"break" & "continue" Statements in Python #10

[@programizstudios]

🔥Finding it Damn Hard to Understand Python? Learn to code-the right way-with interactive lessons, quizzes & challenges. Build a strong programming base; it's IMPORTANT! Try Programiz PRO for Free: bit.ly/interactive-py

[@nikanayo]

for languages in ['Python', 'Java', 'Swift', 'C', 'C++']: if (languages == 'Swift'or languages == 'C++'): continue print(languages)

[@Abeedalamkhan]

To be Honest i was very very scared of programming, i am watching your Videos since last week and now i am writing few lines of codes just because of you. Thank you so much Your are diong a good job

[@kismet4904]

Loving this series, I have learned a lot in such a short amount of time :D keep it up!

[@ppirsjsh505]

languages=["phyton","java","swift","C","C++"] for character in languages: if character=="C++" or character=="swift": continue print(character)

[@ramraj4047]

languages=["python","java","swift","c","c++"] for i in range (len(languages)): if(i==2 or i==4): continue print(languages[i])

[@irynahryma2605]

I've been treing this code for several times, it doesn't skip the languages 2 and 4. I've tried other examples with "break" and "continue", and it worked. Am I doing something wrong?

[@SampannaAryal]

@@irynahryma2605 a=["Python", "Java", "Swift", "C", "C++"] for i in a: if i.upper()=="SWIFT" or i.upper()=="C++": continue print(i)

[@gj18p420]

for i in range(10): language = str(input("Enter a language: ")) if language == "Swift" or language == "c++": continue print(language)

[@sunakshiranjan3308]

just one word- Awesome! Your channel is a very big help to me. Thanks :)

[@kartikeshwarhingole6007]

thank you sir I was able to complete your home work.

[@amine2010amine]

The best Channel to learn python

[@nickjankovic2210]

Great tutori, very professional and easy to follow. The only problem I have is ....I do not know where to find this "link below" where I can check the solution to exercizes at the end of each tutorial.

[@programizstudios]

Hi Nick, You can find solutions to the exercise tasks in this link: github.com/programiz/python-course/

[@pachakutiq266]

languages = [ "Python" , "Java" , "Swift" , "C" , "C++"] for a in languages: if a == "Swift": continue if a == "C++": continue print(a)

[@kishansindhi5181]

Are bhai output nahi aa raha

[@pachakutiq266]

@@kishansindhi5181 really? What's ur error? I'll see if I can help..

[@basirsaboor2367]

can you do it by input function. plz!

[@basirsaboor2367]

input the language by the user

[@saureetchakrabarti3913]

languages = ["Python", "Java", "Swift", "C", "C++"] for language in languages: if language == "Swift" or language == "C++": continue print(language)

[@shadanakhtar5095]

But bro have a doubt that should i watch your video or study from the website and i think video is best because my brother is learning from the website and it take a lot of times but in video you explain soo nicely and fast

[@kevinlavoie2800]

languages = 'Python', 'Java', 'Swift', 'C', 'C++' for language in languages: if language == 'Swift': continue elif language == 'C++': continue print(language)

[@cezartofan1791]

#lol, we think almost the same: languages=("Python","Java","Swift","C","C++") for language in languages: if language=="Swift" or language=="C++": continue print(language)

[@prajilshrestha7995]

Thumbnail: Feeling cute, might teach python later :D

[@RedBull.RedBull]

I don't understand your comment.. how you feel the cute? Teaching Python later to whom?

[@rudrakshchatterjee]

😂

[@glennswhiffmontage9397]

@@RedBull.RedBull didn't understand the assignment.

[@akshaymanta55]

🤣🤣🤣 nailed it!

[@vaishalidixit4871]

THANK YOU SIR HERE IS THE CODING TASK languages = ["PYTHON","JAVA","SWIFT","C","C++"] for i in languages: if i == "C++" or i == "SWIFT" : continue print (i)

[@DigitalAcademyOnline]

Learning Python is something you would like to get in your skills, but you do not know where to start? This NEW channel will help you out leaning Python Programming from scratch - for complete Beginners, Intermediate and Advanced Levels

[@Footballeditz900]

languages = ["Python","Java","Swift","C","C++"] for i in languages: if i == languages[2] or i == languages[4]: continue else: print(i)

[@beksaylor]

Love your videos..and website...thanks so much for all that you and your team do...

