At first I thought we could prove this by just assuming that each set has some elements for A= {a} or B= {b} then we could show that p(A)= {} and {a} and p(AUB)= {a} {b } and {} but the subsets in p(a) cannot be shown in a union so this method probably won’t work
@ANKITCHAUDHARY-wr8px10 ай бұрын
Thanks
@fernandocupil.64632 жыл бұрын
Hola bro. Buenos videos. Deberías hacer un review de los libros Calculus by Tom Apostol. Saludo!
@VinodKumar-wt3nt2 жыл бұрын
Brother can you please do a review on G.S Carr book (A Synopsis of Elementary Results in Pure and Applied Mathematics)🙏🙏❤️❤️