Projection of Solids_Problem 5 in Powerpoint & AUTOCAD

[@vedantvarma5464]

You're a God sent man indeed. I can't thank you enough.

[@koushiknallapuneni2564]

we are having an engineering drawing .god ..that's. Manas patnaik sir......👌👌

[@ManasPatnaikofficial]

Koushik.......Thanks for appreciating my work.... All the best in life I have also started making lectures on engineering mechanics Do check it out on my channel page..... Do share and recommend this channel to your friends and classmates so that they can also benefit... Cheers....

[@koushiknallapuneni2564]

Manas Patnaik sir that's great to hear from you...I'll sure recommend this... best of luck... sir..

[@SuGu1915]

As the object is inclined with VP then why didn't it front view i.e. square abcd lies on VP as per your assumption.

[@yashikamehta2004]

Even I was thinking the Same

[@kshitij4461]

Before I came here I was a big Zero in Engineering Drawing and after watching u r videos I have become hero of engineering drawing😊. Thnxx I will never forget this channel and I'll share to all first year students...... U r simply awesome sir

[@ManasPatnaikofficial]

All the best Kshitij....

[@faizanqazi7004]

I appreciate the efforts you took to make this video and the passion you have ! Thank you Sir 😊

[@_Sameerawakeel_ECE_]

You are working very hard sir people like you can build our nation,s youth . Love you so much sir ❤️❤️❤️

[@heetpatel9960]

Miracle Life saver Just before exams perfect video❤❤

[@ManasPatnaikofficial]

Thank you.....All the very best and do share with you friends

[@satyanarayanaakula4640]

Sir my question is A square pyrimide of side 40mm and axis length is 100mm and one edge of the square is completely resting on hp it is parallel to the hp and the axis is included 60° to hp and draw the projection

[@arjunav5425]

Thank you sir..!! 😘❣️

[@dharaneshreddy252]

Simple and clear cut explanation hands off

[@saikalyaninduri7667]

Sir in case 1 why are you considering the base of the pyramid to be on the hp , in example 1 (where it is mentioned that the rectangular surface ofpentagonal prism is resting on hp but you did not solve it like this question .why ?

[@gouravbhagat5857]

I think its Front view should be drawn first as the axis is inclined to VP..Pls reply sir...i m comfused and make it clear...

[@anupamgautham9483]

Yeah me too

[@fabiyaca]

Your videos are really superb.Can you please make a video explaining trapezoidal method.

[@saiajaygelli2380]

Your video has good explanation

[@naveenparnapalli483]

Thank u sir

[@gameboyrudresh473]

Why does the apex need to be nearer to the VP? What would be wrong if it were further from VP?

[@sujaldhadoti177]

Draw the top and front views of a rectangular pyramid of sides of base 40x 50 mm and height 70 mm when it lies on one of its larger triangular faces on HP. The longer edge of the base of the triangular face lying on HP is inclined at 60 to VP in the top view with the apex of the pyramid being nearer to VP.

[@ce_070_sunny_nath8]

Sir it will be much more better if u explain with the help of hp and vp on real just like u have made pyramid with the help of hard paper.

[@mastizone4245]

Sir you really made it simple . Thank You

[@nishanthbs1046]

Sir you made it really easy

[@yashjain70]

god of engineering drawing

[@ManasPatnaikofficial]

Yash....Thanks for your kind words........ Just regard me as your teacher.... Thats what i am, to help all of you in learning.........

[@known_to_be_jb1981]

Sir. Please make video about section of solids. Using cutting plane. Etc.,

[@hamza2412-l4b]

Sir my question is how to draw a square pyramid base 40mm and axis 70mm has a corner base in v.p. . draw its projection slant edge containing corner makes an angle of 45° to v.p. and flint edge inclined at angle 60

[@NitishGupta04]

Sir, can we make 45° angle through the axis instead of side which is parallel to that axis??

[@ManasPatnaikofficial]

Yes you can do that...... I may have followed the rectangle approach. Its good to see that you guys are thinking 🤔...... All the best

[@NitishGupta04]

@@ManasPatnaikofficial thanks a lot sir❤

[@vikaschandrakar9784]

Doubt:Sir same question but it said that slant edge containing that face parallel to the VP draw the projection of pyramid?

[@sonalieahirwar5427]

sir, in case 2, why we can't take angle - 180 degree instead of angle 45 degree ? (for apex to be at farthest from XY )

[@mrindiagaming7803]

sir thanks for making this video's this r really very helpful for me

[@kroton8737]

sir 1 question -why do you make line cd in front view at 13:06 darker.Shouldn"t it be hidden?