[@KulbirAhluwalia]

Everything is perfect, just keep your head stable when you speak. Thank you.

[@thelegendarysummersky3189]

for languages in ['Python', 'Java', 'Swift', 'C', 'C++']: if (languages == 'Swift' or languages == 'C++'): continue print("Language is: ", languages)

[@oogook8153]

Thanks for clearing my confusion, it was really helpful but take care of your head don't move it so much it might "Break" and you may not be able to "Continue" with such series.

[@lakshanj.kumara7648]

languages=("Python" , "java" , "Swift" ,"C","C++") for language in languages: if language=="Swift" or language=="C": continue print(language)

[@victorycoconut]

Wait! I'm using your Learn Python app and it is really helpful!

[@3zez2025]

lang = ["python","java","swift","c","c++"] for x in lang: if (x == "java"): continue elif (x == "c++"): continue print(x)

[@EmereEmmanuel]

here we go!!! languages = ['python', 'java' 'swift', 'php', 'c', 'c++'] for i in languages: if i == 'swift' or i == 'c++': continue print(i)

[@adammunawar2806]

thisset = {'python', 'java', 'c', 'swift', 'c++'} for x in thisset: print(x) if x == 'switf' 'c++': continue

[@johnhaythorpe1063]

Hi, I am loving the course. But this lesson appears to be out of order when I use the playlist to access the programs, it is appearing before lesson 9, instead of after. I am taking notes and practicing every exercise you demonstrate and then I vary my code a bit to see that I understand what you have taught. Thank you for this great series

[@ozguravan9714]

languages=["pyhton","java","c","c++","swift"] for tongue in languages: if tongue=="swift": continue elif tongue=="c++": continue else: print(tongue)

[@kanika1]

languages =["Python", "Java", "C", "Swift", "C++"] for character in languages: if character == "Swift" or character =="C++": break print(character) Or...... languages =["Python", "Java", "C", "Swift", "C++"] for character in languages: if character == "Swift" or character =="C++": continue print(character)

[@pinkshoelace8388]

I do not recommend the first solution, it will work in this case because Swift and C++ are the last values in the list, but if one of them was the first item on the list then the loop would break and none of the languages would be printed.

[@kanika1]

@@pinkshoelace8388 yes i agree. I realised this when I progressed in python. Thanks for spotting :-)

[@sandipansarkar9211]

nice explanation

[@Aravindblaze95]

languages = ["Python", "Java", "Swift", "C", "C++"] result =[] for language in languages: if language in ["Swift"]: continue if language in ["C++"]: break result.append(language) print(f"The Output is {result}")

[@Aravindblaze95]

The Output is ['Python', 'Java', 'C']

[@gemrwx]

languages = ["Python", "Java", "Swift", "C", "C++"] for item in languages: if item == "Swift" or item == "C++": continue else: print(item)

[@programizstudios]

The logic you are trying to use is correct> However, there is an error in the test condition. Change the test condition to: item == "Swift" or item == "C++"

[@gemrwx]

@@programizstudios Thanks

[@upulithaperera4847]

@@programizstudios but isn't it the same thing sir?

[@abdu47137]

I appreciate you man, thanks for these tutorials

[@codestone4911]

Nice Tutorial

[@man0cash]

thank you for this video it was helpful :)

[@NehaGupta-if7se]

Thank u so much sir...

