Finding End Behavior of Rational Functions (Precalculus - College Algebra 42)

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Professor Leonard

Professor Leonard

Күн бұрын

Пікірлер: 30
@ethanarmstrong7929
@ethanarmstrong7929 4 жыл бұрын
Is it just me or is anyone else mesmerized by this man's bicep?
@magnacrushersart572
@magnacrushersart572 Ай бұрын
*Disclaimer, this video will make you insecure about your body and intelligence*
9 ай бұрын
@4:55 thanks for making the decision to develop a new example instead of mixing up the first one. 💯
@Zeltricks
@Zeltricks 4 жыл бұрын
I'm not even taking this class. I'm just stopping by with my favorite online professor that helped me get a 100 on my differential equation exam! Keep up what you are doing sir! I hope in seeing you making more videos for higher order differential equations!
@JAHWH
@JAHWH 2 жыл бұрын
Went through numerous videos to understand this and when I watched this video I couldn't believe how simple this concept was. Thanks!
@hamzaissa4842
@hamzaissa4842 4 жыл бұрын
I click on the ads just to help my favorite professor of all time
@verano.violet
@verano.violet Жыл бұрын
Professor Leonard, I want to thank you for everything. Your videos have helped me immensely. I’m currently in an engineering program to become an electrical engineer/computer scientist and if it weren’t for your videos, I would not be where I’m at today. Someday I am going to return the favor. You are amazing!!
@StevenMcCauley-o7q
@StevenMcCauley-o7q 18 күн бұрын
return it yet?
@Obscure97
@Obscure97 4 жыл бұрын
Two lessons in one day? What a legend.
@georgesadler7830
@georgesadler7830 2 жыл бұрын
Professor Leonard, thank you for another beautiful video/lecture on How to determine the end behavior of rational functions that don't have Horizontal /Slant Asymptote.
@emilybriseno1300
@emilybriseno1300 Ай бұрын
Thank you Mr.Leonard
@ProtoMaxoid
@ProtoMaxoid 4 жыл бұрын
Leonard's on a roll!
@franciseylim11
@franciseylim11 4 жыл бұрын
Only a few textbooks (so far I found one), that really talks about this last cases, no horizontal asymptote, when the degree of numerator is larger than degree of denominator MORE THAN 1. It is called parabolic asymptote (for that example, y=x^2) , please refer to John W. Coburn, 2E, page 366.
@khushisinghal2316
@khushisinghal2316 Жыл бұрын
Thank you very much professor!!
@greymohan4370
@greymohan4370 3 жыл бұрын
If you guys didnt already know... put Leonard's polynomials into DESMOS to have a feel, (google desmos)
@somasahu1234
@somasahu1234 3 жыл бұрын
Thnx bro!
@faithgraham35
@faithgraham35 2 жыл бұрын
I’ve been doing that but for some reason the last example with the cubic isn’t working out on desmos. It looks parabolic. But I agree with the professor that it should look cubic. 🤔 Anyone know why.
@chrisbird5000
@chrisbird5000 2 жыл бұрын
Brilliant, thank you so much. You explained this so well
@38raiyyan.u9b6
@38raiyyan.u9b6 5 ай бұрын
What about x raised to FRATION by difference in Numerator and denominator
@chriswilliams5291
@chriswilliams5291 5 ай бұрын
What about something that is in factored form such as (x+3)^3/(x-3)^3
@marccepeci2980
@marccepeci2980 7 ай бұрын
If the degree in the NUMERATOR is greater by 2 than the denominator then is it asymptotic to a Parabola?
@beetIebum_
@beetIebum_ Жыл бұрын
thanks again
@hrishiparipati6931
@hrishiparipati6931 8 ай бұрын
THANK YOU, THANK YOU FOR THIS. YOU ARE GOATED!!!!!!!!!!!!! (SUBED & LIKED)
@kedson2957
@kedson2957 4 жыл бұрын
I do not care about petty rational functions just watch for Leonard
@juanmadrid7655
@juanmadrid7655 Жыл бұрын
Men I fucking love the video. Thank you so much!
@38raiyyan.u9b6
@38raiyyan.u9b6 5 ай бұрын
Why there is no slant asymptotic behaviour when denominator degree is Greator than 1 like Numerator
@victord9421
@victord9421 5 күн бұрын
because the asymptote goes from being linear (slant asymptote) to higher powers, like quadratic, cubic, quartic etc...
@teagmcccc
@teagmcccc 3 жыл бұрын
THABK U SIR
@AceHardy
@AceHardy 4 жыл бұрын
✍️
@Fatima-ou5yo
@Fatima-ou5yo 4 жыл бұрын
So cute
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