Work and Energy 04 | Numerical Practice Session | Class 9 | NCERT | Sprint

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[@PW-Foundation]

📝Download Lecture Notes From PhysicsWallah App : bit.ly/2SHIPW6 🎯 Science group- t.me/joinchat/RYszj_1cAl8xEvnv 🎯 Social Science- t.me/joinchat/GCBE5bDgFdxrZeI8 🎯 Mathematics group- t.me/joinchat/GBbG4p5S_OVRV920 ----------------------------------------------------------------------------- 🗓️ Scheduled Syllabus For Sprint ( Class 9th ) released describing which topics will be taught for how many days. Available at PhysicsWallah App :bit.ly/2SHIPW6 •Duration:-1 month (Jan 2021 - Feb 2021) 🎉 Free Batch Exclusive on our KZbin Channel : Physics Wallah Foundation - 9 & 10 •Batch Details : 1) Best Faculties across India for different Subject/Topics. 2) Complete & Relevant Syllabus Coverage of Class 9th within 1 Month - Fastrack January 4,2021- February 15,2021 3) Monday - Saturday : Scheduled Classes everyday. •Physics : Tuesday, Saturday •Chemistry : Wednesday , Friday •Mathematics : Monday, Wednesday, Friday •Biology : Wednesday , Thursday , Saturday •S.ST : Tuesday, Thursday, Saturday, Sunday 4) Scheduled Syllabus released describing which topics will be taught for how many days. Available at PhysicsWallah App :bit.ly/2SHIPW6 ----------------------------------------------------------------------------- OUR SOCIAL MEDIA PROFILES : ⭐Instagram Handle : instagram.com/physicswallah/ ⭐Facebook Page: facebook.com/physicswallah ⭐Twitter Account : twitter.com/PhysicswallahAP?s=20 ⭐ PW App on Google Play Store : bit.ly/2SHIPW6 ❤️ Padhai Karte Rahe, All The Very Best 👍

[@creature3d249]

Sir plz sound chapter par bhi lecture layiye🙄 We are waiting Plz plz plz...........infinite

[@samiullah2732]

Sir i sayed to u that there are no more lectures of u

[@samiullah2732]

Iam from pakistan so near with afghanistan

[@PrabhatKumar-be2le]

Sir sound ch hoga 🙏🙏🙏🙏🙏

[@kanchansoni8083]

Sir PW app par lecture notes nahi mil rahe hai sir please 🙏🙏 help me out.....

[@Ayanshs516]

The best thing I like on this channel is that they teach on a black_board due to which I can study for hours and it does not affect my eyes.❤️..in other channels the board is white and I get headache after looking at the screen for too long..THANKS PHYSICS WALLAH FOUNDATION

[@SMARTअमृत]

Bro Its Not blackboard 😂

[@SMARTअमृत]

@@kapoor7306 why are you abusing

[@kapoor7306]

@@SMARTअमृत chl nikal yaha se pehli fursat me😂

[@kapoor7306]

Ka e babu

[@SMARTअमृत]

@@kapoor7306 achha but kyu niklu bhai batao

[@Bgmi_wala3656]

Sir school 🏫 wali madam aapka number mang rahi thi 😂😅📱 Thnx for 500 likes🫶 Subscribe for more amazing jokes😂👍

[@krish_yadav__012]

To de do

[@krish_yadav__012]

Gf Banna hoga 😅😅

[@princeg9991]

Sarr ki life set hai 😊

[@Ayushnain250]

❤❤

[@KishanNandi-h7u]

Setting kar Raha ha 😎👌

[@nayangupt]

Sir It was my exam today and the exam is very easy thank you alot..🥰

[@ananyaguptavlogs2861]

I wanted this type of teacher for past so many months....... Ahh... Super thanks for teaching me .if who think I can't solve u can do it bcz if I can do nobody can do.... 🙂🙂

[@chhayakatendra5267]

How much you got in class 9 physics

[@shaifali6737]

In last solution, ita = nothing in , everything is out

[@shaifali6737]

Out of mind 😂😂😂

[@BCCCUBER]

