Products of terms in sequences: Can We Do That?!?

  Рет қаралды 1,807

Maths Like A Legend

Maths Like A Legend

Күн бұрын

Пікірлер: 11
@zsombororovec645
@zsombororovec645 5 күн бұрын
You've got me interested in this topic, so please do more videoes, thanks and bye.
@JJ_TheGreat
@JJ_TheGreat 5 күн бұрын
What about infinite products?! I would ❤ to know how to deal with those, since in Calculus II we learn about infinite series (sums)! Thanks.
@MathsLikeALegend
@MathsLikeALegend 3 күн бұрын
an interesting idea. I shall add it to my list of ideas!
@Bola382
@Bola382 2 күн бұрын
thought you were going to use some logarithms as well
@MathsLikeALegend
@MathsLikeALegend 2 күн бұрын
I can see the logic behind why you would say that! It is certainly something that has to be used when exploring this topic much beyond what I have covered here to be fair.
@JJ_TheGreat
@JJ_TheGreat 5 күн бұрын
15:36 But in this case, it has 0 in it, so multiplying would just get 0 !!!!
@MathsLikeALegend
@MathsLikeALegend 3 күн бұрын
got it in one.
@nickronca1562
@nickronca1562 18 күн бұрын
2×4×6×8×10×...×(2n) = (2^n)×(n!). Easy. Likewise 1×3×5×7×9×...×(2n+1) = ((2n+1)!)÷((2^n)×(n!)). Easy.
@MathsLikeALegend
@MathsLikeALegend 17 күн бұрын
exactly! :)
@hello_hi1
@hello_hi1 14 күн бұрын
Expected more factorial types but ok
@MathsLikeALegend
@MathsLikeALegend 13 күн бұрын
Yes, to be fair this opens up a door to a whole new world of calculations (which is partly why I make these videos, to hopefully get people interested in these topics). However, there is too much to fit in just 1 video!
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