Kirchhoff's Laws - How to Solve a KCL & KVL Problem - Circuit Analysis

[@jgetre4816]

even the grade 6 student will understand this, very nice to have on this network

[@davidchang5862]

It is really a waste of time and money paying for school fees. Just KZbin and there you have it. Better quality explanations complete with sophisticated animations and a deep, sexy voice. Bravo !

[@IsaiYuno]

I think its a bot. But true

[@AhmedSamy-ll5si]

I love this voice over so much

[@Fizah6v]

the most useful and most understanding video for meh on this topic ❤

[@philipwilkie3239]

Kirchhoff was one of the under-rated figures in science history. It was these first systematic rules defining how electricity flowed in basic circuits that changed electricity from a curiosity into the ubiquitous tool that it is today. For certain there are other figures - Maxwell the most notable - that made essential and magnificent strides, but these basic ideas of Kirchhoff laid the foundation.

[@buffplums]

This is an excellent tutorial many thanks.

[@aasaithambi8758]

Please provide more videos as beginners like will learn more from that. You are wonderfully great teacher of electrical theory. AwAiting for more videos please

[@Profmad]

Thank you, I will

[@crystalmacau]

You video is fun to work with thank you for your clear explanations💞💞💞

[@chrisposiquit2313]

very clear explanation. thanks for your very helpful videos.

[@maruthalakshmit9a658]

That was very clear, thanks a ton😊

[@kabandajamir9844]

The world's best teacher thanks sir

[@youssefadam5186]

Nice animation. Great content. Bravo 👍

[@Savage-lx5yj]

Clear and concise! Excellent 👍

[@kgomez5104]

He making nose se at all this why he on KZbin explaining the current across can't be the same dumbass that's what the resistator is for

[@kgomez5104]

To fucking regulate the flow of energy so one side can't be giving 12 volts of you want to regulated unless you have a transistor you just probably never worked on circuit

[@ivegotpetercriss]

when he says DONE at 8:01 i felt that

[@AdeoyeBukola-b6k]

True

[@aryanchhillar5320]

24:00 you changed the battery sign ..

[@Krawdad-k8n]

I don't understand why is the equation 5- equation 4 multiplied by two? and why is it multiplied by 29 and (3I+10I)? Minute 22:11

[@Bereket-ow1ky]

Great explanation + great animation = greatest video,it is better than all videos in Kirchhoff law Thank you 👍👏

[@Profmad]

Wow, thanks!

[@mkepler5861]

you obviously weren't watching very carefully, he made two mistakes!!!

[@kebugcheck]

you're so helpful...thanks!!

[@UcoK0007]

Thanks a lot, Sir Shanilka

[@Düttürüdüt]

beautiful video

[@subatomicparticle6535]

At 6:43 if there is "0" volts at point D then how can current flow with no EMF to create/cause it after that point. Doesn't the wiring after point D also contain some resistance that would require some voltage to be consumed all the way back to the battery. Kirchoff's law being the sum of all the voltage drops will equal the source voltage.

[@andyz1157]

Need to show calculation part of voltage and current 😊

[@UNIVERSESOUND250]

i got problem so when there is rise do we put negative sign or it is positive sign

[@SelindaThomas]

well explained. Thanks🙏

[@Ben5-uf5tg]

in the last example you changed the direction of the voltage source with 0.5 volts which messes up calculations. otherwise great content

[@jeewakanuwantha7561]

Same problem to me

[@MarkBinalasi]

You are right 👍

[@filyz94]

at 22:10 number 2 come from where? "2" x eq 5 - 4.

[@manjeerapalagummi496]

Please upload thevenin and norton's theorems

[@UcoK0007]

Sir, why at the example no. 02, the source at right side, before the + on the top then at the second you made it to be - on the top? Could you explain it to me Regards

[@SajeduzZaman-kh1rm]

22:09 can you explain why you used 2×(5)-(4) equation. Why not (5)-(4).

[@RadiantMeteor-y4n]

That is to solve the algebra. It is not a physics question, it's a math problem

[@PrincessaRatty]

It's like the elimination method in simultaneous equations. He twice both equation for them to be the same number to cancel it , I think 😊

[@nacirasebsi1869]

Thank you so much teacher!!🙏🙏 Sorry teacher at: 4:40 of this video I1=0.3A I2=0.6A Excellent lesson👍👏👏💯🇩🇿🇩🇿

[@I_love_electricity]

5:29 Something isn't right. Sould the fraction be 3 over 40?

[@whoopsie2122]

In that area he did not use ohms law. It just means that the value of Rt1 is equal to 40/3

[@crystalmacau]

Its right when you do the algebra :) Because 1/Rt=3/40. So you have to rearrange to find Rt. Thus Rt= 40/3

[@I_love_electricity]

@@crystalmacau There was something I missed and thank you.

[@tritomvanherk518]

Very well explained thanks.

[@MehilaTahaYacine]

23:46 you changed the positive side of the 0.5 battery.

[@lorenknox76]

Thank you!

[@Aggy-c4q]

how come the voltage at point C D is 6.7v? if you sum up the voltage drop for the circuit i.e 2.2v +9.8v+6.7v it will be more than the supply voltage which is 12v.

[@muftahibrahimsahoub3497]

Thanks so Much pro mad its very good information and good intimation withe video

[@geraldwellem2696]

U are making my life easy.. Do you have those notes or slides?

