Problem 3 on Deflection of Beam (Macaulay's Method) | Deflection of Beam

Problem 3 on Deflection of Beam (Macaulay's Method) | Deflection of Beam | Strength of Materials |

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@pravinkumaryadav1563 3 жыл бұрын

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@harshilmishra2894 5 жыл бұрын

Sir you are simply awesome.......... Thanking you

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@spreaddeenislam4463 4 жыл бұрын

Tnku v.much sir i have alot of problm in this topic but now it is clear

@ImpactAcademyOfficial 4 жыл бұрын

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@Dulangajayananda 4 жыл бұрын

Thnk you so much sir i have got that well

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@ashokjn3511 5 жыл бұрын

Thank you so much sir .

@ImpactAcademyOfficial 4 жыл бұрын

@vasachisenjubean5944 5 жыл бұрын

Why did u consider a dummy load?

@ImpactAcademyOfficial 5 жыл бұрын

That's the step which should be followed while forming equation using Macaulay's method if udl is not in contact with anyone of the support...👍👍👍

@iaincrawford5472 5 жыл бұрын

Excellent!

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@agbomoses9851 4 жыл бұрын

Good one

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@pramodrauniyar2099 5 жыл бұрын

What will be boundary condition for slope at support sir

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@spreaddeenislam4463 4 жыл бұрын

Sir here also maculays bracket used but you not use it so explain it

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@kausthubvemuri9902 4 жыл бұрын

Sir what is the condition for maximum deflection of the beam for the above problem

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@32keshav11 5 жыл бұрын

sir why we are continued that udl

@ImpactAcademyOfficial 5 жыл бұрын

Bcoz udl should have contact with atleast one end support,hence it was extended...👍👍👍

@sithiraweerasinghe977 4 жыл бұрын

What is the mean of I???? Moment of inertia or second moment of area. Sir you put second moment of area equation for that?. And I want to know second moment of area and moment of inertia are same ?????

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