Problem Solving Approach: Orgel Diagram | Electronic Spectra | Transitions | CSIR-NET | June 2019

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All 'Bout Chemistry

All 'Bout Chemistry

4 жыл бұрын

This video is a part of Problem Solving series, in this series you will get videos which will just contain solution of problem and how you can approach them.
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#CSIR #OrgelDiagram #Spectra #CSIR #NET

Пікірлер: 28
@shyamaleegogoi143
@shyamaleegogoi143 4 жыл бұрын
Sir, please explain how Mn2+ undergoes spin allowed transitions ????
@sandhyatandale448
@sandhyatandale448 4 жыл бұрын
Thank you so much
@kiransingh1004
@kiransingh1004 4 жыл бұрын
Thanks sir
@PriyaPriya-se9sf
@PriyaPriya-se9sf 3 жыл бұрын
Sir How to ni+2 broad band this are not show jahn teller distortion
@chemmgic2811
@chemmgic2811 4 жыл бұрын
🙏🙏
@gopalakrishnanr8192
@gopalakrishnanr8192 3 жыл бұрын
Ni(2) there is no jhon teller distortion then it will give 3 sharb band, but they are telling 3 broad band, why?
@abhishekmishra9010
@abhishekmishra9010 4 жыл бұрын
In the given option, Ni2+ exhibits broad bands but there is no John-Teller distortion in Ni2+ then why option (d) is correct... Plz explain it... It should give 3 sharp bands
@AllBoutChemistry
@AllBoutChemistry 4 жыл бұрын
The reason for Broad band in Ni+2 case is the change in symmetry of the molecule upon transition. For ground state Ni+2 we have 6e in t2g and 2e in eg state. Which makes symmetrical electron density along the axes. Now consider first transition from t2g to eg orbital, making 5e in t2g and 3e in eg orbital, thus creating asymmetry in electron density along the axes, thus the symmetry of molecule will be disturbed or distorted which will be depicted in terms of broad peaks.
@AllBoutChemistry
@AllBoutChemistry 4 жыл бұрын
Similar explanation can be done for other transitions as well
@abhishekmishra9010
@abhishekmishra9010 4 жыл бұрын
Thank u
@shafnat3262
@shafnat3262 4 жыл бұрын
@@AllBoutChemistry then the first transition should give a strong band....here all the 3 bands are broad...why so??
@rudranilghosh2713
@rudranilghosh2713 4 жыл бұрын
Sir can you make a detailed video on tanabe sugano diagram in youtube /unacademy free /unacademy plus? It'll be helpful for msc purpose.
@AllBoutChemistry
@AllBoutChemistry 4 жыл бұрын
Ok Rudranil I will try to make it soon, 👍
@jamaladyan3487
@jamaladyan3487 4 жыл бұрын
Sir aap u academy pe online coaching dete ho for csir
@AllBoutChemistry
@AllBoutChemistry 4 жыл бұрын
Yes
@kundanlal3328
@kundanlal3328 4 жыл бұрын
Sir please make video of physical spectroscopy
@kundanlal3328
@kundanlal3328 4 жыл бұрын
Please make a video on main Group elements
@jeerusrinivasarao1173
@jeerusrinivasarao1173 4 жыл бұрын
Sir I want numerical explanation for jam from all topics and plz help me if you can
@AllBoutChemistry
@AllBoutChemistry 4 жыл бұрын
I will try to make videos on that
@shaileshankalgi1168
@shaileshankalgi1168 4 жыл бұрын
There is no given the complex is tetrahedral or octahedral
@PriyaPriya-se9sf
@PriyaPriya-se9sf 3 жыл бұрын
Sir pls explain me
@Mounikaseshu
@Mounikaseshu 4 жыл бұрын
Y Co2+ give only 2 signals but u mention 3 signals in orgel diagram and u didn't explain it also...directly u explained Cr3+ as 3 signals..can u please tell that
@AllBoutChemistry
@AllBoutChemistry 4 жыл бұрын
Cr+3 is the one which gives 3 signals and it violates the statement given that's why I just talked about it.
@Mounikaseshu
@Mounikaseshu 4 жыл бұрын
@@AllBoutChemistry y Co2+ give only two signals y not 3
@AllBoutChemistry
@AllBoutChemistry 4 жыл бұрын
@@Mounikaseshu in orgel diagram of Co2+ you can see the cross point, where A2g and T1g(P) cross each other, so the transition happens to be from T1g to T2g and T1g to A2g or T1g(P) Due to cross point last two transitions are not descrete and they appears to be same. Giving only two peaks in electronic spectra
@Mounikaseshu
@Mounikaseshu 4 жыл бұрын
@@AllBoutChemistry tq sir
@rameshk9271
@rameshk9271 4 жыл бұрын
@@Mounikaseshu Co+2 is d7 complex.. It has 5e in t2g and 2e in eg. In this only 2 transition are spin allowed 3rd transition will be spin forbidden
@brijesh_shah
@brijesh_shah 4 жыл бұрын
Thanks sir
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