Position and width of the fringes in interference | Wave Optics 12th Physics Term 2

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शिक्षक और सड़क एक जैसे होते है खुद उसी जगह रह जाते है मगर उस पर चलने वाले लोग और शिक्षक के पढ़ाए हुए बच्चे बहुत आगे निकल जाते है

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This short video is also best for revision in exam time:

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Awsm as always.... ❤️🔥

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Thanks 🙏🙏

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Bahut badhiya sir. I liked your explanation very much. Aap bahut achha samjhate hain.

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Thank you sir ❤❤

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❤🎉

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Derivation syllabus me nhi hai

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Thanks sir

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10:08

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Sir 💫 thankyou

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Awesome 😎

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Tqquuhhh sir

[@sailendranathpal8]

Sir for *dark fringe* path difference= (2n-1)lamda/ 2 But in few videos in KZbin i am seeing that they are doing ,for dark fringe path difference= (2n+1)lamda/2 Which one is correct?? Sir ???????????????

[@aravjee8982]

both are correct, first case n = 1,2,3,4...... second case n = 0,1,2,3,4......

[@JAI_BHIM_JAI_BHARAT]

Depends upon expression you take

[@aryansagar2746]

Thank you sir

[@modenvilla63]

22:11 sir waha pr bright fringe ki width same nhi aa rahi

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1:11 kaun hai vo

[@EthicalAthiest]

Why in case of constructive interference xd/D should be equal to nλ

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waaah sir wah

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Sir 🙏🙏 Hamare book mai dark fringe ki path difference (2n+1) Lamda/2 likha hai

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Ye video dekhnaai kai baad lagta hai apunnn hi bhagwaan eeech...

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Sir, semiconductor ka video kb aayega

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Coming soon 🙂

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@@PHYSICSwithUmeshRajoria tqquuhh sir

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What is fringe 🧐🧐

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First

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