Proof of Closed Subset of Compact Metric Space is Compact | L11 | Compactness

[@saistudent789]

Thank you sir... It was very clear😊

[@rohitthakuracademy2017]

Clean explanation.... understood very well.... thankyou very much sir for your efforts ❤❤

[@enigmogaming8604]

Best explanation on KZbin

[@n.k.7825]

Thanks 👍

[@sonalidhanwate3164]

Thank you 😊 sir

[@gopinathan2095]

I was looking such a person like you sir... Really you are doing great job... I'm learning a lot from you... Your explanation is very good and mastery...

[@ranjankhatu]

Thank you so much. Such comments always motivate me to create more videos.

[@rajshantanu]

Doubt (at around 3.50th min), If G = H intersection Y, where H is an open subset of X and Y is a closed set, isn't is possible that the points of H which lie on the boundary of Y, do not have any open ball which is contained in Y ? Because that will mean that there exist some points in G (the points on the boundary of Y) which do not have any open ball contained in Y (since Y is closed) and therefore, G does not remain open in Y.

[@keshavlalit1555]

Sir kya compact matric space k kuch lectures missing h playlist me ya total itne hi h

[@ranjankhatu]

I am working on it now

[@keshavlalit1555]

Ok sir

[@ARVINDyadav-ve9dt]

plz🙏🙏🙏🙏🙏🙏 sir aap bhut acha padate hai but hindi m bol diya kro plz plz

[@shashank_kishore_]

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

[@smarty_samkhan]

U r doing such a fab job,..U r making horrible M.S subject a cup cake which is very easy to eat... Do u teach algebra as well??

[@ranjankhatu]

Yes. But not uploaded videos yet. We will start it soon.

[@ARVINDyadav-ve9dt]

sir plz in hindi