Power Dissipation in a Resistor

[@LolanBadeauxMakes]

I have watched so many videos on resistors and ohms law. your the first person to bring me straight to the math in a way i absorbed it immidiately and in the order in which i needed to understand it clearly. thankyou so much

[@LolanBadeauxMakes]

Straight to understanding how and why series and parallel determines whether your disipating because of voltage or amperage.

[@danialraja]

Thank you so much sir. This video has really made me understand the concept of power dissipation. My Indian teacher was teaching me this today and I didn’t understand a word he said. I don’t know why they say India is projected to be a superpower when people can’t even understand them.

[@sathish5470]

lol

[@haroldingco3552]

thanks this is much better than the zoom class for 4 hours

[@quizsection]

Thanks for catching the typo. I would very much appreciate it if we keep the comments G-rated. Thanks!

[@quizsection]

Yes, as soon as I can get back in front of my lecture cam. I'm in the middle of moving, so give me a couple of weeks to get on it. Thanks. In the meantime, let me just say, to find the power dissipated in a resistor, you must first know either the voltage across the resistor, or the current through it. To find either of these, you will probably need to use a combination of Kirchhoff's equations, and equivalent resistance of parallel resistors...

[@frogger5687]

Watching this video at 1.5 speed was much better than regular speed.

[@Exodus9874]

even at 2 speed is still slow asf

[@latashiasmith6324]

Thank you.

[@chherryflavored]

omg i watched it at 2.0 speed and it was still too slow

[@godminnette2]

@@chherryflavored This is why you get the chrome extension that allows you to watch youtube videos at faster than 2x speed. I watch many videos at 2.5x

[@chherryflavored]

Godminnette2 awesome!! Thanks :)

[@quizsection]

I'm glad it works for you. I'd love to put together some video lessons, although you may have to wait a bit, I'm afraid. I'm in the middle of moving, and currently do not have access to my lecture cam. Stay tuned though; I'm hoping to get back into it ASAP...

[@quizsection]

Yep, that's correct. And yes, I do still check this. My move this Summer has been complicated by a bunch of things, but now I FINALLY have a new place to set up shop. I should be back to videos next week!

[@agogirl88]

Thank you sir! That was really helpful. I finally completed my Electricity assignment, which is due tomorrow 😀👍👍

[@janetlockett]

Oh my goodness, thank you so much for this video! You are a life saver. UCSD Physics 1B Electricity and Magnetism.

[@quizsection]

+Janet Lockett I've had some good times down thataway, but getting around can suck...every street is named La Jolla something-or-other! :P

[@taeyang]

+Janet Lockett Lol I'm taking 1B right now

[@joharinawaldeck1092]

To whom it may concern We are developing an online programme for the South African Department of Higher Education and would like to include your video in the unit on Electronics. Please also indicate if all your videos will have the same permissions. In order to assist learners who do not have regular access, all the media will be loaded onto a learning management system for download to a device. I would, therefore, like to request permission to download your video from KZbin to include on the LMS. We will provide full attribution to the video with whatever details you require. I look forward to hearing from you. Many thanks,

[@forthebuttercups]

Thank you so much, my physics professor didn't explain any of this!

[@mrsyed2376]

Rachel S. somewhat the same problem just mine did not explain a thing but thinks he did

[@quizsection]

Hahahahaha! Nah, I'm just glad I can help ;) Let me know what other questions you might have though. I'm happy to do follow-up videos too!

[@hadiaamin1466]

Its was an amazing video...just wanted to ask if there's any difference in the usage of the 3 formulae for power...do they all arrive at the same result?

[@CourageousCoos]

Hey man don't know if you still check this, but for total power in a parallel circuit is it just Pt=P1+P2+P3 etc?

[@lssgrs]

what is the relationship with dimention of a resistance and the power dissipation?

[@quizsection]

You're asking for a dimensional analysis? Watt = Joule / Second = (Joule / Coulomb) (Coulomb / Second) = Volt * Amp = Volt * (Volt / Ohm) = Volt^2 / Ohm or... Watt = ... = Volt * Amp = (Ohm * Amp) * Amp = Ohm * Amp^2

[@MexterO123]

Thanks man, so all ways are equivalent? You just use what you know and use the appropriate equation.

[@badio310]

How do you know when to use the symbols for Amps and Watts. Im confused

[@felixthecat2589]

Amps are for current, Watts are for power. The power dissipation he is calculating here is to determine how much heat those resistors are going to put out when you connect the whole circuit together. When you buy those tiny resistor the usually can only dissipate 1/2 or 1/4 of a Watt, they are called current resistors. If you want a resistor to dissipate watts (in our case, heat) you need a power resitor, they can go to values like 5w or 10w and so on... Im not a specialist but I think this is the correct explanation! Please someone correct me if Im wrong! Ill be happy to learn some more!

[@Headshothorror4488]

I have a resistor, how do I find watts of it and ohm and volts ? I. need buy another one same ? Also how do u know if it fried black

[@quizsection]

You have an actual resistor? If so, it typically has color codes to indicate the resistance and the wattage...

[@zippycraftmc]

This was incredibly helpful. Thank you.

[@seddiklamperoug7712]

man I have a question I need an answer quickly .... how calculate a powerdissipation (max) in a resistor RI think it's dp/dR but I don't really know how

[@quizsection]

+Seddik lamperoug In theory, there is no maximum dissipation for a resistor. Any given real resistor has power ratings, yeah, but mathematically there shouldn't be a limit.

