Simple Harmonic Motion: Hooke's Law

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[@malavikab4236]

Neatly explained, Mr. Dave

[@oorody4297]

4:11 why we put (-)for (f)

[@ceilinaomair2397]

negative sign indicates force is in opposite direction

[@drgermankills7963]

The negative sign in the equation is simply indicating that the force is opposite of the direction of the spring displacement.

[@Ranbir.Bhardwaj]

At 2:22 you said that force exerted by the spring is always opposite the motion But while coming towards centre, force and motion are in same direction. Shouldn't it be like ' force is opposite to the direction in which spring is streched or compressed' ??

[@carultch]

I'm sure that's ultimately what he meant. The spring force is a restoring force, which is proportional to and opposite the deformation from its neutral unstressed position. The spring force doesn't "know" what the velocity or acceleration is of the mass. Viscous drag would be proportional and opposite the velocity, while the apparent "inertial force" (D'Alembert Force) of the mass is proportional to and opposite the acceleration.

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[@martinnambahu2891]

thank you for this video just learned that the force is always negative because its acting in the opposite direction

[@jhelseaamarixe4475]

4:10 is the force always negative like the constant? or if we only pull it then that's when it's negative?

[@blinkbubs3994]

always negative

[@mahboobraju]

Look the equation F=-kx will automatically give the direction of the force for eg. When the particle is somewhere between mean position and positive extreme then x will be positive and hence the force will act towards the negative x axis.....as the acc is towards the -ve x axis and vice versa

[@carultch]

It is negative because it is a restoring force that returns the spring back to its unstressed position. Force is opposite the displacement from the rest position of the spring. It isn't always linear with the displacement, because eventually if you stretch a spring far enough, you'll take it past the point of no return, where it will permanently deform. Force vs distance is not a linear function once you cause the metal to permanently deform.

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This video reminds me of my late friend Elliot 😢, the action of the spring reminds me how he used to caress my skin back and forward 🫶🤞

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[@zynex9250]

4:14 Why is f negative?

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[@Attalla-t9b]

3:28 What about the formula for kinetic energy of the spring?

[@ROCK-dq5xm]

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[@AV-ts2nm]

Hi Prof Dave could you please explain to me as to why the force on the spring is negative?

[@ProfessorDaveExplains]

i think it's because the force of the spring causes an acceleration in the negative direction? i'm not too sure

[@currentlynowshyam1783]

@@ProfessorDaveExplains true opposite to force applied

[@vjith5978]

@@ProfessorDaveExplains so does it act as a restoring force?

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Commerce? 😆

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[@vjith5978]

4:10 why is F, negative?

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I have the same question and my test is in 10 minutes i’m done for

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[@shanestewart1252]

Thanks Dave. Your video reminds me of Baywatch. There is a lot of harmonic motion seen when people run on the beach.

[@shanestewart1252]

All jokes aside Dave. I was a inspector for a railroad and there is something called a harmonic unbalance it say. The difference between cross level between rails in 7 consecutive joints can not exceed . If I remember correctly it is 1 and 5/8 of a inch and if it does the track must be slowed to 10 mph. . Rail length are about 32 feet so a joint are staggered every 16 feet . If not a train car will rock off a track. I assume it is similar to a tsunami in the ocean.. why would that cause a harmonic unbalance.?

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[@eriksambong8806]

I would like to ask why the force has a negative sign. Is it because it is stretched?

[@shivkumarverma9124]

It's acting opposite to the direction of the force we apply, suppose a mass is connected to a spring. We apply the force on the right side, the spring tries to pull us backwards to get back to its natural length. That is, to restore equilibrium. So the force is negitive.

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Explain relationship between newton's third law of motion and reflection of light. Or Differentiate , in your next coming video Plz plz plz plz I hope you are honest professor .

[@bredmond812]

1:19 Could you say it exhibits cosinusoidal behavior? What is the difference?

[@ProfessorDaveExplains]

hmm i suppose that would mean the same thing, but we generally just use the word sinusoidal, as derived from the sine wave, to describe smooth, repetitive oscillation. at least that's my understanding!

[@bredmond812]

Yeah, everybody says it exhibits sinusoidal as far as i have heard. Not to go off on a tangent, but while I have your attention, what does it mean to say that I have a wavelength? Should I understand it as basically the net of all of the wavelengths of my constituent particles? Anyway, it looks like cosine got left out when it comes to english phrases. (see what i did there? :P)

[@ProfessorDaveExplains]

go off on a tangent! zing. so i wouldn't necessarily think of your wavelength as the net of all the wavelengths of your particles, because your wavelength is much smaller than the wavelength of any individual particle. this is because wavelength is inversely proportional to mass. it's just a way of showing that quantum principles do extend to macroscopic objects, as the universe is fundamentally of a quantum nature, but when we get to macroscopic objects, quantum effects become so unbelievably negligible, that we ignore them, like you having a wavelength that is a trillionth of the diameter of a proton. or something like that.

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[@carultch]

@@bredmond812 The essential difference between sine and cosine is the phase at which these functions start, when the input equals zero. Sine starts at the ascending node on the midline and cosine starts at the positive peak. "Co-" means "of the complimentary angle" as a general prefix for trig terms. So cosine(x) is sine(90 deg - x), which is equivalent to sine(x + 90 deg) due to the periodicity of the function. The word sinusoid and sinusoidal come without a prefix, and refer to the original function of sine. These terms only refer to the shape, and not to any of the parameters that scale or position the shape (such as amplitude, midline, phase shift, or angular frequency). Therefore, both cosine functions and sine functions are considered sinusoids (the noun) or sinusoidal (the adjective), regardless of whether we use sine or cosine to identify the function.

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being the first to comment I hope a reply form u professor !!!!

[@ProfessorDaveExplains]

thanks for watching!

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Avegarohan Jaiswal

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Why do you want OP's contact details?

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[@anuththarachanaki7969]

Sir, How doea a restoring force occur when an object osillates?

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Thanks professor dave

[@srivallikatkuri8028]

Why is the force negative at the end?

[@Thesaviorsway]

In which scenario do you know to use 1/2 kx^2 instead of -kx

[@richardlu0928]

I'm also a physics student now so I'm not sure my answer is right or not. I think F=kx is for the force required to stretch the spring, and 1/2kx^2 is for the elastic potential energy which is Ee, one is energy and another is force. Hope this helps!

[@carultch]

@@richardlu0928 Your answer is entirely correct. And you will find that if you take the negative integral of -k*x, you will get 1/2*x^2. Potential energy is the negative integral of force relative to position, when the force is conservative. More generally for the 3-D case, force is the negative gradient of potential energy.

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what if we are using the formula T=2pi over square root of m over k, so how would we find it

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[@danielalexanderreyespineda1131]

Hi!! teacher, I will like to know if we compute the work that will do the spring on that object (which is applying force on the spring) is it going to be -1.8 J? right? I just want to learn :c

[@BirnieMac1]

Okay but what if they’re not letting us simplify it without friction anymore Is it just setting up the equations of motion and taking the sum of forces (friction opposing motion)?