Polar Plot: Steps, Drawing Procedure, and Solved Example 1

[@EngineeringFunda]

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[@77-siddharthsattyam24]

if i will score good in cs i will definitely share this in my group you doing good job dholakiyaaaaaaaaaaaaaaaa ji :P

[@EngineeringFunda]

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[@tistic]

at 13:19 there is a calculation mistake, tan^-1(root(2)) = 54.7 not 60 it is root 2 not root 3

[@roshni9320]

Exactly

[@sugamrajput7719]

yaa, you are correct the value of tan inverse of root 2 is wrong but the overall phase is 180.01 degree. The phase is correct.

[@emeruomemmanuel9675]

You are correct

[@mohdmustakim4765]

Thank you Sir. Very good explain polar plot.❤️❤️❤️❤️❤️❤️.

[@EngineeringFunda]

Love and happiness of students is my ultimate goal, God bless you 🙏, keep learning and keep progressing.

[@vaishnaviwani2003]

@@EngineeringFunda -jw^3 kyu liya sir in step 4

[@DeepakGupta-xy6xb]

This video is really helpful for me. Thank you sir for this video❤️

[@EngineeringFunda]

Love and happiness of students is my ultimate goal, God bless you 🙏, keep learning and keep progressing.

[@jealouseggs5619]

THank you so much fo rexplaing the steps as well as the reasoning behind it!!

[@EngineeringFunda]

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[@shivam_08gamer]

Thanks sir i have a few doubts regarding it but now you have answered it well. Thanks a lot 🙂👍👍👍

[@EngineeringFunda]

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[@rohitkimar4440]

Best explaination !! Crystal clear✅

[@EngineeringFunda]

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[@DamnSonImGood]

Sir is the negative sign necessary in step 4

[@ramdasmendewad2948]

Sir your contribution for us very helpful

[@EngineeringFunda]

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[@mrx.0000]

why's there -jw in the 4th step?

[@baherualemu7129]

you are excellent teacher !!!!

[@EngineeringFunda]

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[@priyankadhawale7438]

Wasn't there a mistake in step three? It was omega /2 so 90/2 so it has to be 270-90-45 right?

[@thriller_clips3795]

Omega isn't equal to 90⁰, omega is substituted to infinity. So it's infinity ÷ 2 = infinity. Tan-¹ infinity = 90⁰

[@onlyhumanity6148]

Bahut badiya sir♥️♥️♥️

[@EngineeringFunda]

Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

[@onlyhumanity6148]

@@EngineeringFunda sure sir u are doing hard work. Please keep on providing quality and clear content. I have subscribed your cahnnel and will suggest my friends too to learn from here.

[@EngineeringFunda]

Your welcome 🙏

[@basharali746]

Sir can u pls explain where is - j in step two, how to write magnitude =w

[@avanigajallewar1751]

nice explanation!! Thanks Sir

[@EngineeringFunda]

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[@Abhi-kw7tp]

Hard work sir🔥🔥🔥

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[@empress_of_beats]

Sir jcube = -1 . Question mai (jw)^3 diya hua hai. Then sir in step 4 , why have you taken -w^3 , it will be either -w3 or j^3 w^3

[@Area-fd8ht]

First thing jcube is not -1 it is -j Because j=✓-1

[@sourabhkoshti978]

J. J. J=J^2=-1 and J×-1=-J

[@Area-fd8ht]

@@sourabhkoshti978 chal na lawde ladki dekhi nhi ki gyaan chodna shuru..

[@sourabhkoshti978]

@@Area-fd8ht so what are you doing basically

[@Area-fd8ht]

@@sourabhkoshti978 ha me bhi whi kar rha tha.. Gyaan hi bacha hi wese bhi chodne ke liye..😂

[@EngineeringFunda]

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[@rudraaworkout7750]

nice explanation sir

[@EngineeringFunda]

Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

[@edwinchigozie215]

This is a gem

[@neeleshranjan7827]

Great sir

[@EngineeringFunda]

All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏

[@GSPmediaO28]

TQsm sir😍 for sharing

[@EngineeringFunda]

Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏

[@campus6674]

sir you did a mistake in step 4 you take -jw^3 where this negative sign come ?

[@anuragojaskar5656]

Sir the phase angle which you have taken of w^3 as 270 degree while finding polar form .how sir?

