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@Happy-pz2ntАй бұрын
59:47 question answer Area of triangle =|a×b| /2 Here taking a×b we get, (-4-12) - (-2+3) + (4+2) = -16-1+6 Taking magnitude|a×b| √(16^2+1^2+6^2) =√(293) Applying on are = √293/2 😊
@jjumaneeАй бұрын
There is no 12 in question
@jjumaneeАй бұрын
My answer= . Area of ∆=1/2 |a(vector)×b(vector)| A×b=|I^ j^ k^| |1. 2. 3| |-1 4 -2| A×b=I(2-3)+j(1-3)+k(1-2) =-i-2j-k |A*B|=√(-1^2 + -2^2 + -1^2) =√1+4+1=√6 Area of ∆=√6/2
@farhankv-d4hАй бұрын
@@jjumanee AxB=4-3 aannn vro take 2-3 aa edthadil ann mistake pattiyad 🙂