Pointer Arithmetic (Addition)

[@iamaprogrammer1022]

Initially p has address of a[2]... And p=p+2 means two shift towards right from initial address.. So now.. P will have a[4].

[@mdghufranalam7369]

and uh also write as P will have 4[a].

[@modapothularajasekhar4645]

[4]

[@youmemeyou]

​@@modapothularajasekhar4645&[øk]

[@TantawyAhmad]

WOW!! Literally, best programming intro and C explanation I've seen so far the series is Amazing!! ❤ and the explanation is very simple😊 Please post daily content👌 I came here for the "Data Structure intro" but found the explanation worth to review the basics of programming all over again. I'm sure the other playlists are as good as this one. Thank you so much!!😊 Please post from the Data Structure part on your road map 🙏 >>Data Structures: 1) Stacks 2) Queues 3) Linked list 4) Trees 5) Binary search trees 6) Binary heaps 7) Graphs 8) Tree traversals

[@tlarson91119]

0:50 A shorter way would be to just get rid of the ampersand and [0]. When an array name is used in an expression, the array is automatically cast to a pointer to the first element of the array. So one could also write: int *p = a;

[@simonmarabi2661]

exactly

[@hetaeramancer]

he's teaching it systematically. mentioning that shortcut will cause confusion to beginners

[@techmad8204]

Yes, isn't this the reason why we don't use & in scanf for strings?

[@gyanusingh9416]

@@techmad8204 yeah man

[@sahil1307]

@@techmad8204can you tell me which resources are you using to learn c

[@abdelrahmanm.6215]

Your videos have honestly made a HUGE difference in my academic career. i thank you from the bottom of my heart for putting in the effort and time.

[@MrAjaypatole]

Base Address= 1000 , p= &a[2] = 1008 , p= p+2 = 1008+2*4 = 1016 , p= a[4]

[@swapnilchavan8378]

Awesome

[@andreeastanciu328]

This is the most amazing C tutorial. ❤️ Very good job, I can't wait for the playlist to be finished.

[@seunlivefootball]

Wish i could see you and give you a hug, like right now! I have been trying to understand this pointer of a thing for more that three days, but here comes NESO ACADEMY which such a lucid explanation. Thank you very much! You've made my day.

[@labandaetoilista4873]

The answer is : the pointer will point to : a[4]

[@bhargavskulkarni2855]

How

[@bbom9197]

​@@bhargavskulkarni2855it moves the pointer 2 index forward. Thats the fifth index Which we write a[4] Because counting begins from 0

[@pascalchinedu6705]

This series has made me attempt C programs I found difficult. I can't thank you enough sir. Better late than never. I'm glad I saw this academy

[@080_cse_sanjaykarthicks4]

Initially I thought that the pointer concept is very complex. But after watching videos of NESO academy about the pointers,I have started to understand the concept. Thanks for the instructor for making me understand the complex concept in an efficient way.

[@sunilkumarreddy6537]

It is realy a good explination for me apart from the class and coaching section. Thank you sir

[@Neha-zm7by]

I never commented on anyone youtube channel but neso how can i thank you i am understanding everything(apart from recursion) and now i think i can pass my exam

[@nisha..sharma..8554]

I have taken course on udemy in c programming.. but after some days I have seen this channel on KZbin .. and I have a thought about wasting my money on udemy... ❤️❤️❤️... Thank u so much sir..

[@nirbhayparmar]

a[4], 5th element of the array

[@shiranabbasi3044]

No need to multiply by 4 in case of int array. See this example int size = 4; int arr[] = {1, 2, 3, 4}; int* p = &arr; *(p + 1) = 9; for (int i = 0; i < size; i++) { printf("%d ", arr[i]); } It should print: 1 9 3 4

[@ramarajujaya2480]

i can't express my happiness to find a great lecturer like u i am veryveryvery very happpy

[@OshiniVidharaJayaweera]

Thank you so much for these amazing videos. I understood really well what are pointers and literally I understand each point you explain. The best teacher ever for programming. Whoever I meet with doubts in C I will recommend Neso academy for sure

[@raghavattri9449]

I tried various platforms to learn c but the quality of explanation that u give is next level

[@studyspectra_1980]

And is a[4]..as p=p+2 simply means shifting the pointer by 2 units from the initial position in forward direction..ie.from a[2] to a[4]..

[@yasharora4300]

Thank you so much sir. Best explanation on complete KZbin.

[@badavathjaipal7027]

primary address is p is array of 3rd element i.e p=&a[2],when we add p=p+2 then new address i.e p=&a[2+2]=&a[4].which refer 5th element.

[@rajivkumawat7940]

ans is 4. sir i am 1st year student in iiit gwalior in IT stream. my programming language was going extremly wrost but neso academy saved my engineering life .i saw many youtube channel related to programming language but this one is extremly good. i gain more dept interest in programming because of you. so thank you very much sir for creating such kind of channel which helps all students . 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏thank you very much sir 🙏🙏🙏🙏🙏🙏

[@ashwanikumarsrivastava1187]

You are the best teacher for C programming

[@niteshsoni8956]

ANS- index will be 4....Sir thank you so much for teaching and sharing such amazing knowledge of C with us!!

