Aldol Condensation

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I was not understanding this at ALL before I watched this video. You are a master of Ochem!

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Yes

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am I the only one that sings along in the intro lmao it's so frickin catchy, I always find myself humming it at random times

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branding at its finest!

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Your explanations are perfect! It's fantastic how simply you illustrate every topic that we would otherwise find challenging to comprehend.

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I understood more from this 5 minute video than an hour long lecture hats off

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you don't have to stop! there are many other subjects to learn, even if just for fun.

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Professor Dave Explains I hope to do biochem next semester! Hopefully it will bring me back here! Thank you so much!!

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Helpful for MCAT. Thanks!

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Did you already take the MCAT, and if so, how did it go?

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How'd the MCAT go?

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The lecture is perfect only that the writings tend to block important information down

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Just wanted to drop by and thank you for the amazing tutorials you've made for organic chem. You've definitely really helped me and many others grasp different concepts of this subject with such simplicity and ease through your great tutorials. Many thanks prof Dave :D

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Got The Office vibe! This makes learning even better! :D

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Wow nice video! Really well explained!

[@PetrilloCinema]

Thank you sir for getting me back on track! I forgot about that final hydrogen deprotonization👌

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why are you so good?

[@rima9967]

U r always great in explaining everything ..thanks a lot

[@Ps3COD4Fan]

Dave, could you have also used the first resonance structure? The anion carbon attacking the carbonyl carbon?

[@ProfessorDaveExplains]

+LT “Chargers” GFX you certainly can.

[@brianmathews682]

I was wondering in the second to last step it looks like the negatively charged oxygen takes on two protons to form water. Why does it take on 2 to make water instead of taking on 1 to become an alcohol group.

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It was too fast for me so this video helped me: kzbin.info/www/bejne/p2eQd598jJVkoa8

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Finally someone asked the question I had in mind!

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Wow awesome explanation...gives a thorough knowledge...i also sanged along the intro song...its catching...pls do videos for pg students

[@tobiasueffing9985]

Why, at the last step, does it not just form an OH-group, why does it form an double bond?

[@ProfessorDaveExplains]

sometimes you can isolate the addition product, depending on the precise structure, but particularly at higher temperatures elimination is going to be favorable

[@swiftblade168]

Excellent explanations

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[@MrGrapesforall]

Hi, I added some NaOH+ to my wastewater in order to raise to the pH to 7.0. However, an immediate discolouration of my wastewater occured. I suspect it to be due to aerobic oxidation leading to acetalhyde accumulation that leads to adol condensation. Does the adol condensation produce oligomers and polymers that may cause a darkening of aqueous solution? and am i correct in my thinking?

[@ProfessorDaveExplains]

yikes! out of my wheelhouse. the only thing i can say is that enolate chemistry (aldol, etc.) can indeed lead to polymerization, but i can't say much about pH or color or anything like that.

[@Wukeywukey]

During acidic workup, why isn't an alcohol simply formed?

[@ProfessorDaveExplains]

+Wukeywukey sometimes you can stop at the aldol addition product (alcohol), but because of the entropic favorability of elimination it'll usually go to the condensation product, especially at higher temperatures.

[@josho3668]

Wouldn't OH be a good leaving group in basic conditions instead of a formation of a formal positive charge.

[@ProfessorDaveExplains]

absolutely, though we can show the condensation product forming during aqueous acidic workup if we like as well.

[@josho3668]

Thank you

[@youthefuture3816]

shouldn't the aldol product be an aldehyde plus alcohol product? Please explain

[@jennazhang4927]

Thanks!! Explained better than the instructor. However in the last ste, would H2O basic enough to take off the H+ from the alpha H of carbonyl? Isn't is supposed to be OH- instead?

[@ProfessorDaveExplains]

+Jenna Zhang with acidic workup water will do! in acidic conditions water is a base and hydronium is an acid.

[@jennazhang4927]

+Professor Dave Explains Ohhh right! Acidic condition should never use OH- to deprotonate. I see! Thanks again!!! Very helpful

[@tynation0330]

May i know why we don’t use the carbo anion to react further?

[@princessxx94]

Where did the aldehyde come from? Is that what Aldol condensation is, an aldehyde is necessary I'm assuming for this mechanism?

[@ProfessorDaveExplains]

came from wherever! we can mix anything we want together when we do chemistry. for aldol condensation, you need an aldehyde or ketone.

[@princessxx94]

Professor Dave Explains makes sense! Thank you for responding!

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here the night before my 2nd year orgo2 mid-term

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Hahaha looks like learning the mechanism of reaction would be a good investment

[@CraziiBOY504]

So easy to learn from this!! LOVE LOVE!

[@RusiesKroket]

Do these enolate ions with partial charge only occur in water solutions, or is it also possible to find them as solid molecules without water, or are they always part of a larger molecule?

[@teodoraaprcovicc9696]

Thank you so much for this explanation!

