Problem within a problem

[@JulesMoyaert_photo]

If I had a teacher like YOU! Always so clear! I am almost ashamed to be unable to solve it, though SO SIMPLE!!!

[@harrymatabal8448]

For ever, short, simple and to the point unlike some of the other videos.❤

[@TPE_Mitchell]

If I had a teacher like him. I would be far in life

[@LoveAllMyFamily]

No you won’t

[@TPE_Mitchell]

@@LoveAllMyFamily I would be in NASA or on the Moon

[@Caleb-DH]

😂

[@rui2565]

Yeah, he is good

[@navjotsinghdhiber3454]

I had a teacher like him. But he was very strict and used to best children who didn't study. I beat me too. I used to fail in maths till 7th grade every time successfully. But when He started teaching us. I got 56/100. I was shocked. Then in second exam I got 83/100. In finals I got 80/100. Many students in my class had perfect scores. He was a phenomenal teacher. It is because of him I am studying Physics Major in College. A good teacher can work miracles.

[@claudio_isen]

greate Teacher !

[@murdock5537]

Simply great, this is awesome, many thanks, Sir!

[@mrhtutoring]

My pleasure 🙏

[@JakubS]

Good video

[@nddmais191]

Very good.

[@hermansims2296]

Outstanding!

[@programmieraufgaben8391]

nice solution✌

[@grey698]

sir can you please please teach these chapters. I am fond of your teaching style and it is quick to pick up as well. I am in grade 12th from India. *this is priority wise order 1) CONTINUITY AND DIFFERENTIATION 2) RELATIONS AND FUNCTIONS 2) DIFFERENTIAL EQUATIONS 3) INTEGRALS 4) VECTORS 5) INVERSE TRIGNOMETRY

[@joshuathomas6326]

How does he write with the chalk like that…standing in that position

[@mealves1]

First-rate resolution!

[@think_in_math]

All support for you sir❤

[@mrhtutoring]

Thank you! 😊

[@Earth_GG]

As a jee aspirant i solved the sum by seeing only the thumnail and came here to verify my answer which is right

[@akgamerz3309]

ME TOO VERY EASY QUESTION 😂

[@1dantown]

X= 1/sq.rt.(5)?

[@mrhtutoring]

Correct

[@FruitPanch7]

I wish I had this math teacher

[@Brid727]

I did the same thing until you approached 2^[2/{log5(x)] = -4 What I did next is multiply both sides by log5(x) so that: -4{log5(x)} = 2 Now move the -4 at the front to the exponent of x in the LHS(logarithm property) so that: log5(x^-4) = 2 Now we pair the base and the exponent(5 and 2 respectively) on one side and the argument on the other side(x^-4) Now, we made an equation so that: x^-4 = 5^2 Now multiply both sides by -1/4 so that: x=5^(-1/2) Or, x=1/sqrt(5) If the question asks for the value too, put it on the calculator and the approximate value is 0.447 upto 3 decimal places

[@harrymatabal8448]

Mr brid excellent work

[@spider1816]

Thank you very much sir. I have only a question:, how were you able to calculate the reciprocal of the square of five so quicky, do you have some trick? However your lessons are always interesting.

[@mrhtutoring]

I used a calculator : )

[@uuproverlord8324]

Is it valid to instead go from 2^(2/log5x)=1/16 to log2(1/16) = 2/(log5x) to log5xlog2(1/16) = 2 to log5x = 2/log2(1/16) which is x = 5^(2/log2(1/16)?

[@japanesefinch9021]

Why does the 2/-4 suddenly become -1/2, without log5x changing? Love your videos, thank you!

[@jinjin1156]

He just change it to its lowest form, even if you dont do that you will still arrive with the same answer.

[@Andeeznuts2008]

He just simplified the fraction from 2/-4 to -1/2 into its simplest form.

[@jamesharmon4994]

5^(-1/2) = 5^(-1) * sqrt(5) = (1/5) * sqrt(5) = sqrt(5)/5

[@costaliberta5969]

didn't get the first yellow line... (trying to remember all that from 25yrs ago)

[@MY_GOAL_IS_MY_LIFE]

1/5^1/2

[@anestismoutafidis4575]

1/16=0,0625 2^-4=1/16 2^-4=2^(2/-0,5)=1/16 2^(2/-log5->(2,24)=1/16 2^(2/log5->(2,24i)=1/16 2^(2/log5->(2,24)×-1 = 2^(2/log5->(5i)^1/21/16 x=(5i)^1/2

[@josephshaff5194]

🤣