7:35 it's wrong when velocity is tripled KE= ½m(3v)² Ke=½(2)(3×5)² Ke=(15)² KE=225 Joule

[@iayt2284]

Bruh! Velocity isn't tripled,it is increased by triple,it means 3V is added in previous velocity,i.e [5+3V] Putting in ∆ K.E. M/2[ (v)^2 - (u)^2] i.e, 2/2[ (5+3V)^2 - (0)^2] J 2/2[ (5+3×5)^2 - (0)^2] J 2/2[ 400-0] J 400 J

[@foodiezagg5698]

​@@iayt2284😅

[@tdmaster9965]

8:02 sir K.E. of the object = 25 J Velocity of the object = 5 m/s K.E = 1/2mv2 m = 2×K.Ev2 m = 2×25/25= 2 kg If the velocity is double, v=2×5= 10m/s Therefor K.E (for v = 10 m/s) = 1/2m2 =12×2x100=100J If the velocity is tripled, v=3×5 = 15 m/s Therefor K.E ( for v = 10 m/s) = 1/2mv2 = 1/2×2x225=225J

[@db_2408]

I also got 225 J. Sir did a calculation mistake. He multiplied 5x4 instead of 5x3.

[@_jk75_]

Sir is right because .....it was mentioned in the question that if the velocity is "doubled" and next one was ' velocity is "increased" triple'. Hope u understood but even u face any problem, go to 7:22 and listen him carefully.

[@niranjanbiswajith9482]

u are crect

[@niranjanbiswajith9482]

@@_jk75_ how will we get 20 if 5 is multiplied 3 times

[@_jk75_]

@@niranjanbiswajith9482 not only 5 is multiplied into 3.....but it is also increased....means 5+(5×3) understood???? Go to 7:20

[@jauharaftab2935]

thanks for always being there. u make every thing look easier, to be super honest u r one of the best ever. EAST OR WEST, PW IS THE BEST.

[@icc6780]

Sach mein kya

[@sterlinglifescience9520]

Aftab Bhai app kha se ho

[@rishikasethi6495]

sir in Q3 ans for velocity increased by 3 times will be 225 J and not 400 J. as they have said 3 times which means 5x3 = 15

[@kavyanavyashow4644]

I was confused about it too... I thought i was the only one who got it wrong...thanks to your comment 😂❤️

[@adityapandey7674]

@@Allinone-cm5rc kaun sa nasha kiye ho hume bhi batao zara

[@SarojSingh-vl2kj]

@@Allinone-cm5rc yes ur correct

[@SarojSingh-vl2kj]

@@kavyanavyashow4644 no ans is 400 only it's increased by 3 times

[@hegxer_editssubscribtions4545]

Yup exactly

[@xd3835]

8:15 , sir if you had taken 10m/s (5*2) in the first part which asked for KE when v was doubled then you could've taken 15m/s (5*3) in the second part of the question as well. You have used two different concepts in the same question.

[@simran_visuals]

Yes , ur right !

[@TECH-SUBHU]

Yes , same i was thinking that

[@bruhamit]

Bhai ye teachers log jab questions solve krte hai to nervousness me Inka bhi answer galat ho jata hai

[@monikakaushik4372]

Qsn me given h incresdt it mns apko 1st velocity (5) me 3 times velocity ko inc karke add Krna h so 5×3=15 and 15+5= 20😊

[@Rohitsingh_16]

I've studied first four physics chapters of 9th ncert for my cds exam from you. Now I'm able to solved all previous year questions of physics cds. A big thanks I am sure on this cds 2 2023 I will do all question of physics 9th ncert. 🎉

[@sakshitiwari3456]

Funny hogua

[@brajeshpal7756]

Most brilliant teacher of physic🙄❤️❤️❤️

[@parthaojah9109]

No doubt

[@shivanshraikwar7358]

Agreed

[@RaviYadav-no6nx]

Sach me yar

[@rockstar892]

Yeh koi kehne Wali baat hai He is best teacher

[@ayushi_singh118]

😂

[@swastiktiwari75]

*I recommend everyone who is doing full revision of physics to start revision of topics from this chapter because this seems to be pretty easy and simple to understand with a bit of practice of numercials and understanding concepts.*