[@surendrakverma555]

Thanks Sir 🙏

[@EngineeringFunda]

Most welcome

[@vrajvaghela9272]

12:33 why there is -3 is not considered for calculating magnitude and why there is 3 power of root 2

[@Akash-nl3oz]

4:38 pe sir calculation me mistake hai omega^3/omega hoga coz omega^2 jab sq root chodega to sirf omega bachega. Par ans fir bhi infinite hi aayega shyd so np.

[@EngineeringFunda]

It is correct dear

[@Akash-nl3oz]

@@EngineeringFunda ohh yes sir I just noticed dono sq roots se ek ek omega niklega, sorry.

[@GokulGokul-iz2to]

Thank u very much sir

[@EngineeringFunda]

Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏

[@shubhamkumar5081]

Sir I have a doubt you wrote jw^3=jw^3=270 But sir Jw^3=-jw^3=-270

[@yennamveni3790]

As it is type 0 doesnt the graph start from the other side

[@AbhishekSingh0216]

Sir why have you written -jw cube in step 4 the sign should be positive?

[@DamnSonImGood]

I thought of It too

[@AbhishekSingh0216]

@@DamnSonImGood because there is a negative sign in a denominator which is taken to numerator 👍

[@annusworld3]

In step4 sir you have written -jw^3 but in question there is no (-) why did you kept that. Clear my doubt sir

[@EngineeringFunda]

In question it is (jw)^3 = j^3×w^3 Here j^2 = -1, So (jw)^3 = -jw^3

[@annusworld3]

Thanks sir😇

[@vijayprakashee23gec-bhoj75]

@@EngineeringFunda sir, some where I read j^2= -1. Is it wrong sir?

[@EngineeringFunda]

@@vijayprakashee23gec-bhoj75 I have already said that J^2 = -1

[@yashpreetkaur2042]

@@EngineeringFunda sir at 1:47 how it is √1 + w² where j² = -1 please explain

[@AnkurGupta-nd2el]

why you have taken w^2=2 as w=+root2 only? what about -root2

[@princexyz8489]

awesome...❤❤❤

[@EngineeringFunda]

Your welcome

[@srupoemwriting8287]

Sir how you calculate w=√2 it's 3√2

[@nikhilduggani3766]

Sir , kindly explain the concept of polar plot and how it decides the stability

[@EngineeringFunda]

See it in playlist, I have already explained it.

[@230-saikumar8]

Sir how should we say direction of polar plot??

[@TheVistaIdea]

Sir , at intersection point if the magnitude is 0.66 , then why have u taken 0.66 point in left hand side of graph

[@EngineeringFunda]

You see the angle (phase) here, it is 180.

[@TheVistaIdea]

@@EngineeringFunda Ok Sir, Thank you very much for videos

[@pranayjain._]

@@EngineeringFunda sir but, w^2=2, so omega should be +- √2 right ??, Why did you take only √2?, Even w=-√2 could be taken

[@EngineeringFunda]

@@pranayjain._ frequency can not be negative

[@pranayjain._]

@@EngineeringFunda Thank you sir for your time ❤️

[@nksnikhil2001]

where is the '-j' in the second step

[@ajaykamal6883]

Sir solve the question K/[s(1+jwT1)(1+jwT2)] Plz sir solve the question 🤗

[@EngineeringFunda]

In my playlist of control engineering, I have explained polar plot for type 1 system, just go through it. This is that example only.

[@aravindhengg9753]

hi sir, when i calculated i got -0.66 and not 0.66

[@monalisasharma3616]

why only +ve root ??? why not w=-root2?

[@SurajThakare0]

Sorry to say but I couldn't understand a thing from step 4 and onward for past three videos that are type 0, type 1 and this.

[@riii_3]

There's "-" in 4rth step because he didn't write j^3 and wrote"- j"only he put j^2 = -1 and wrote only j

[@kkjj4937]

how do we calculate that term using matlab

[@MuhammadQasim-kw1er]

why 0.66 on negative real axis???

[@Mk-xc7gh]

Why - sing sir in step 4. ???

[@dhakshayini.tdhaku1079]

In step 4 :-jw how it will come

[@pradeepshetkar7264]

Step 2 is not clear as well as step 4.. Number of people are asking in the comments. No response from you...?!

[@SahiilVadera]

√2 kidhar se aaya

[@shakilstark6649]

I think you need to prepare well before explaining this topic....I think you are not clear about this topic..so dont repeat this again

[@Anonymous____________A721]

No need of your advice

[@shakilstark6649]

Jalwa😅😅😅@@Anonymous____________A721

[@नमस्कार-ड7त]

Thank you Sir 🙏.

[@EngineeringFunda]

All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