrrrrrrrrrrrrrrrrrrr]

Sir, you are the most influential, kind-hearted and positive person I have seen in my life, after my dad...

[@candygirl6401]

Can u tell me does this playlist cover whole chapter or just imp topiks

[@hostelers18]

PHYSICS WALLAH(at door) : Knock knock 😎 VEDANTU : Kon aaya hai.🤔 UNACADEMY : Mai dekhta hu🙄 PHYSICS WALLAH : TERA BAAP AAYA😈😈

[@thevoiceofmahaksingh5249]

Copy paste 🤣🤣🤣

[@hostelers18]

@@thevoiceofmahaksingh5249 Oo maa kasam phle maine bnaya tha kl kisi or ne isse copy kia tha

[@Lucifer-pj8vc]

Dada aaya😂🤣

[@thevoiceofmahaksingh5249]

@@hostelers18 koi Nahi Achha banaya hai 😂

[@SG-nd7hx]

kzbin.info/www/bejne/i3yXq4Wqd616p7s😘😘

[@peeyushsrivastava3741]

Second one is correct sir Because when the kinetic energy will increase then the potential energy decreases by formula mgh. of PE

[@adityasanjaysalve3718]

We alll thank u physics wallah sir for making this platform for us and yaa this sir is mind-blowing Yes or not plssss reply

[@SG-nd7hx]

kzbin.info/www/bejne/i3yXq4Wqd616p7s😉

[@somnathmahatha7591]

Sabse pehla kaam Sundar diagram 🥰🥰🥰🤩🤩🤩

[@SG-nd7hx]

kzbin.info/www/bejne/i3yXq4Wqd616p7s😘😘

[@avrpavankumar842]

Sir circular motion me aapne angle of banking ka formula nahin bataya

[@aarvisingh4969]

😊 kzbin.info/www/bejne/gZW8YoN7hph9eck

[@SG-nd7hx]

kzbin.info/www/bejne/i3yXq4Wqd616p7s

[@avrpavankumar842]

@@SG-nd7hx are kuch kaam ki baat karo

[@SG-nd7hx]

@@avrpavankumar842 kya kam

[@harshgargpb31]

At 28:18 Sir please Check Your Calculation apne 3 katt deya haii...... Vo nhi ktte ga.... Aur V ke value aye ge √176/√3... Pls Tell me this is Correct .....🙏🙏 Sir Pls tell Me, am I right or wrong....🙏🙏 THANK YOU FOR GIVING HUGE KNOWLEDGE...❤️

[@vaishnavikumari5242]

Sir circular motion me aapne death well wgera nhi pdhaeya😅??plz rep.. Will it be taught??

[@shilpiyadav9920]

Sir, today's class was superb 😉😉👍🏻👍🏻🙏🙏🙏

[@Kunalishere_1111]

Sir pura Work done hua crystal clear... 🙏🏻🙏🏻✌😇

[@AbhishekKumar-vt2oh]

Yee

[@sauravgarg7193]

For all of you here at 12:41 I have very interesting formula to find percentage change invented only by me abd it's super easy So it is like : If x is directly proportional to y^t and change in y is given by y% then formula is ((1±(y/100))^t-1)×100 Try this in all example sir did and it is satisfactory So everyone please share this to your friends with name of Saurav formula But no copy right because it is very obvious formula that every can find And also I have to conclude here that ± sign in above formula shows that if change is negative than you can use- and if change is + then same Also if you have given that x is thrice or twice you can replace 1±.. with that in above formula only Thanks edit: sorry there is change in above sorry very very It is change that change is in y with y % Thanks

[@asheeshkumar791]

41:25 I think that you have done a wrong calculation. It may be 240-64/3

[@jatin8886]

4/√3m/s hai answer

[@tamilcircuit2734]

Alakh ji is the only example for growth... He Started his journey with white board and now he is a legend 💞

[@Officiallyarohi]

Machhar Ka Khoon Kar Diya Sir NE.... 😂😂😂😂😂❤💛👍🙏

[@amanhehu]

kzbin.info/door/FpHyPLRvEyzYK0OCvBkZpg Need bio as a fuun 😅😅

[@SG-nd7hx]

kzbin.info/www/bejne/i3yXq4Wqd616p7s😁

[@prajapatisatyam6931]

Sir, you are the best 👍💯 teacher but sir.. Ek baat hai... Aap 1-5 count kiya kijiye so that we can take screenshots and note it...

[@allifazhar]

Aur mene pehla question ❓ galat krr diya😔😔. But concept revise hoo gya❤️

[@Ajay0pp]

Bro Konsa class ho app

[@anubhavparasar8917]

Sir i hated physics. But sir u have changed me .. Now I want to do physics the whole day.. Sir please continue this till class 12th also please 🙏🙏🙏🙏🙏

[@lakshitpaliwal7428]

Energy ⚡level

[@AmanSingh-yl3ly]

30:00 ans..=√48 m/s 😉 Sir ye box ki arrow ni samajh aati Ye Kya force Nikal Raha hai Kya isse Arrow to left side se lagegi n... Ese lag Raha hai ki box se force Nikal Raha hai 😞 arrow ke chakkar Mera ans. galat ho gya... (It's just my doubt ki left corner par force dikhani chahiye n)😕😕

[@prt4691]

Bhai box se force nhi nikal raha hai Aisa mano ki rope hai usko tum kuch rahe ho Toh F force tension jaisa dikhne lag jayega tumhe Hope this helps 👍

[@abhijeetgupta.62]

30:40 Is question me mai sahi solve kar raha tha but thoda mistake hone ki vajah se Mera answer = √60 answer aa raha tha

[@adityasinghyadav4466]

Q. Inclination of 37° and height is 4..... sir mistanken here.. ans is √176/√3

[@meetaxarduhan1693]