[@umking1952]

My favorite lecture session because theory are available in many plateform but this type of numerical practice is done only here

[@rushilg5679]

who asked

[@rushilg5679]

@Aarya Suparey nahi degi

[@meharbano5653]

Thank you so much sir...amazing teaching skill🙌

[@vansh_1090]

Thanks sir ! This chapter is now piece of cake for me :)

[@priyankagrover5557]

Í Øhhhh

[@chhayakatendra5267]

For me it is whole cake cause this ch seems very easy after watching sir's lecture and I like cake so... 😂😂😂

[@AKGAMING-vy4id]

P.w thanks sir

[@AKGAMING-vy4id]

😅🤣😅😇😍🤩🥰🤯🤠🥳🤬😡😠😈😤😭

[@bgmiop6803]

@@chhayakatendra5267 full komedy

[@aditikumari8657]

You are a very good 👍 teacher for physics ☺️☺️ sir

[@itz_amit_xvii]

Hm

[@kingofallsports786]

Hi

[@prachisharma9289]

In third question answer of three times of velocity will be 225 J not 400 J. Love you PW platform

[@AdityaSrivastavaE]

Sir Please make lectures on Sound , as we need them for Olympiads ... 🎖️🎖️

[@dhruvsharmatech9376]

Ooooo

[@saurav8272]

Oo

[@Ind-VIDENCEPvtLtd]

O

[@mohitmaheshwari3727]

Ooo oooo ooo oooo ooo oooo ooo oooo ooo

[@laxmigaur7993]

Yes sir please make some more numericals on this.....

[@ANIMEVERSE6655]

42:55 best moment "Are waah kuch to solve karne layak hai yaha"

[@ananyaguptavlogs2861]

I have passed my exam and it well so good...... Thanks to all the three teachers 🥰

[@sh1ko_ae]

Pass krna hi important nhi Hota achhe marks laane se Hota hai

[@rushilg5679]

who asked

[@ananyaguptavlogs2861]

@@sh1ko_ae abee pass matlab ho chuka h

[@ananyaguptavlogs2861]

@@rushilg5679 who said to read😑

[@pearl_yyy]

Sir tusi great ho bohot badhiya padha rhe ho sir we r so lucky to have study with such a huge nd perfect platform i am so thankful to all pw team❤️

[@hireshdevi9733]

One of the best teacher in class 9 physics by pw 🙃

[@rptcreation892]

Rakshak Sir Op ❤❤❤ Awesome explanation 😍😍😍

[@aakarshsrivastava1579]

43:39 to 43:43 the line is the best line for a physics lover.

[@lanlantopgamer4674]

0:01 hallow bachooooo

[@बाबुलालबाबूजी-ष9थ]

Sir you are the best teacher of physics. You are the god who save me. 🤗💯

[@niyatii12]

Sir you have read very well😊and I understand very well😄😄thank you for this...now I will read for your own channel...thank you so much sir...🌸🌼

[@dalibhakhar148]

It really helped me a lot💜

[@kavitamishra7728]

Sir trust ,pressure, up thrust, density, relative density and force exerted by liquid karwa do sir plssssssssss

[@ramandas6602]

Ek video hai espe Jake dekho

[@hariramjat8769]

05:23 sir answer is Hence, when the velocity is doubled its kinetic energy is 100J and when the velocity is increased three times its kinetic energy is 225J.

[@shambhusharansingh3150]

Ha

[@NaveenKumar-cg3oi]

Yeah 😊

[@princevarshney2131]

Right[velocity three time increase hogi to 15 ayaga]

[@rockstar892]

Hmm

[@puneetkumar1625]

Tomorrow is my exam and I was not clear with lots of concepts but after this vedio I am Fully ready to score good marks. thanks sir

[@fakebedo_op4765]

Thoda marks batana kitne mile science mai and be honest 🤬

[@sh1ko_ae]

@@fakebedo_op4765 whi toh! Ek din phle padhta hai aur woh bhi bol rha hai ki concept bhi nhi pta thaa bsdk. Ek din phle padh ke ghanta marks aayenge

[@moltiagaming]