[@seshanky]

Brother am sry but can u pls say what is an index 😅

[@EigenA]

Taking care of me in signals, controls, and now during an internship. Great work!

[@tinkukumarsiddharth2281]

I didn't understand the any programming language in the,but here I am learning it with the interest.

[@mohamedmezid4821]

Answer of the question: After the operation "p = p + 2", the pointer p will now point to the memory address that is 2 elements ahead of its current location. Since the initial value of p is the address of the 3rd element of the array i.e &a[2], after the operation p = p + 2, the pointer p will point to the 5th element of the array i.e p = &a[4]. Therefore, the index of the array after this operation is 4.

[@adnaneafifi4734]

If we want a[2+2] a[4] we have to multiply p=p+2*4 if we assume that the data stored is an integer.... and if we assume that the value of the integer a[2] is in 1002 to go to a[4] we have to add 4 and add 4 again 2*4

[@asmiachiproduction]

If only if this video exists back in 2017, I would have excelled my programming paper. Thanks for the great content.

[@abbikgg3992]

@jw72jswu728uwj You don't know his circumstances. Maybe he dropped and coming back at it again. Mind your own business.

[@preetimadas3517]

It will be a[4].... And sir you are amazing..... I m literally getting to understand C learning from u....

[@priyankarodda1943]

Excellent Teaching I get clear about pointers 👏👏👏👏👏👏👏

[@sudipsen3677]

Nice explanation sir ❤️ really amazing .Thank You

[@creatorsayanb]

I'm looking that so many comments are a[4]. But p=&a[2] which means the base value of a[2]. When we write p=p+2, then base value will added with 2. and the output of p will be a base value only. Not a value like a[3],a[4] etc.

[@samrudhshetty9334]

your totally correct bro. my brain was rotting reading the comment sectiom

[@ajmalkhaniit]

Index will be 5 bz pointer contains third address of array and we 2 in this so pointer will move 2 position in forward direction

[@EyeNeo]

Index will be the p[4] which is actually the fifth element of the array.

[@TEeducation]

'P' will point the &a[4] of the array, that means i will point he 5th element of thee array.

[@emperorisalive]

The video explains pointer arithmetic, specifically how adding an integer to a pointer moves the pointer forward by that many positions in the array. It provides examples and explains the underlying memory layout. Key moments: 00:00 Understanding pointer arithmetic is crucial in programming. Adding an integer to a pointer moves it to the next memory location, not just by the integer value, due to memory allocation. -Pointer arithmetic involves moving pointers to different memory locations based on integer additions. -Explaining the concept of adding an integer to a pointer using a practical example with array indexing. -Detailing the memory allocation and the impact of adding an integer to a pointer on memory addresses.

[@080_cse_sanjaykarthicks4]

The answer to the h.w qn is 4 as first the pointer pointed to the index 2 and p=p+2 moves 2 positions to the right, and so now the pointer will point to index 4,i.e,p=&a[4]

[@nawalazhar]

please add more topics! i love your explanation style!!

[@otetumooluwaseun3948]

As p contains the address location of a[2] p + 2 will be a[4] ie the fourth index of a

[@ankitaverma2271]

So the index of the array after this operation is p=a[4]. Sir please let us know whether it js the right answer or not?

[@QuotationNation]

right

[@Tanzimhossain2]

6:38 a[2+2]= a[4]

[@wastetanz]

this was so clear! thank you for this

[@adityathakur8951]

Abee

[@tamimurrahman619]

p=&a[2]------->address of array 1008--------->elements position is 3rd in array; =>p=p+2=p+2*4=1008+8=1016; -------->which location is address of array a[4](1016)---->elements position is 5th in array.....

[@raktimmandal2476]

Initially p has address of a[2]. And "p=p+2" means two shift forward from initial address. So now - P will have a[4]. because 2+2=4.

[@achugh52]

pointer p will have address of p[4] hence point to p[4].

[@himanshuranjan657]

The explanation is like butter

[@AshishKumar-rb1gw]

Programming language is very good and practice with me and improve skills thinku you so much your practice white

[@SarthSanjayJoshiBEE]

The index of the array pointed by the pointer p will be a[4]

[@shreyasingh222]

Thanks for such great explanation ....

[@twiz8859]

Century complete now second century on. Can we say 6:00 p+3*4=Base address+next Element*total byte of that element.

[@shaireenwaheed6492]

Sir ans is Base add a[0]+2*4 And Index 2

[@RAVIVERMA-zy3vs]

Lets consider the base address is 1000 and currently the pointer is at 3rd element which means 1000+4+4=1008 is equal to & a[2] and we have to add 2 to it p=p+2 means 1008+2*4=1016 Which is nothing but & a[4] so this is the Answer...