Rohit sir's interview is under-rated 🤣

[@otakusonline9860]

Hello bacho intro so heart touching 🥺🥺

[@nidhigupta799]

Sir aapne 41:00 mein 3 ko glti se cut kr Diya

[@aggarwalnaina36]

Both are right ( kinetic energy)

[@SanjayKumar-fo3ih]

Rohit Sharma aur hamare Rohit sir me koi different nahi hai Rohit Sharma waha maidan hit krke boundary lgata hai aur yaha Rohit sir phy me numerical ko hit krte hai Who agree✋✋✋✋👇👇

[@jangirrahul07]

Best teacher ever sir plz class12 bhi PACE krdo

[@gautamkumarchoudhary7794]

40:48 Aapne 3 se divide nhi kiya 64 ko Issiliye aapka perfect answer aaya 😂😂😂

[@kashif4300]

30:12 vale ka answer shayad √72 m/s hai sir , Btw sabse pehla kaam Sundar diagram Edited:::: are are are , sir mummi kasam Bina dekhe Kara tha , shi answer aaya sir sir sir 🥺🥺🥺🥺 , kitti Khushi ho rhi mujhe sir , yippppiiiiiiiiiiii 🥳🥳🥳🥳🥳🥳

[@ashishsingh3194ydhaw]

kzbin.info/www/bejne/nJ3Nc5Swm8ilZ7s

[@narendraraikwar5977]

19:40 sir sayad mouse mai problem hai plz replace cell fir thik ho jayegaa 🙂

[@dhruv9618]

Bhai ye smartbord hai. Is me mouse hi use nahi hota.

[@narendraraikwar5977]

@@dhruv9618 bhai hote hai camera mai nahi dikhta hai usse cpu contact mai rehta hai👍

[@prathmeshsingh9699]

Sir ne to advanced level tak ke numericals kara diye is lecture me

[@SouvikDas777]

v = √60 m/s Edit: are haan sir upar wala component to liya hi nahi....jaldbazi...😅😅👍

[@anuradha5355]

Physics wallah is now becoming a platform

[@PW-Unofficial1500]

31:38 DOUBT- sir friction m humne Normal reaction se multiply kyu kiya instead of mg. Please tell sir🙏

[@PW-Unofficial1500]

@Haniya Khan ha to yha Normal se multiply kyu kiya instead of mg...

[@prt4691]

Bhai dekho frictional force= uN Zada taar question mein N= mg hota hai LEKIN!!! Iss question mein dekho N+20sin37°= mg tha (kuch nhi y direction mein force balance kiya mene bus) Toh N+20×3/5= mg N+ 12= 20 Normal force= 8N aa gaya Hope this helps 👍 Yaad rakhna N hamesha mg ke barabar ho zarori nhi hai 👍

[@hasanhazary2680]

From Bangladesh. Thanks to physics Wallah

[@atullamba2138]

Lagta hai bhoot ko bhi Rohit sir ki physics mai interest aa gaya😂😂😂😂😂😂😂😂👇👇

[@technomathematics1211]

Tare y hai ko bhi nahi hai kya aap jante han ki vah apane aap ko samarthan

[@madisonmarley]

Konse collage me ho bhai tum abhi

[@aayush8922]

Sir aapke lecture me bhut mazaa aata h padhate bhi achha ho aap aur mazzak bhi karte ho Great sir🙏🙏🙏🙏

[@SG-nd7hx]

kzbin.info/www/bejne/i3yXq4Wqd616p7s😘

[@vatsalkumar7265]

41:20 sir 3 kaise kata?

[@SayanMondal-w8r]

Mera bhi same question yar

[@rajmanishyadav3037]

Aap bhi aacha hi pdhate ho sir par humlogon ko phle wale alakh sir se hi pdhne mein maza aata hai

[@masa7894]

Sir denomeneter ka 3 kha gya Mera ans to √176/3 a ya h. 41:11

[@walnutmathseducationpz]

Same here!

[@saritashukla7286]

Best physics teacher clear all the concept

[@siddharthgarg350]

AT 41 : 00 SIR AAPNE DIVIDE BY 3 NHI KIYA

[@chiraggera3579]

Correct

[@FlamboyantSlayer]

You are a great teacher sir . ❤️

[@lavish195]

Ghost 👻 also wanted to study Physics by Rohit sir😜😜

[@doom5832]

Stfu

[@leisuregaming7627]

maine khuch nhi pada koi important chapter ya topic btado physics se jise mai bass pass ho jau

[@lavish195]

@@leisuregaming7627 kalash parvat me jaa kr tapasya kr 🤣🤣

[@doom5832]

@@leisuregaming7627 sb ch ka crash course dhundh le

[@leisuregaming7627]

@@doom5832 crash course matlab btado

[@HarshRaj-xd6ix]

Direction of friction in moonwalk is forwards and work done by friction is negative

[@prateekyadav5578]

19:40 lgta h bhoot ko physics samajh nhi aarha tha isi liye class disturb kar rha tha 😂

[@pranhitaydvyadav5005]

K.E. is Directly proportional to M

[@subham_yadav]

40:17 Sir friction ka workdone ke liye apne 20/3 or mg ke workdone ke liye 4 Kyo ab ye mt kahna ki direction ke hisab se liya h 😁

[@Play_Adda]

At the time 30:20 answer:- Speed is =√72m/sec Because normal force=8N So that friction force=1.6N...... .............................................continue

[@badboyx69]

51 :55 😭😭😭 sir u should have told about that f earlier I was confused for 10 mins

[@tauheedumar5279]

?

[@Akhand-BHARAT-]

Where is the energy come from, If it can't make or destroy, I wrote a theory or postulate in it,

[@shivamarora2969]

Yes please tell.