Mera hogya hai dimag kharab bhai puri video dekh ke questions solv kar liye but at last mene dekha class 9 ke questions hai aur me 11 me 😅😂

[@twobrothergamer8537]

Lol😂🎉

[@AnkitSingh-hv4hc]

Amazing person I have seen in my life 💖🎈

[@pardhanplaz3501]

Starting 🤣🤣helloooooooooooooo bachoooooooooooooooooooo😩😂😂😂

[@ArshDeepSingh-l6s3f]

Hellooooooooooooooooooooooooooooooooooooooooooo bachooooooooo😂😂

[@AnaghMishra-tf2zl]

Helloooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo Bachooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

[@tanveerraza2026]

Sir in. Question number 3 the velocity will be thrice so, the value of velocity will be 15 and the kinetic energy is 225 J. (It is given in S.Chand side book)

[@kshitijghate6895]

13:27 was my favorite part ever.

[@gautamchoubey1275]

My also bro 😂😂

[@nidhidubey6606]

same here.....

[@poojaranisahoo6777]

8:27 If the velocity would become thrice then it should be 15m/s.And The KE is 225 J

[@poojaranisahoo6777]

@@Triggered_nisch Yeah

[@user-ky1dk7tm8z]

Yes

[@tsyondazr5251]

thats nots the case since it is increased by triple that means velocity (v) + (3v) since it says increased so the orginal + additional

[@blank1967]

It's written is increased three times

[@nagpatneyShourya]

@tsyondazr5251 by that logic the above question should be v +2v by which the answer should be 225 J

[@sushilapoonia3946]

Thank you sir now my all doubts are clear

[@pransu1579]

These numericals will be really very helpful for my upcoming Science Annual Examinations

[@pranavdwivedi3527]

Challengeer questions answer is 658235kg . ( Caution - in this question while calculating last question numerical no brain was harmed use of calculator is strictly necessary in that)

[@ahanachanda7221]

i did it all using my own brain and still got the right answer🙂

[@pranavdwivedi3527]

@@ahanachanda7221 you are human calculator

[@shubhamkori5842]

Best teacher ❤

[@tsslimasultana1307]

Sir question no 3 3 times increased in velocity means 3×5 =15 and (15)² =225 it's correct answer is 225 Thank You Sir 😊 🙏

[@pratiksharma9895]

Sir I get 99 percent in my final exam thank you sir for your support 😊😊

[@beastboyfaiz1196]

How

[@pratiksharma9895]

Hlo bro firstly apko apna self notes bana hai aur pw sai hi padh lai aur ncert bana lai aur revision bar bar kar baas kafi hai ​@@beastboyfaiz1196

[@LuckySingh-yh5mx]

Sir , with the help of my mind I find ans.of last ques. It is .. m - 5.59(10⁷) kg Thanks a lot sir for teaching too much good

[@hkmathematicsclasses2037]

You are the best teacher in world

[@programerz3224]

Q.12 if he is on earth then his mass is 50 so weight is 50×10=500N P=W/T P=f.s/T P=500×6.75/0.0025 P=1350000

[@pokegamer4403]

Time is 9 second not 0.0025 hr

[@programerz3224]

@@pokegamer4403 9second hour=0.0025 hour!

[@pokegamer4403]

@@programerz3224 we have to go with si unit which is watt and 1 watt means 1 joule of work done in 1 sec

[@programerz3224]

You can't understand

[@aaquibkhan1612]

sir , you teach really very great

[@ankushtantuway6988]

Thank you sir aap se padke poora samajh aaj ata hai mere sir kuch nahi padhate hai thank you physics wallah foundation thanks a lot sir ❤❤❤❤❤❤❤

[@All_gay_are_asshole]

Q4 it should be converted into meter.

[@nalnikotwal2170]

wdym?