[@abdulquadiransari1647]

Sie, In Case 1 the Last Stage We Don't Have To Joint O' a' As a hidden line

[@ManasPatnaikofficial]

Abdul...You are absolutely right.... Thanks for pointing that out.... There should be a hidden line joining a' and o'...

[@prangya9805]

You just saved me thank you

[@tanishakhandelwal5174]

because it is inclined to vp shouldnt object be horizontal in first steo

[@shubhamketkale9383]

Sir in first step why have you made the square pyramid to rest its base on the hp to get its true shape on vp, you could have also made it to rest its one face on the hp to get its true shape in the hp in top view and its true base view on the vp?

[@vinayjustin8138]

Sir u said when ever the angle is made with HP or vp in third step ...we able to kept the edge perpendicular to xy.....but in this question why u kept parallel to xy

[@narasimha22]

Sir when the axis line is making 45degrees with vp then why o point in 3rd stage is not lying on the 45degree line

[@MUKESHKUMAR-ir4bl]

very nice sir thank you so much

[@ManasPatnaikofficial]

Mukesh.......Thanks for appreciating my work.... All the best in life And do share and recommend this channel to your friends and classmates so that they can also benefit... Cheers....

[@letwisdomgoviral2254]

greetings..why did u start with TV first ...Axis inclination is with VP??

[@pranjalchouhan5658]

A square pyramid has the base edge of 40 mm and height of 60 mm. Draw its TV and FV when the base makes 45° with HP and the axis makes 45° with VP.

[@bagg2290]

Do we have any app to get the solutions for CAED problems for projection of solids??? plz help me to get it

[@priyanshugautam5468]

Sir what if the angle 45 was given to be phi and not beta then how would we do...??

[@priyanshugautam5468]

Sir please reply I am confused..

[@priyanshugautam5468]

Sir I could'nt fund it in the comment section too

[@nareshkrtnaresh7357]

super Sir

[@ManasPatnaikofficial]

"THE MANAS PATNAIK LIBRARY" Topic-wise Playlist of Engineering Drawing / Engineering Graphics in English 1. Orthographic Projection: kzbin.info/www/bejne/jXiZeWWmfriIsLM 2. Projection of Point: kzbin.info/www/bejne/nHyXmWidgpxmrZo 3. Projection of Line: OLD: kzbin.info/aero/PLIhUrsYr8yHz_FkG5tGWXaNbIxVcibQvV NEW: kzbin.info/www/bejne/pquoYXdjfs-rmpY 4. Projection of Plane: kzbin.info/aero/PLIhUrsYr8yHx7TVB51jN3HZVyW3R6RiBg 5. Projection of Solid: kzbin.info/aero/PLIhUrsYr8yHxARPzEFz1nXgt8j6xF_tEm 6. Section of Solid: kzbin.info/aero/PLIhUrsYr8yHwAbiCATZUbzd_CpF0EHF3v 7. Development of Surface: kzbin.info/aero/PLIhUrsYr8yHwdB96ft6c0Uwc4SDCLuG1v 8. Auxiliary Plane: kzbin.info/aero/PLIhUrsYr8yHxHWk2TCg1SrphF1vKpHXoB 9. Interpenetration of Solids: kzbin.info/aero/PLIhUrsYr8yHyTGceE1TGhCSxxfHyFpnNM 10. Isometric Drawings: kzbin.info/aero/PLIhUrsYr8yHxVky7bfrnbRcdXcHjT_K83 11. Conic Sections: kzbin.info/aero/PLIhUrsYr8yHx0TuqsY0FUZ7Z24BbKxJoQ 12. Cycloidal Curves: kzbin.info/aero/PLIhUrsYr8yHwwA8eBea78pJW1lw9XAv6z 13. Involute: kzbin.info/aero/PLIhUrsYr8yHzu8pqYvGwQoJKVpuS1Jusa 14. Plain Scale and Diagonal Scale: kzbin.info/aero/PLIhUrsYr8yHwTgo_zu_ELqOC1ypcp5Gr9 15. Complete Engineering Drawing in one single Playlist: kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS Topic-wise Playlist of Engineering Drawing / Engineering Graphics in Hindi 1. Orthographic Projection in Hindi: kzbin.info/aero/PLIhUrsYr8yHy3chHVzYA4BMbY9DbhyYSY 2. Projection of Point in Hindi: kzbin.info/aero/PLIhUrsYr8yHwinNUxVA1NW0xxLRlDfINH 3. Projection of Line in Hindi: kzbin.info/aero/PLIhUrsYr8yHyvWb87YtG3A3jDEnChgzir 4. Projection of Plane in Hindi: kzbin.info/aero/PLIhUrsYr8yHxj9N5e1oZA0x_k5ZVssf3U 5. Projection of Solid in Hindi: kzbin.info/aero/PLIhUrsYr8yHylYPjrulRGm8DSPiimxP3P 6. Scales Hindi-Urdu: kzbin.info/aero/PLIhUrsYr8yHzJA426HjlEmiRqUkJTkozB 7. Section of Solids in Hindi: kzbin.info/aero/PLIhUrsYr8yHz2Sv6RNP9c5owe5Sic1IMC Topic-wise Playlist of Engineering Mechanics / Applied Mechanics / Fundamentals of Mechanical Engineering in English 1. Forces: kzbin.info/aero/PLIhUrsYr8yHzoyUutEK57JzWy1n-vxIS0 2. Friction: kzbin.info/aero/PLIhUrsYr8yHwY1TDraJpyYkU8Zug-kM4m 3. Shear Force and Bending Moment: kzbin.info/aero/PLIhUrsYr8yHy1lc0hEhbpEAGsGwNmUWt7 4. Trusses: kzbin.info/aero/PLIhUrsYr8yHwIXEt9cqjEsEO8l83xcIf7 5. Centroid and Centre of Gravity: kzbin.info/aero/PLIhUrsYr8yHzZ52dVA3wQ_0IQVl7CKL7p 6. Moment of Inertia: kzbin.info/aero/PLIhUrsYr8yHw8qWxAVOx-5Y2XfGPOmcDy 7. Dynamics: kzbin.info/aero/PLIhUrsYr8yHwOZxmY63A_lURu6c-jNk-z 8. Complete Engineering Mechanics / Applied Mechanics in one single Playlist: kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS Complete Playlist of ENGINEERING SERVICES EXAMINATION: kzbin.info/www/bejne/mZKYeqqep6iBmLM Complete Playlist of Machine Drawing: kzbin.info/www/bejne/n3emn3mLh556msU Complete Playlist of Theory of Machines / Kinematics ofMachines / Dynamics of Machines: kzbin.info/www/bejne/eaCXip-Xq6ijm7M

