Probability Tossing Three Coins Tree Diagram At Least 2 Heads

#globalmathinstiute #anilkumarmath CORRECTION: for at most 2 Heads we should have included TTT condition also. Please write the corrected answer. Thanks
/ @mathematicstutor Learn From Anil Kumar: www.globalmathinstitute.com
Dependent Mutually Exclusive Probability: • Probability Concepts C...
#probability #CoinsProbability #anilkumar #globalmathinstitute #mpm4 #treediagram
CORRECTION: Last option in Tree Diagram is HHH, corrected later while writing the values in the table.
However, there is a mistake in writing the solution of part c.
at the most 2 heads should have been 7/8
I should have included TTT (no Heads also)
Thanks
Draw a tree diagram to show results of tossing a coin three times.
a. What is the probability of getting 2 Heads
b. What is the probability of getting at least 2 Heads
c. What is the probability of getting at the most 2 Heads

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[@Davide-bl2wb]

The "at most 2 heads" part should consider also the case with 0 heads

[@slayerz2234]

Why??

[@Davide-bl2wb]

@@slayerz2234 I think at most 2 H means any number of heads less or equal to 2. I think it should include the case 0 heads (TTT) together with H u HH

[@radianthd566]

exactly it should be included @@Davide-bl2wb

[@uhjk91]

LOL - Mr AK did say that students get confused by these sorts of questions. Looks like Mr AK got totally confused himself. Well done to all those who spotted this error. Thanks for creating this video AK, just goes to show we can all make mistakes with these weasel word questions.

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Lol

[@OPTIONALWATCH]

I got HHH for the last one, but I get it now. I just hope that in my test, which is timed, I don't run into little mistakes because I have zero time available to look where my mistakes are :-(

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[@narendrasamtani9051]

in the case of at most we count (0,1,2) not more than 2 but fine with 0, so the answer should be 7/8.

[@kanishka4598]

Yes

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yes

[@sarash243]

That's what I think too

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Thanks for appreciation. Another related video: kzbin.info/www/bejne/rIHTqZyLa6eYbbs

[@DK-bt7ln]

I think u wrote the wrong option at 2:57... It is supposed to be HHH.

[@MathematicsTutor]

Ya, corrected later while writing the values in the table. However, there is a mistake in writing the solution of part c. at the most 2 heads should have been 7/8 I should have included TTT (no Heads also) Thanks

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Sir u should take for atmost part c probability will b 7/8

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[@danielhenry2745]

Congratulations for your good, clearly and understandable explanations. My point of correction is at (c) since we are required to find the p(at most 2H) this means including outcomes of {0H, 1H and 2H} thus P(E)=(1+3+3)/8 = 7/8

[@MathematicsTutor]

Yes, that is correct and the CORRECTION has been given in the comments, Thanks

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[@Lillith9008]

for the last question (what is the probability of getting at the most 2 heads), wouldn't 0 heads also be counted in that?

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I think Answer of c is wrong sir.It should be 7/8. Including TTT

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yes

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Thank you sir that is wonderful and i have a doubt on the when a coin is tossed twice.If the second throw results in a head,a die is thrown, otherwise a coin is tossed. That is my doubt sir if sir could explain on this.

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Excellent videos. However does "getting at the most 2 Heads" not also include the possibility of zero Heads, i.e. 0H, 1H, 2H ?

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You could also calculate the number of outcomes then find the number of different permutations.

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For CS students let me help you. It's just a binary (for coins) it's the cases of getting at most, at least & directly getting ones (1').

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