[@larvaml4439]

Same

[@amitbarannayak7751]

16:41 Chalo lines complete karte hain Suniye to Rukiye to Arre kyun hai khafa Aisi kya jaldi jaane ki Ohhhhoooo

[@pihu09817]

Sir lectures for sound also .🙏 Please ,please, please 🥺🥺🥺

[@rajnish6414]

Yes sir

[@HARSHIT_0012]

Sir in question 3 its velocity is increasing 3 times means it's velocity becomes 15 so the answer would be 225 Newton you have put velocity 20

[@anmolkatoch9274]

31:53 answer is 3750 watt

[@itz__sam_14]

sir question no 3 answer will be 225 joule when its velocity will be increase by three times

[@itz__sam_14]

@@monk_mode786 No that was wrong if velocity increase doubled it will be 10 and if we triple the velocity it will be 15 just ask you teacher what will be the answer if not search in google

[@manjurani6859]

Sir your speaking style is amazing 😎 Loved the session 😁☺️

[@muskanpatel446]

3 rd question second part wrong answer sir K.E. of the object = 25 J Velocity of the object = 5 m/s K.E = 1/2mv2 m = 2×K.Ev2 m = 2×25/25= 2 kg If the velocity is double, v=2×5= 10m/s Therefor K.E (for v = 10 m/s) = 1/2m2 =12×2x100=100J If the velocity is tripled, v=3×5 = 15 m/s Therefor K.E ( for v = 10 m/s) = 1/2mv2 = 1/2×2x225=225J

[@deepaksharma-gp5de]

Sir Q.5 Ans is 208333.3

[@HELIOS677]

But how?

[@supriya_3125]

Wht I say about uh sir...🤭I have literally no words for ur amazing explanation.🤩....u r really a geniussssss🙏🤗.......I lv ur way of teaching....😉

[@syednaqvi2340]

True 👌🏻

[@tannu5548]

Hey supriya you know me 😁😁😁😁😅😅😁😅

[@syednaqvi2340]

@@tannu5548 no I don’t know u😂

[@syednaqvi2340]

@@tannu5548 I know😄

[@tannu5548]

@@syednaqvi2340 ohkk

[@GuptaFacts007]

Sir apne q no 3. Me part 2 three times increase nahi jod diya hai Galat hai answer 225 Joules hoga

[@shahnuma3351]

Sir Please Thrust And Pressure And Fluids Pressure And Buoyancy

[@Nisun_Hansda]

Same question of Q.n 6 Solve this An object of mass 10 kg is at a certain height from the ground. If the potential energy of the object is 500 J. Determine the height of the object relative to the ground.(g=10 m/s)

[@AGGaming47]

5m answer hai

[@Just_bit-gaming1k]

@@AGGaming47correct same 👍

[@indiasbest1164]

Sir q no 10 ko karne ka kya mera bhi tarika sahi hai. 1 device use in a day :~ 10 hour 4 devices uses :~ 4×10 =40 h. 1 divece use energy ,500 w Then = E =p×t 500×40÷1000 Hence ans. Is 20 kwh

[@rakeshVerma-fi8tw]

Galat h bro 1 day m 24 hours hote h 40 hours nhi ho skte

[@Nishit77]

Best Tutor

[@Ankurnarula-vachaan]

This man proves physics is not boring

[@rolird624]

Yes

[@nafisahossaini.7456]

Ha boring nhi hard hai physics.

[@jayneelkhandelwal4508]

Good sir best sir Zindabad physics wallah.

[@brajeshpal7756]

Sukoon mil gya❤️❤️❤️

[@adityaprakash4745]

Sound Chapter pls

[@creature3d249]

Awesome sir my all doubt are cleared Thankyou so much Rakshak sir Love u sir so much 😊🙂🙂

[@MahakalBhakt-0]

Sir ji q3 mai apka if v increase 3 time mai 20 aa rha hai lekin ana 3multiply 5 ayega Mtlb 15 aur total ans second ka 225j ayega

[@pratimsaha7684]

thank you sir for making physics so much interesting .. i really appreciate your efforts from the core of my heart.. really you are my idol... if someday u see my comment please give a reply.. it will make my day...