[@sknuralam7291]

A square pyramids, base 25 mm side and axis 50 mm long has one of its triangular faces in the H.P.Its axis is inclined at 450 with the V.P.Draw its projections when i) Apex nearer the VP than the base. ii) Apex furthest to the V.P. than the base.

[@venkateshh332]

lol he given the question in description bro

[@kartheekkuna1990]

How can we solve ......a square pyramid all edges of the base equally inclined to the HP ,and the axis parellel to and 50 mm away from both HP and VP ..... Can you please give me the solution to this e-mail..

[@aryanprakash2442]

Good morning sir why did you divide circle into eight parts in problem number 2

[@navooryamini5039]

What if the condition's are not mentioned like in this sum ?then how do we do the step 3?either from the apex nearer or farther?

[@ManasPatnaikofficial]

No issues..... Just make an assumption....

[@jimeetshah4330]

sir...from the 2nd step...Why dont we draw hidden lines from C and D?

[@eidimajid1104]

Sir can we see d'c' in step 3rd in case 2 or d'c' is hidden sir plzzzz explain

[@bhavyasri24]

Super video sir

[@vikasmeena876]

Sir apne last video me kaha tha ki If axis is inclined with vp Assume the solid resting with it's base on vp then the true shape of the base will only be seen from the front .hence you have to begin by making front view first But in this problem you start from top view and assume base resting on hp Why please help

[@ManasPatnaikofficial]

Iss playlist ka second video dekhna.. Usme 5 problems hai...... Mere khayal me ye problem 5th position pe hai..... Do watch it..... I will clear your doubts.... 5. Projection of Solid in Hindi: kzbin.info/aero/PLIhUrsYr8yHylYPjrulRGm8DSPiimxP3P

[@vikasmeena876]

@@ManasPatnaikofficial thanks sir

[@MrShrigiri]

very informative

[@ManasPatnaikofficial]

Thanks for your appreciation and support Sir Do encourage and recommend this channel to your students and fellow colleagues

[@hprameeth2917]

Sir what we have considered is a pyramid then how come did you get a prism in the final front view

[@ManasPatnaikofficial]

Prameeth....That is a Pyramid.....Look at those dark thick lines....

[@hprameeth2917]

Oh correct yeah....got confused

[@bhushanpande2174]

We are given the apparent angle and we need to change the apparent angle

[@mudhirajsailu1516]

Nice sir 👍👍👍👍

[@robinsinghnegi6768]

When to asaume 1 st step and when not

[@rohityadaav2709]

Tq sir such a nice video

[@asgarh4589]

Sir, u said that "If axis is inclined to V.P., then assume the solid resting with it's base on V.P."... But, here you are making the base rest on H.P... Why sir?