[@KananBehera-q5k]

Thank you so much sir ❤

[@zaktrinkle1425]

Why did you multiple equation 5 by 2?

[@surgingcircuits6955]

At 4'13", why wasn't Rt = ((R1*R2)/(R1+R2)) enough? Thx.

[@surgingcircuits6955]

Nevermind, thx. Another video filled the info holes.

[@gorang_vashist]

for example, if same question came in MCQ type exam , and my current values are negative then how should I choose correct answer ?

[@siddharth5448]

It simply means that the assumed direction is wrong & not the value. If your calculation is correct just go with the +ve option

[@robertlinder6414]

Flashback to high school electronics shop

[@PrinceMatladi-w4h]

Salute 🤝

[@jondoe3456]

How did you get 40/3 for your answer?

[@crystalmacau]

Because (1/Rt)=(3/40) So you have to rearrange to find Rt (solve for Rt using algebra). Thus Rt= 40/3

[@davidf9062]

21:40 WTF ! You changed the sign of 7i2 ! But how ? Very confusing.

[@lubbers71]

was also confused but the sign should be +7I2 (in the first equation)

[@Wil_Bloodworth]

I wish I "got it" but this was really confusing. I will have to watch it again and see if it makes sense the second time. I think it was all of the reused label names that is confusing.

[@drmindbender8616]

Current draw

[@whoopsie2122]

@Wil_Bloodworth Don't just watch it. Solve the problem to understand it better because it's really confusing when you just watch it.

[@crystalmacau]

I pause a lot, and use several study aids this being one of them. The more and more you hear the words slowly slowly it will click. I also draw EVERYTHING

[@stanfordkoga-zs9nh]

Thank u

[@DrakeLarson-js9px]

This is Great!

[@BurRun-kt3tf]

Thanks អរគុណ❤

[@GiC7]

Thanks

[@Bob-dx9ve]

DONE!

[@juancarlossaavedra6757]

@1:29 there is a big mistake ! electrons have a negative charge so the current should flow in the other direction ! !.

[@Bedfford]

yes, but in the video the current is in the CONVENTIONAL form, not the REAL. For almost all cases, the conventional flow work just fine.

[@VinceVILLEGAS-w1r]

asa ang sign sa resistance?

[@farhans2650]

Make a video on MOSFET

[@thandintsizwa5639]

Please make a video on MOSFET

[@oliversalvador8694]

Current flow from negative to positive

[@SelindaThomas]

Current is the flow of elections, but current and electron flow in opposite direction. Current flows from positive to negative and electron flows from negative to positive.

[@wimharter]

Current travel is negative to positive

[@siddharth5448]

No, Current flows from positive to negative

[@معكتاب]

9:09

[@SatExam-gl9eq]

calculate the law

[@IrtazaShahid-v4f]

in Q4 voltage is 2.9 and your approach seems a little wrong in that case.

[@mkepler5861]

it is quite obvious you know this material very well, but at 15 minutes the Loop 2 is not a circular current path. it is only from top down. another problem is at the 21 minute problem, on the left side of the circuit, you used conventional current flow positive to negative. but on the right side you use electron flow from negative to positive. sorry MAD, but you can't have current flowing in both directions, no bueno, I'd like to see you talk your way out of this one. you may have made this cake, but the only way you can eat it is to admit your mistakes or if you can answer my questions why you are right I will give you a sub and thumbs up. mike but I don't this that's gonna happen!!!

[@JakeGamiao]

Yeah. We have the same observation bro. @ 21:40 He said loop BCDB but presented 29 = V3 - V2 and ultimately ended V3 + V2 = 29 as as the 3rd equation... HOW DID HE DO THE MATH in this part...it shud be noted that + or - signs denote the direction of current... HOW COME mike seemed to have neglected that theory????😂😂😂 Your presentation does not seem to be helping mike!!!! on the contrary YOU ARE CONFUSING visitors of ur video.

[@subatomicparticle6535]

@@JakeGamiao Good on ya Jake I just posted the same and wanted to see if someone else also picked this up. How does 29 = 3 I3 - 7 I2 all of a sudden miraculously with no explanation now become 29 = 3 I3 + 7 I2. They both cannot be correct. Equation 3 looks correct based on solving that loop which I called CBDC starting just after the battery + using the direction of current flow and not his arrow direction opposite to current flow and how he solved the first loop ABDA. My question is what practical application would you put 2 independent power sources in a circuit like that. In electronic equipment AA, AAA, C, D batteries are installed + to - to multiply the voltage output. I never seen anything + to + or - to -!

[@StephenShimo]

Wow

[@Studybird244]

😊❤

[@gideonsaro9669]

❤

[@DanielleKing-n7z]

Clark Brian Jones Linda Rodriguez Mark

[@RonMatthews-q6h]

Rodriguez Jennifer Taylor Mary Brown Donna

[@PegFlora-n8s]

Brown Jeffrey Walker Deborah Martinez Kevin

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[@elifdemir1471]

😭😭😭😭

[@DorisCorey-j7i]

Martin Margaret Miller Donald Thomas Angela

[@MonroeAlva-f7r]

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[@MohamedMathani]

thanks

[@HicksEmmanuel-p5y]

Hernandez Nancy Walker Larry Jackson Jason

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