[@rockstar892]

Same with me

[@AnkitRaj-kl4lw]

sir ans of 3rd question will be 225J not 400 J because it is increased by 3 times so 5*3 = 15 then K.E. =1/2mv^2 =1/2*2*(15)^2 =225J ....ans

[@meenajain7109]

*Sir we want sound chapter please*

[@SanjaySharma-dh3fr]

Sir class 9 ki menti quiz kar lo plz🙏🙏

[@tappukepapa4984]

yeesss sir plz kyunki Class 9 ka 80% students ke exam 1st ya 2nd week ke Mar mai Hai

[@vaishnavisingh6654]

@@tappukepapa4984 ha 1st March se

[@rinkujaiswal3202]

Finally uploaded

[@RiyaKumari-ps5gu]

Question no. 3rd when velocity is three times. Solution is false . Correct answer is 225 joule..👍👍👍👍

[@shivbhalake2751]

Sir main Maharashtra board Se hu muzhe foundation Karna hain Sir muzhe physics interesting lag rahi hain because of you Thanks sir

[@sanjana5706]

26:44 "shuru kree" Mayo japan 😁 I know

[@Pragati_23]

Me too😁😁

[@kishankumarsinha6167]

I love your teaching style like no one can do it wow wow

[@poojaranisahoo6777]

16:41 Waaah! Waah! Waaah! Wah! 😂🤞🏾

[@shahastabegum914]

Sir when velocity is three times then kinetic energy is = 225

[@Neet-y8t]

Kinetic energy is increased 3 times, so it is 5×4=20 , 20×20=400

[@Sparrowyt150]

No it will be 400

[@Sammyyyyyyyyyyyy]

8:20 sir here when the velocity will be increased by 3 times, the kinetic energy will be 225 J and not 400 J

[@almas003]

It's not said that the velocity became thrice it's said that the velocity is increased three times that's why it will be 400J

[@Sammyyyyyyyyyyyy]

@@almas003 You can check the answer in google, it says that the velocity will be 225 J Since; mass= 2 (already found) and velocity= 15 (the velocity is increased three times, the v given in the question was 5. But when it is increased by 3 times it becomes 15 as 5x3= 15) the formula to calculate K.E is 1/2 x m x v^2 So, as we put these values in the formula. K.E= 1/2 x 2 x (15)^2 = (15)^2 = 225 J Therefore, it was just a mistake made in the video.

[@danec955]

Helo sir, the way u explain is clear and understandable.. thank you !!

[@magicalshorts3864]

👋

[@abcdefghijk749]

What is the work done by electrons moving around nucleus? Justify your answer

[@inspectme_7]

Thank you sir Such a nice session ❤️

[@malikrinku5]

Sir I am Ankit Yadav from bidfaram sir I solve maximum numerical s

[@ziyafatma8851]

Nice lecture sir.....😇😇😇

[@curositygotech5064]

5:03 *Me confused with 120J till he turned back to correct it*

[@omparkasharora2598]

Sir 7 numerics me na Pe is equal to ke so itna karne ki need hi nahi padagi because if 2000j is pe then ke is also 2000 And its half will be 1000

[@divyanshigupta131]

Sir kya gate hai aap wah 👍👍😂😂😂😂 16:40

[@bhaikisolutions3932]

One shot video in sound chapter because my exam start 22february

[@kunalaggarwal9834]

Nhi aarha wo😂😂

[@shashiacademy]

Thank you sir

[@immortalnoob123]

I really dont believe my maths that much but as far as I know the challenger questions no. 2 answer will be 658235.3 kg (I used a calculator just in case and it was obviously correct :) )

[@demonslayer1158]

Sir times means multiple or multiplication

[@rizwanyunusphysics5566]

Nice explanation

[@swatibajpai4027]

Thanks for physics

[@rekha7998]

Sir please teach sound chapter also..

[@narayanaswain5724]

The way and seriel wise you explained all the thngs are relly awesome thank you very much love you sir and wish you a very happy life always and sir bless us for our coming exams

[@ashishop4257]

7:57 iska ans 225J h 400 J nahi

[@rizulsaini8128]

sir ne velocity 4 times kar di thi par question mei likha tha ki velocity 3 times karni hai

[@Sparrowyt150]

Sahi hai 400J mahashae

[@meditationwithmotivation4764]

Thank you so much for the ncert question

[@anuverma23498]

Maza aa gaya sir🤗