Thanku so much sir jii kl mera paper hai apki videos sy mjhy bht mili Allah pk apko is ka ajar dain 🥰
@abujar.7869 ай бұрын
Mera to abhi he 2 ghante bad😂
@MuhammadHassan.official1559 ай бұрын
Mera bi kal h😂😂😂😂@@abujar.786
@umarafzal80094 ай бұрын
Deserve more than 5M subscriber and 10M views on one vedio
@azcomputing4 ай бұрын
thanks, Your appreciation means a lot to me
@poonamraut17692 жыл бұрын
Thank you sir , college me khuch smj me hi nhi aya tha ab smja
@chtalha97733 жыл бұрын
Excellent bhai very helpful video
@umarafzal80094 ай бұрын
Sir kmall method❤❤❤
@sdansari7541 Жыл бұрын
Wonderful Explanation❤❤❤
@muhammadidrees41293 ай бұрын
What an explanation ❤
@maazali9672 Жыл бұрын
such a great explanation😍😍
@SidraBibi-ho7riАй бұрын
Thank you sir 😊
@muhammadhamzakhan9695 Жыл бұрын
Thank you sir! excellent work
@malikshahban262010 ай бұрын
I like your efforts ❤❤❤
@vedantsalvi55364 ай бұрын
thank you sir
@nimrawani75742 жыл бұрын
Thank you sir its really help me
@azkaaziz66663 жыл бұрын
Very nice explanation
@sharoontariq Жыл бұрын
Mza agya
@arsientertainment37433 жыл бұрын
Thanks sir this video is very helpful and good
@azcomputing3 жыл бұрын
Welcome
@tech4inspiration6192 жыл бұрын
@@azcomputing sir ma nay pumping lemma for non language wali example may X=3, Y=4, Z=3 put kiya ha or jab Y ko pump kia ha to wo a^n and b^n equal aa gya ha, please guide me
@nawabzadi678 Жыл бұрын
@@tech4inspiration619the ending string will be aaaaabbaabbbbb which is not in the language as their is a sequence required in the question that number of b's must be followed by equal number of a's so it's non regular language
@laxmilodhi38903 жыл бұрын
Thanks sir
@Digitalmind2245 Жыл бұрын
Nice sir 🥰
@SmilingChefHat-wh9suАй бұрын
Difference between pumping lemma for CFLs & pumping lemma for regular language?? Is these are different from one another? Answer me plz...
@shadman.edu1234 жыл бұрын
Zabardast bro
@a.jgoldhouse3 жыл бұрын
Good sir
@UsmanGenius9 ай бұрын
What in the case if starting condition is ab and ending is bab, in that case I found pumping lemma is giving false result, is it?
@ArshadMehmood-qk7hw Жыл бұрын
❤❤❤❤❤❤
@MadGenious Жыл бұрын
What if we divide S in such a way that X Y and Z still follow the Description even after Pumping Y? For example, instead of considering Y as 4 b's after the 1st b.. We consider Y as the middle, 3 a's and 3 b's? So when we pump, it will still satisfy the RE.. The point is, whaat is the criteria of division of S between X Y and Z?
@arehman33043 жыл бұрын
Dear Sir, Thank you for the explanation. I am watching your videos from Italy and My exam is on 26th January 2022. My professor taught this topic in a very different method. I just need to ask that how do we prove it in a mathematical fashion.
@azcomputing3 жыл бұрын
First of all thanks for watching. Yes, there are different and multiple methods to cover a single topic. Similarly we can prove it in mathematical fashiin in different ways. Basically, pumping lemma is used as a proof for irregularity of a language. If a language is regular, it always satisfies pumping lemma.
@BollywoodUniversity7862 жыл бұрын
Jazakallah sir. You're method is great Sir agr a ki power 834 Or b ki power 733 Ya kasy slove krny gy Kindly tell me
@fairystar48693 жыл бұрын
Sir plzz myhill nerode theorm ka bta dain..,possible ho tu kal tak ...perso sham ma paper h
@ahmedraza6101 Жыл бұрын
Very nice explanation sir🤌👌
@baseermalik829Ай бұрын
kindly map it on any regular expression please
@arehman33043 жыл бұрын
I would love to hear from You if you could provide these mathematical proofs using pumping lemma: L1 = {a^p b a^q b a^q b a^r | p, q, r >= 1} L2 = {a^p b a^q b a^q b a^q+r | p, q, r >= 1} L3 = {a^p+q b a^q+r | p, q, r >= 1} State whether L1, L2, and L3 are regular languages, and provide mathematical proof.