[@ameyadeole1189]

i can help you in better way in above video teaching method is wrong

[@gopalakrishnanganesan2127]

Sir, why can't we do it in two steps by assuming that it's triangular face lies on hp in the first step itself?

[@ManasPatnaikofficial]

try doing that.....i am sure you will get stuck....

[@rajpanchal9581]

we are not knowing the length of the 0' to c'd' so 1st step must be required

[@rajendramutyala8243]

Why we take 1st stage in that way only

[@maheshgouri4691]

super sir.

[@ManasPatnaikofficial]

+Mahesh Gouri Hi Mahesh.... All the best and do let your friends know about this channel so that they can also benefit.....

[@adamyabansal]

Hello sir.... Sir what will be the difference if given beta was phi....?

[@ManasPatnaikofficial]

It's a bit difficult to demonstrate via words. Message me in FB messenger

[@brainhax6758]

hello sir in case 2 , i got the third stage exactly the mirror image of yours, i.e. my apex of 3rd stage was facing 2nd stage top view or i measured 45 degree in opposite direction is it ok or wrong??

[@ManasPatnaikofficial]

Its right

[@saijaswanthasapu31625]

show the elipsedrawing.thankyou

[@tahreemfatima8363]

Sir, will we join o'a' in the 3rd stage of first case with dotted lines Kindly answer it.............

[@siddhantchavan1370]

Coz it's hidden in that specific view

[@mohamedadan1198]

Thank you more than much.

[@kalpanahedau2848]

sir If in question Apex is Away/Near the o server then how to draw it dis vdo is about Apex is Near The*VP*

[@ManasPatnaikofficial]

Well Kalpana, if it is near the observer, that means it is away from VP. And if it is farther from observer then its closest to VP. I hope u can now work it out yourself......

[@kalpanahedau2848]

Manas Patnaik Thnk u so much.....

[@sony-rn1op]

Sir, as it is given that top view of axis makes 45 degrees, why don't we follow the rule which we used in other problems like in planes in circle problem(true length of axis can be drawn at 45degrees and the axis length from second diagram can be taken as radius and an arc is cut on the line.)

[@kuttinkutt9568]

tnanks

[@ManasPatnaikofficial]

Hi Kuttin..... Thanks for your appreciation... All the best.... And do let your friends know about this channel on drawing and mechanics so that they can also benefit.....

[@tanishakhandelwal5174]

its beta and not phi

[@radhekrishna2477]

thnk u

[@ManasPatnaikofficial]

You are most welcome Radhe..... 😀Do share this channel and its playlist with your friends. 1. Engineering Drawing Playlist (ENGLISH): kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS 2. Engineering Drawing Playlist (HINDI): kzbin.info/aero/PLIhUrsYr8yHx0C3ebAW-FQxTP8ig8-QxU 3. Engineering Mechanics Playlist (OLD): kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS 4. Engineering Mechanics Playlist (NEW 2023-2024): kzbin.info/aero/PLIhUrsYr8yHxeypEyVdWeGNxWHjNxU_JP 5. Mechanics of Solids Playlist: kzbin.info/aero/PLIhUrsYr8yHzft7ygw5THZo4aDcsxEadP 6. Theory of Machines / KOM / DOM Playlist: kzbin.info/aero/PLIhUrsYr8yHx0aFXSQvT7nm6ivJSMKnAU 7. AUTOCAD Playlist: kzbin.info/aero/PLIhUrsYr8yHyLArdiiSDLa0Fmz8YKIy7G 8. Machine Drawing Playlist: kzbin.info/aero/PLIhUrsYr8yHzwT06rv7u3tqdfmmKOCz1w Visit Main Channel Page(@manaspatnaikmech) for Playlists on specific topics. Second Channel for Hindi Audience: @btechplus Download the Manas Patnaik App for Premium content : bit.ly/3wMRxoc

[@siddheshchaubal]

In the last stage, how come axis is making 45 with XY line? It will make some angle 'beta', right?

[@ManasPatnaikofficial]

Siddhesh Chaubal beta is infact equal to 45 degrees

[@pmsid7276]

tyvm

[@ManasPatnaikofficial]

You are welcome...

[@pavankolloju9416]

what is à and b' in last

[@ManasPatnaikofficial]

a' and b' are corner points in base edge..........

[@saivivek3037]

is he promoting polycab?hahaha

[@ameyadeole1189]

wrong way of teaching