[@seddiklamperoug7712]

quizsection thx man

[@hamzahtalib5360]

thank you so much sir..........i have now solved my assignment due to this

[@billwilliams6338]

QUIZSECTION, /// if a lamp bulb draw .15 amps and another lamp bulb draw .25 amps how do you find the percentage of current draw between the two different lamp bulbs? what is the formula .15 amp lamp bulb draw less current compared to .25 amp lamp bulb by what percentage?

[@anthonydask7659]

man you got neat hand writing haha

[@emmanueljaison5547]

Hello buddy, my question is How power and resistance are related..Can we say power is directly proportional to resistance or inversely?

[@thaifannaticzz1156]

I have a question Sir, Are all formula for Power Dissipation are applicable to Parallel Circuit? Please reply to me ASAP

[@cDynasty001]

Can you please explain how to do this in series, but with three voltage sources in between the resistors?

[@quizsection]

Hi there :) When you have voltage sources and resistors in series, the relative placement of components doesn't matter. Circuit "V1-R1-V2-R2-V3-R3" has the exact same properties as Circuit "V1-V2-V3-R1-R2-R3." Each component shares the same current, which is calculated as the sum of voltages in the loop, divided by the sum of resistances in the loop.

[@brendasmith2944]

ffs you didnt do a perpindicular circuit! runed my day cos this was a good video!

[@talktoeric]

What would be the wattage of a resistor with the description R-US_0204/2V?

[@quizsection]

+Eric Hogan pikirsa.wordpress.com/2011/08/01/eagle-component-package-sebuah-catatan-pencarian/ If I'm reading this page correctly, it's a 1/8 W resistor. The 0204 refers to the dimensions--0.2 x 0.4 cm--and the dimensions correlate with the power dissipation. 1/8W resistor (PTH)Various R-EU 0204/5 5 mm grid 1/4 to 1/2W Resistor (PTH) Various R-EU 0207/7 7.5 mm grid 1 W resistor (PTH) Various R-EU 0414/15 15 mm grid 3 W resistor (PTH) Various R-EU 0617/17 17 mm grid 1/16 W resistor (SMT) Various R-EU R0603 Typical power for 0603 size 1/4 W resistor (SMT) Various R-EU R1206 Typical power of 1206 size 1 W resistor (SMT) Various R-EU R2512 Typical power for 2512 size

[@davidg5189]

When you are calculating power across the resistors in series, don't you have to calculate it according to the amps in each resistor :O?

[@quizsection]

Well, you don't have to. With a resistor, P = I^2 * R = V^2 / R. You can calculate it either way, but the configuration of the resistor does make one or the other methods easier to calculate. When the resistor are in series, they have different voltages, but the same current...so P = I^2 * R is the easier calculation. When the resistors are in parallel, they share the same voltage, so P = V^2 / R works better.

[@davidg5189]

quizsection thanks :-D

[@rickinio]

Thank you for posting this video!!! :D

[@CourageousCoos]

Thanks for the swift reply! I appreciate your videos, they really do help.

[@NIRMALABD-gn7bk]

If it is series and parallel means wat can i do sir?

[@VictorWilliamsAthens]

Thanks! Helped a lot with review!

[@suprateekat5338]

Very clear and concise !!!

[@aldeguerrealingo5251]

viewers should have a prior knowledge on the values of voltage and current in series and parallel circuit in order to understand the power dissipated... otherwise it would be difficult for the topic to be understood..

[@dungdaongoc]

So if i have a 6ohm resistor and 2A flowing through. how much energy would dissipate in 5 minutes?

[@pawpad1777]

7200J Power=I^2 *R, R=6ohm, I=2A, hence, P=24W Energy=Power*time, time=5minutes=300seconds Energy=24*300=7200J. the real question is how is that resistor still functioning with all that energy going through it in such short time.

[@wizman619]

LOL, that IS the real question

[@jaysonblazer3552]

why he didnt use the first equation for power?

[@F1NSH3R]

Really good lesson thank you Sr ✅

[@MRYEMAN]

School should be taught this way

[@quizsection]

Happy to help :)

[@youngbuck5009]

Thanks for the helpful video.

[@RazerRose]

so for every resistor the voltage and current drops right ?

[@justaquestion1934]

current stays the same, voltage drops and power raises

[@snoops121]

Thank you, just the answers i was looking for made clear.

[@mrJoyoboyo]

1. 1pcs R 3 Ohm 2. 3pcs pararel Total R 0.5 Ohm 3. 3pcs Serial Total R 6 Ohm ?????

[@Bktend11]

Perfect explanation

[@brendasmith2944]

what if there were two voltage sources! please! just answer this question i beg you!

[@quizsection]

+Brenda Smith Where should the second voltage source go? Can you send me a picture of the circuit you have in mind? My E-mail is [e-mail]...

[@aldeguerrealingo5251]

nice explanation sir.

[@venoxidegaming1432]

This helped me so much thank you!

[@proteinplanet8345]

Thanks 😊😊 for my help 😘

[@ChideraUwandu]

Thank you!!

[@kingpin456]

or for series to solve i just do v divided by r....

[@mickdundee3411]

Thanks man nice video

[@aramisstavridis6449]

very helpful. thank you

[@abulfazal5044]

Sir ur American ???

[@joshuaofficial1708]

I need help

[@ronyrocks4539]

Vey helpful

[@surajpandeysurajpandey1850]

good

[@quizsection]

hahaha...Thanks.

[@joelhaddad9434]

skip to 4:10 thank me later

[@patil-abhishek]

V2/r

[@ilzul12]

Awesome explanation!

[@ObsishOroMan]

10q

[@kanchansarve3929]

Very bad