Picard method of successive approximations example for solving ODE

[@rafidavis1961]

This is brilliantly clear. Thank you so much!

[@joevanderen64]

Thank you so much for this great explanation. It may have been worth noting the pattern that exists that could make higher orders easy to find. All odd powers are being divided by each odd number less than or equal to the power and even numbers follow the same pattern. Must just be this specific given function.

[@shaikhfarheen5051]

Thank you so much sir... . It's very helpful...😇😇😇

[@dindupavanpavan348]

Your explanation is very excellent

[@Civillearningonline]

Thank you

[@RamaDevi-mz4nc]

Thank you 😌😌 super explanation

[@manim5514]

But sir u didn't find y(0.1)

[@bbbrrrnkk1906]

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[@bikygroup5864]

Very helpful

[@gayandesilva3180]

Thank you sir!

[@SperaLekoria]

Nice i lost during facual class

[@manim5514]

Thank you sir..nive explanation

[@Nikhil-xm8ti]

Mam ek question solve krna Apply Picard method to solve initial value problem upto 3rd approximation dy/dX= x^2+y^2 given that Y=0 when x=0

[@anp9929]

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[@dailyshorts880-q9d]

​@@anp9929 😂

[@pratibhasingh8474]

Thank you bhaiya 🙏🙏

[@Civillearningonline]

Welcome behen❤️🙏

[@ruwansaranga-o7p]

nice

[@dailymixwithbattili.ganesh1684]

Thank you sir

[@odishi-ff]

Awesome sir

[@NavneetSanap]

Thank you

[@harsha0927]

super

[@Tendril0]

Y'=xy+1. Y(0)=0 solve please

[@Mr_Billions]

which method

[@Roxx142]

Hii

[@Tin_tin1]

​@@Roxx142bas jis jgha ladki dikhe hi hi or kuch kaam nahi hai KZbin ko to chod de

[@fafirita2049]

Thanku sir

[@asmaa.ali6]

is y(0) same as y_0 ?? if so, this means that y_infinty same is y(x=infinity)!

[@Civillearningonline]

Y(0)= Y(X). So in equation we put x=0, to get the value of y.

[@sunny_kashyap98]

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[@Civillearningonline]

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[@Civillearningonline]

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[@sunny_kashyap98]

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[@JashanDhillon-zl3yj]

👍👍👍

[@KunalKumar-kq6nk]

bhaya aap ka video aaca hai lakin hindi me bata na

[@Civillearningonline]

Start kiya hu Hindi me bhi. Ye method bhi hindi me aayega jaldi hi. Civil learning Hindi channel pe

[@itishreemalik5239]

Thank you sir😊

[@saveenravindu]

Thank you sir

[@vaeyt]

Thank you sir ❤