Never thought I’d learn maths from Arnold Schwarzenegger
@mathwithalex Жыл бұрын
Stay tuned. I'll be BACK!
@winonamama8358 Жыл бұрын
boy what are you saying
@mtaur4113 Жыл бұрын
Needs more parentheses to be totally clear on the log rules. Maybe even square brackets at some point to get out of nestsd parentheses hell. Implied parentheses for ln x^p is kind of slippery, especially when writing ln(x^a)^b to mean ln( [x^a]^b ) when it looks more like [ln(x^a)]^b.
@mathwithalex Жыл бұрын
I see. There could be some confusion. Thank you for pointing that out.
@curiousaboutscience Жыл бұрын
That is pretty cool to see worked out!
@mathwithalex Жыл бұрын
I appreciate your ongoing support. I'm enjoying watching the videos you upload as well!
@mathwithalex Жыл бұрын
For the exciting proof of the Euler number used in the video, take a dive into the rabbit hole through this link: www.youtube.com/@mathwithalex/community Your curiosity is appreciated!
@Jan_Heckmann Жыл бұрын
Hello there! I see that you proved that e=lim x->0 of (1+x)^1/X three different ways. But is it true, that only the second prove counts? Because the others use the derivative of the natural log, leading to a circular reasoning.
@Nzargnalphabet10 ай бұрын
I’ve actually always preferred the infinitesimal definition of derivative, it makes more sense and you can kind of just plug and chug, but limits are cool too I guess
@mathwithalex10 ай бұрын
Thank you for watching. Please feel free to leave your opinions in the future as well. Thank you.
@davannaleah Жыл бұрын
How about: y = ln(x) So x = e^x dx/dy = e^x which is x So dy/dx = 1/x
@mathwithalex Жыл бұрын
You're referring to "x=e^y," right? It's a quick and convenient approach! Thank you for the great feedback. Please continue to share your valuable insights in the future.
@davannaleah Жыл бұрын
@@mathwithalex Ah, yes, sorry... mistype
@mathwithalex Жыл бұрын
No problem at all. I make typos too often. I wrote it down so that others can see and understand. Thank you.
@MH-sf6jz Жыл бұрын
Have you proven the inverse function theorem?
@mathwithalex Жыл бұрын
I apologize, but the video explaining the proof of the inverse function theorem is not yet prepared. I will add it to the upcoming video list. Thank you for your valuable suggestion.
@nicolascamargo8339 Жыл бұрын
Saludos desde Colombia
@mathwithalex Жыл бұрын
Hola. Gracias. Saludos desde un coreano que vive en Singapur.
@nicolascamargo8339 Жыл бұрын
Wow excelente
@mathwithalex Жыл бұрын
Voy a seguir viéndote en futuros videos, esperando siempre contenido excelente.
@mndtr0 Жыл бұрын
(lnx)' = ln 😅
@mathwithalex Жыл бұрын
haha~ 😄
@sigmascrub Жыл бұрын
This gave me a chuckle 😂
@mndtr0 Жыл бұрын
@@sigmascrubI'm glad that you have fun ^^
@adrified9352 Жыл бұрын
Funny joke
@loich.9133 Жыл бұрын
ln(x) is not a function, therfore you can't write (ln(x))'. ln is the function, you must write with this notation ln'(x). It's like f(x). You write f'(x), not (f(x))'
@samueldeandrade85359 ай бұрын
Shut up.
@TranquilSeaOfMath10 ай бұрын
Very nice. Done like the pro you are. 🧮 Cheerful Calculations!