PYQs on Residue and Integration | GATE 1996 to 2023

[@dhirensasmal9547]

Most Talented Teacher in world. 🎉 namasta (🙏 ) sir . Very helpfull lecture.

[@Manish-uq5le]

Every videos provided by you very helpful to us. Thanks a lot❤

[@rnithyaraj9498]

Thank you sir Please upload videos related to Abstract algebra

[@rajar89]

Very very helpful for gate exam.. thanx sir ❤

[@DrHarishGarg]

Glad to hear that

[@KomalKakadiya-o2n]

Awesome work keep it up sir it's very very helpful for csir net exam

[@ayanamaiti2823]

Thank you so much sir! I learnt so many new tricks from this. Thank you so much for your efforts ❤

[@priyankaagarwal7429]

Love it......Kindly upload the videos of abstract algebra...

[@DrHarishGarg]

Will upload soon

[@Manish-uq5le]

​Will you sir.......I am waiting​ eagerly@@DrHarishGarg

[@celinjoseph-x4s]

Yes waiting for it sir

[@Siyagupta52]

@15:36 the correct answer is (b) As we write 2Rez=(z+barz) and then the singularity will be at 0 also. It becomes z/(z+2)+1/(z(z+2))

[@sandipkrhazra4207]

In question gate 2021 ,1/2πi$e^z/(e^z-2)dz when applying argument principle 11 zeros lies in R and no poles so answer should be 11

[@ratulchoudhury9144]

1:29:03 correct answer is 11.

[@yuvat9241]

1:29:03 how

[@mathematics6587]

Pls upload abstract algebra pyq sir.

[@vishalagrahari2670]

Sir 14:30 pr aapne jo Q. Me circle banaya h wo limocon hoga na. To winding number 1 ke liye 2 hogi aur 3 ke liye one so option c correct hoga na please check sir.

[@vishalagrahari2670]

Sorry sir option a will be correct

[@kishanchaurasia5250]

Definitely

[@RajendraGupta-cs7pb]

Your way Of teaching is very good.

[@sonalsharma266]

this was very helpful sir, thanks a lot. please make one with taylor and laurent series gate pyq questions.

[@smaranikabiswal3439]

Thank you so much 🎉🎉Sir❤ very helpful video 😊

[@diyasingh3579]

Thanks alot Sir...sir could you please upload videos related to abstract algebra.

[@somduttakayal5067]

Thank you sir for this video. Please upload videos related to abstract algebra

[@tarun7412]

Thank you sir❤

[@DrHarishGarg]

Most welcome

[@pampidas7151]

Thank you sir, apka podane ka andaz unique hai. Sir aap, NET ki coching korate ho? Keise join kore?

[@mathsbynijajangra]

Sir please upload pyq of function of several Variables

[@Manish-uq5le]

Thanks sir ❤

[@Pkmaths-c3o]

Sir sinz/z^8 has no pole its essential singularity so by expansion we get residue .may true

[@khrishajayant]

🙏🙏🙏🙏🙏🙏🙏

[@jaikmthomas5035]

@47:00 sir why your taking roots are 2 OMEGA and 2 OMEGA^2.....actual roots are omega and omega ^2 only right ?

[@sabudevi8855]

Kiyuki ...bha ...roots 2,-1+√3,-1-√3 hai toh Omega ki value -1+√3/2 aur w^2 -1-√3/2 hoty hai toh 2 se multiply aur divide kia hai tb 2omega liya hia sayd

[@naveenpatil9703]

Tysm sir

[@Pakhi25]

At 1:13:02 z=0 is essential singularity not pole

[@jaikmthomas5035]

Sin (ix) =i sin h (x) & cos (ix) = cos(hx)

[@shrawankumarpatel2148]

Thank you so much sir

[@professorragavan9783]

thank you sir...

[@alokkprajapati]

Many thanks sir

[@DrHarishGarg]

Welcome!

[@tanmoymondal830]

Sir at 3.38 you say z is a pole of order 8 but how?? At z=0 it is a pole of order 7- is not it?

[@prinsuvishwa5026]

yes you are right

[@yogeshjadhavpatil4120]

Thank you sir

[@Mahidreaming-sq1zn]

Why multiply by 2pi i ......in double pole ??? Pls reply sir

[@YOGESHSINGH-lw3ol]

15:00 it is a limacon but you drawn circle i think sir is wrong here i used concept of Winding number got 1st option as answer kindly fix

[@kishanchaurasia5250]

Yes, correct

[@neerajmaths4414]

Csir Net abstract algebra please

[@Kuldeep-up5ht]

15:06 it's not a equation of Circle its cardiod and there is mistake in answer here is a use of winding no concept

[@skjahidulislam9568]

❤❤

[@mahadevshiv3348]

15:30 wala question glt kiye hai sir

[@ravikumarbhoi4666]

sir gate 2021 ka question apne galat bataya he isme 11 poles ayenge please check

[@velmurugandon1241]

You write sin(ix)= sinhx but it is wrong sin(ix)=I sinhx

[@freethinker5670]

💐💐💐💗💗💗🌱🌱🪁🪁

[@anikasharma8169]

sir please explain in Hindi if you can :)

[@DrHarishGarg]

OK... But the explanation is very simple, not hard to understand

[@Sudeeppradhan1999]

Thank you sir ❤❤❤

[@smaranikabiswal3439]

Thank you 🙏🏻 sir

[@UmamaheswariV-d7w]

Thank you sir

[@abhisheknath7887]

Thank you sir