[@wall__]

Thanks for kindly explaining :)

[@mohd.aizat_2761]

Is Aldolization and aldol condensation the same process?

[@akrampasha1300]

Ur explanation works like magic ,thanks . Can I hope to get a video on zener diode voltage regulator,plz.

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If i had prof like this.......

[@evvinoah722]

THANK YOU SO MUCH. I was reading through my lab protocol and the explanation sounded like an alien language...this helps a lot!

[@nappingracez]

I'm a bit confused coz my textbook says base is used for aldol condensation, and after watching this video I personally also think that using acid makes more sense. So which one is correct??? Thx in advance :D

[@ProfessorDaveExplains]

aldol can be done in either basic or acidic conditions, in this clip i show the basic route.

[@nappingracez]

Oic, thanks so much :))

[@mawunyondo5034]

How did the water form and not OH after the protonation?

[@s9k328]

H+OH=HOH=H20

[@lulno]

Can you please explain where the second carbonate comes from during the addition? I can't seem to get i. thanks!

[@ProfessorDaveExplains]

+Nona Hovsepyan carbonate? no carbonates involved. feel free to email with questions!

[@Erez_Shamir]

Professor Dave Explains Hi, where the proton came from at the end of the reaction, coul'd it be from the water?

[@ProfessorDaveExplains]

yep water is most likely!

[@Erez_Shamir]

thanks!!

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i love this channel too but if you think this 5 min video is better than all your lectures lmao it says as much about your class as about prof dave

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Your videos are awesome, you're easy to learn from and explain things well.

[@RishabChawla297]

Why do you have -OH2 after work-up? Should it not be -OH followed by base-catalyzed elimination and leaving of the -OH? Because water can leave by itself, no?

[@ProfessorDaveExplains]

could be, but hydroxides won't protonate in basic conditions, that requires acid work up. if i remember correctly, the elimination probably happens during the workup itself, with just the addition happening while in basic conditions. but i'd have to double check!

[@dreamybull1509]

@@ProfessorDaveExplains you'd have OH after protonating the oxide. The presence of the carbonyl group renders the alpha carbon mildly acid which would allow dehydration to occur

[@zeeshanhaider9004]

Hi Sir, why aldol condensation of ketone is difficult than aldehyde?

[@ProfessorDaveExplains]

it's not! both are perfectly feasible. ketones are a little more sterically hindered though, that can sometimes be a factor.

[@madeline8968]

Why wouldn't the O- only get protonated once to make an alcohol? What pushes it all the way through to condensation?

[@ProfessorDaveExplains]

thermodynamics! especially if it's hot, elimination is favorable. but it's true, sometimes the addition product can be isolated.

[@sameersinha5467]

Please make a video on Cannizzaro reaction!

[@PunmasterSTP]

I just wanted to say thank you, and I sincerely hope that I'm not too enolate. 😎

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Thank you professor Subscribed

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very well explained! makes it possible to study OC of one semester within one week! thanks from Germany

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Synthetic and clear!

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unbelievable, you r too good

[@mallayyahiremath8792]

Sorry Sir I have an check last result OH group is not present sir OH. O | || / \ / \ maybe sir

[@shaughnreilly6928]

I agree, my book shows OH as the leaving group. Even though OH is considered a "bad" leaving group, the condensation product is conjugated and is the driving force behind the reaction. Plus losing a hydrogen and a water is overall losing H3O. Losing a hydrogen an OH is overall losing H20.

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I hereby declare you jesus of chemistry

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"Now, upon aqueous acidic workup..."

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Umm, so?

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AAMC MCAT FL3 question 1

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very helpful and well made video thank you !

[@TK-ww8zk]

Can you upload a video on all types of aldol condensations,please? My OC teacher sucks😛

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Great video....keep going

[@gauravsaimaddipati8356]

What is aqueous acidic workup

[@NiteshSagar-hx1xn]

In India we learn this Aldol Condensation In our 12th grade of high school 😂

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really!!💯💯

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@@s9k328 yes

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@@s9k328 you don't learn this in high school?

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[@ProfessorDaveExplains]

sorry i'm not sure!

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Thanks

[@hannahpalme8706]

Can you do an Aldol Addition

[@ProfessorDaveExplains]

aldol addition is the first part of aldol condensation, it's in this clip.

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Life saver!

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Whats's a PKA?

[@ProfessorDaveExplains]

-log Ka, measurement of acidity

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Could you please do a video on polymers

[@ProfessorDaveExplains]

in the biochemistry playlist i talk all about polymers! at least biopolymers.

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can you do a practice problem video for aldol condensation reactions please? I'm going to take my orgo 2 exam on Monday so it won't help me but will surely help other students. Thank you.

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What are doing with ypur life bro

[@ProfessorDaveExplains]

Um, I'm a science communicator.

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Single handedly saving my organic chemistry grade, I'm not even kidding