[@beans4114]

languages = [ “python” , “Java” , “swift” , “C” , “C++” ] for i in languages: if i == “C++”: continue elif i == “swift”: continue print(i)

[@harshad9203]

languages = ['python', 'java', 'swift', 'C', 'C++'] for item in languages: if item == 'swift' or item == 'C++': continue print(item) -- Programming Task Answer --

[@nandupagere5764]

language = ["Python", "Java", "Swift", "C", "C++"] for item in language: if item=="Swift" or item=="C++": continue print(item)

[@hijushajahan5263]

languages = ["Python", "Java", "Swift", "C", "C++"] for i in languages: if i == "Swift" or i == "C++": continue print(i)

[@georgemorrison1814]

I am new in programing . After several attempts, I found out the answer on the Github repository is wrong. Correct code should be list = ["Python", "Java", "Swift", "C", "C++"] for item in list: if item == "Swift" or item =="C++" continue print(item)

[@georgemorrison1814]

Sorry it is right, I realized my mistake

[@limingyin5094]

you forgot to put : at the end of the if item == "Swift" or item =="C++":

[@joyceadhiambo9977]

Dude you are an excellent teacher...am now enjoying coding languages=['python','java','swift','c','c++'] for language in languages: languages=['python','java','swift','c','c++'] if language==('swift'): continue if language==('c++'): break print(language)

[@mdiftekhar6876]

languages=["python","java","swift","c","c++"] for i in languages: if i=="swift": continue if i=="c++": continue print(i) print("h")

[@shaileshsingh1445]

Wow you are such a great mentor , really helping to build basics :) God Bless you :)

[@avachavoshi574]

Thank you!

[@Jayashreee624]

I have written the same code just changed the variable " item" into "digits" at 2:36 but I am getting

[@riturajritweek681]

languages=["python","java","c","c++","swift"] exclude=["java","c"] for i in languages: if i in exclude: continue else: print(i)

[@rajeshdubey1260]

#Can you create a program so that all items of the language are printed except swift and C++ # language=["Python","Java","Swift", "c","c++"] language=["Python","Java","Swift","C","C++"] for i in language: if i=="Swift": continue elif i=="C++": continue else: print(i)

[@dymonn]

lang = ["Python", "Java", "Swift", "C", "C++"] for item in lang: if item == "Swift" or item == "C++": continue print(item)

[@muradali1231]

If I type- "if item == 3: break" after "print(item)" it gives Indentation error. Does anybody know why this happens.

[@jodezod]

If it says indentation error then you probably messed up somewhere on the indentations

[@santoshkapse3359]

languages = ["Python", "Java", "Swift", "C", "C++"] for langauge in languages: if language == "Swift" or language == "C++": continue print(langauge) output :- Traceback (most recent call last): NameError: name 'language' is not defined

[@divyaahirkar9183]

languages = [ " python" , " java" , " swift", " c" , " c++"] for language in langyages : print ( language) if language =" swift" or language = " c++" break

[@kamrulhassan1219]

why used float number here? if we use int number what will happened

[@ines7257]

thank u!

[@GiulioVonKerman]

What means float(input())? Thanks!

[@VikasChauhan-ue2th]

Float means decimal numbers like 10.6, 9.0, 4.89, etc. If you try "int" instead of "float" it will only give you integer values like 10, 9, 4 and not the decimal values.

[@SUMANKUMAR-nt2ur]

Sir when next video will post

[@bharadwajs3475]

Op sir. With your 1video I can understand easily. I think you are a South Indian🇮🇳👳. I hope you will continue posting more videos regarding python. ❤❤

[@Anonymous-tt7yi]

Yup, I am pretty sure because his first software job was in Hyderabad, India.

[@lastonline2614]

he is from nepal bro...

[@soumadeepdas7610]

where is the github link sir?

[@losikanicholas5105]

Y r we using or during the comparison

[@anukaran3438]

lang = ['python','java','swift','c','c++'] for i in lang: if (i==lang[2]) or (i==lang[4]) : continue else: print(i)

[@pavelboldin7227]

I forgot about OR, so my code is: languages = [ ] for language in languages: if language == 'swift': continue if language =='C++': break print(language)

[@f.a5148]

my like turned your video from 1.4k to 1.5k

[@demetrepanjakidze3787]

languages = ["Python", "Java", "Swift", "C", "C++"] list=[] for _ in range(len(languages)): if languages[_] == "Python" or languages[_] == "Java" or languages[_] == "C": list.append(languages[_]) print(list)

[@DoryRutayisire]

why can't we just use an if statement instead of a while loop at 3:34?