[@vaibhavsharma9298]

Amazing video 🙆‍♂️

[@shivamrawat4289]

HOMEWORK QUESTION we will get index 4 i.e.a[4] --(EXPLANATION)------->>>>>suppose we take &a[2]=1000, so according to question (p) is equal to 1000 and if we perform p=p+2*4 as earlier explained in the current video , we will get p=1008 and each element of array ocupy 4 bytes of memory , so definetly after reaching from address 1000 to 1008 we have moved two index value forward means from a[2] to a[4], means from index 2 to index 4. So final ans is we have reached a[4]. hope you all understand :) .

[@devsutong]

why did the instructor says that we should multiply by 2 by 4 in 5:40

[@shivamrawat4289]

@@devsutong bro simply we can say it is the formula to perform such things and practically if we do this question on compiler same output we get so we can say that we have understood which formula compiler use to perform such functions .

[@devsutong]

@@shivamrawat4289 ok now i understand, good explanation by the instructor but his English is very misleading

[@nizammalik2148]

Amazing explanation.

[@Perceptionz_Sound]

Great video.

[@D-Coder440]

Thank You Soo Much

[@ashishkumarpal380]

Initially p have &a [2] and after p=p+2 address will be shift two index right so ans is &a [4]

[@tejparmar3440]

Initial index value of p=2 and after adding 2 it will become p=4

[@venkateshpulukuri4832]

in writing of address ,p=p+1*size of the data type ;is better i thought

[@jakemichaelwilson]

Thanks again for the videos. At 5:05 I'm confused why the video shows p=p+1 when the correct way is p=1000+1x4? Is the prior the way how it should be written in C? I already watched the following video as well. It would clear things up if I understood why it is important to understand both math concepts? Which one is the code format for C?

[@clashbegins2063]

its only p+1 not p+1*data type

[@maxcanten2922]

P points to the array a[4] And index will be 5

[@tayyab.sheikh]

H.W problem : p = &a[2] ; p = &a[2] + 2 ; ❌ p = &a[2 + 2] = &a[4] ; ✔️

[@mokkalapradeep7290]

please make a videos in sorting techniques and some more programs on patterns it is important they test us logical knowledge

[@MuhammadAbdullah-wx1ev]

here a[2] means third element so p+2 wil shift the pointer to the fifth element so the final answer will be p=&a[[4]

[@engineer7857]

Thank you for this wonderful job. 😀

[@nehajaiswal3942]

Best explanation ever

[@48_subhambanerjee22]

answer to homework question: it will point to a[4].. that means, 5th element in the array

[@HopeNHopes]

The answer is a[4] that is the fifth element of the array;//

[@KumarRavi_25]

You are Doing a great work❤️❤️

[@manavbabber5454]

Please upload the videos of data structure topics including stacks,queues,heaps,linked lists etc

[@HinaFirdaus]

4th index or 5th element 4B base address then 1016

[@techys4335]

pointer will point index 4 i,e 5th element of an array

[@nuralyazafira1960]

answer p will point to the fourth elements so p=&a[4]

[@aatmprakash]

please make video on MICROPROCCESSOR 👍👍👍

[@anandharsh1773]

thanku sir ur great .........

[@TheRedTeam]

Fried my brain. Good night.

[@jeedikantivenkat7814]

Index of array will be 5 Pointer will point to a[4]

[@andiespeg1897]

Is element and index the same... If not... It will point to element 5... Index 4...

[@CheapPhysics]

The index is 4.. And the memory location is 1016.... (Say 0 index has 1000 memory location)

[@priyaupwanshi8063]

Index = a[4] after p = p + 2

[@zainabbohra2915]

Amazing sir😎

[@true4189]

Thank u

[@castiel0504]

I think the answer is p=[a4]...Because pointer shifts 2 places in the right direction.

[@akhil9967]

If initial address is 1000 then 1016 is the location that pointer points to.

[@mouneshdb9211]

a[4] or 5th element of array

[@rashmisharma9397]

P=p+2 as you earlier said that we have to multiple the memory byte the int is taking so why we are not multiplying 4 to 2

[@java_shaileshkushwaha878]

Because p=p+2 is also equivalent to p=p+2*4 but here i do explicitly but compiler do implicit Internally compiler do same as your thought but we not use this type calculation it is time consume working same

[@pranavhendre6209]

the answer :-a[4];

[@negativedignity8994]

saying p = &a[2] and after the operation p = p + 2 the answer will be p = &a[2 + 2] === p = &a[4]

[@kunaii_cs]

Its the fifth elemnt or p=&a[4]

[@myviews8991]

Index of the array remains same as we are incrementing the address in the pointer by 2 but index of the array was never changed......

[@DeepakKumar-fd4qu]

Sir please make a video on structure and union as soon as possible please huge request to you

[@sr-sunny-raj]

index after operation will be -: 4.

[@compangit1524]

The index will be at the 5th elements of the array.

[@raghavan8594]

Sir,what if, initially when 'p' points to final element??

[@akshitarora470]

You will be able to view the address next in line (4 bytes separated) , but obviously doing a *p for that memory location will result in an error.

[@sandraokafor5380]

The answer is a[4]. I love these videos a lot, they are quite explanatory. Thank you.

[@amrnassar8417]

thank you

[@kunjd26]

Answer is: a[4]

[@GurpreetSinghkalyan]

Excellent