Probability Tree Diagrams : removing items without replacement

[@saraibgui1697]

Thank you so much this was so helpful! I have an exam tmrw and my teacher forgot to tech us this and we need it for the test so thank you!!!!

[@RepublicOfNewEnectra]

Sure this comment was posted a fair few years ago but i also have my exam tomorrow. Wish me luck

[@horrorayaan-1278]

You wrote b instead of w in the last branch

[@lindagamibes6781]

This video just saved my life thank you 🙏🏽😭

[@amankataria1997]

One of the best teachers on KZbin. Thanks!!

[@christianacknowledgement538]

haven't you done it wrong? it says that 2 were taken out, so it must be out of 10 not 11

[@saraibgui1697]

He wrote 11 because at that stage he hadn't taken the 2nd one out. Hope this helps

[@JaneOpondo-qq7qs]

Thanks so much this really helped my daughter

[@angedieka3320]

hello! kind help me here: In batch of 100 screws, a maximum of 3 can be defective. A random sample of 20 screws are taken. How many defective parts are allowed in this sample considering all scenarios probabilities less than or equal to 90%?

[@sselunjogisimonpeter3377]

Thank you

[@i_cee_u]

Oooh, that was easy. Thanks 🎉

[@juanalocken5852]

So, say I have a mixed packet of Sweet Bell pepper seeds that contains equal parts of 5 different varieties, what is the minimum number of seeds that I would need to plant in order to ‘guarantee’ that I’ve planted one of each variety. 80% of them + 1, right?But, what if I had a bucket of seeds?! That’s a ridiculous amount of Bell peppers. So I thought, we’ll, I’m willing to utilize two rows in my seed starting tray. That’s 12 cells. There are 39 seeds in the packet. An equal 20%of each variety (orange, white, purple, yellow, and red) included in the packet, according to Burpee. What are the “odds”, “%chance”, or “probability” (i’ve been thinking about this too long and I’m not even sure which I’m asking for anymore lol) that I will have planted at least one of each variety? This brain teaser has got me stumped. Please and thank you

[@KeybladeWielderXV]

Got my Maths GCSE exam tomorrow and your videos have helped me bump up my grade from a miserable D grade all the way up to a B/A grade! Thank you so much!

[@JoelynUwea-yt5ff]

Is it possible if we can simply again?

[@akandwanahoblessing5051]

You videos are nice

[@muhamadapqoribinmohd.dzulk2261]

can you upload with different number ,I'm still confuse

[@jaydarilar]

thanks bro

[@user-hj2lt2jo3v]

Great work , Thank you

[@she2787]

thanks

[@potatoesmasher4885]

Omg thank you so much

[@tobifalola1146]

Thank you soo much

[@akandwanahoblessing5051]

Send me answers for A box contains 4 pink counters 3 green counters and 3 yellow counters . 3 counters are drawn at random one after the other without replacement . (a) Find the probability that the third counter drawn is green and the first two are of the same color. (b) Find the expected number of pink counters drawn.

[@Lynne.cee15]

call nenna

[@Joy-io3up]

Why did he use 1/3 to multiply at 2:26 though. Pls help 😭😭

[@Lynne.cee15]

1/3 is the same as 4/12 when simplified

[@LucyNamukwaya-eo1jm]

U took out one with no replacement yet the question says two

[@Bananaduck133]

He takes one out, represented in the first 3 branches, then in the second branch, he decreases the denominator, symbolising he has already taken out the first ball.

[@Elliante]

indeed

[@monarmatutul4371]

i konw very simple method =4/12*8/11+4/12*8/11+4/12*8/11 =8/33+8/33+8/33 =8+8+8/33 =24/33 thats it ☺☺☺

[@skstar3855]

You wrote B instead of W why hmmm???

[@George-Smith]

Same doubt here

[@skstar3855]

Bla bla bla BORING you seemed a bit worried too cuz the pen slipped from your hand 🤣🤣🤣

[@potatoesmasher4885]

Your just dumb at math lol

[@janaijohnson3711]

THANK YOU