[@emrandafadar4445]

I can't understand this one but how about this :- languages = ["python", "java"', " Swift", "C"', " C++"] Print(languages [0]) Print(languages [1]) Print(languages [3])

[@Markjairus95]

languages=["python","java","swift","c","c++"] print(languages[0,1,3])

[@debebebelaye1881]

my_list = ["python", "Java", "Swift", "C", "C++"] for i in my_list: if i == "Swift" or i == "C++": continue print(i, end=",")

[@some0ne308]

#Question_answer language = ["Python", "Java", "Swift", "C", "C++"] for p_language in language: if p_language == "Swift": continue if p_language == "C++": continue print(p_language)

[@anandshankarm777]

languages = ["Python", "Java", "Swift", "C", "C++"] print(languages[0]) print(languages [1]) print (languages [3])

[@ayonbiswas4186]

[print(i) for i in ["python", "java", "swift", "c++", "c"] if i!="swift" and i!="c++"]

[@bhavishibansal2573]

lang=["Python","Java","Swift","C","C++"] lang.remove("Swift") lang.remove("C++") print(lang)

[@voytox]

you should use loop and what is thought in this vid

[@torsoto23]

languages = ["Python", "Java", "Swift", "C", "C++"] without break&continue: for i in languages: if i != "Swift" and i !="C++": print(i) with break&continue: for i in languages: if i == "Swift": continue if i == "C++": continue print(i)

[@SahilShaikh-7]

language = ['python','java','swift','c','c++'] new_language = [ ] for i in language: if i == "swift" or i == 'c++': continue else: new_language.append(i) new_language will be ['python', 'java', 'c']

[@wnttknwmrthngs3360]

Is this acceptable? lang = ["Python", "Java", "Swift", "C", "C++"] for i in lang: if i == lang[2]: continue if i == lang[4]: continue print(i)

[@gabrielnino2892]

No thank you! ❤

[@prathmeshborse2898]

😇

[@misterduck4527]

you didn't turn your head enough

[@ivanpaulmendoza4248]

where the fuck did the for and in range come from there is no tutorial for that in this series

[@banerjeekrishna5230]

Thalakai oopadam aaparaa babu

[@anonymousboss824]

Binod

[@freeprivatetutor]

Why Break and continue are giving no output? Just blank, not any warning, Write exactly same but no output, only the end has printed

[@moustafamedhat4189]

for languages in ['Python','Swift','C++','C','Java']: if languages =='Swift' or languages=='C++': continue print(languages)

[@Mamata171]

tq

[@keerthanasaini3167]

languages = ["Python", "Java", "Swift", "C", "C++"] for language in languages: if language == "Swift" or language == "C++": continue print(language)

[@didio.1791]

languages = ['python','java','swift','c','c++'] for language in languages: if language == 'swift' or language == 'c++': continue print(language)

[@majidalich2947]

languages = ['Python', 'Java', 'C', 'Swift', 'C++'] for i in languages: if i == 'C++' or i == 'Swift': continue else: print(i)

[@reqssss]

languages = ["Python", "Java", "Swift", "C", "C++"] for language in languages: if language == "Swift" and "C++": continue print(language)

[@girishgh9793]

languages=["c++","c","phyton","swift","rust"] for language in languages: if language == "swift" or language == "c++": continue print(language)

[@kevinekene3765]

languages = 'Python', 'Java', 'Swift', 'C', 'C++' for language in languages: if language == 'Swift' or language== 'C++': continue print(language)

[@zainulabdeen7074]

languages = ["Python","Java","swift","C","C++"] for i in languages: if i=="swift" or i=="C++": continue print(i)

[@Avinashsingh-lz3ey]

languages = ["Python", "Java", "Swift", "C", "C++"] for language in languages: if language == "Swift" or language == "C++": continue print(language)

[@awesomeiram]

but u just ripped-off that other comment tho

[@sravankanagandla6147]

languages = ["Python", "Java", "Swift", "C", "C++"] for i in languages: if i=='Swift' or i=='C++': continue print(i)