Pressure of an Ideal Gas | KTG Derivation | YOLO JEE Advance Physics with Vikrant Kirar

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[@CrashUp]

Thanks a lot :)

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[@notwhite5431]

Good class but in ncrt text book the eq is p= 1/3nmv². You have written p=1/3nmv²/v. 🧐

[@chiranjibirout6814]

Excellent

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[@CrashUp]

🐛

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