Python Armstrong Number Program (For 3 Digit Number) - In Hindi

[@mdshahid3436]

Sir..I want to say something. I watched several videos on KZbin but I didn't understand from any videos.. suddenly I got ur video Its really surprised for me because it's really amazing the way of teaching 👌😊.. right now my each and every concept becomes clear..I appreciate your efforts and ur knowledge... THANK YOU ❤️ SIR

[@codeitup]

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[@mdshahid3436]

@@codeitup sure sir ❤️

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Code Harry ka baap

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Right 😊

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before i found your video i had to look for many videos yet difficult to understand but when i started looking yours i understand it and saved a lot of time.thankyou

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Best videos in the you tube for beginners

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right sir you are amazinggggggggggggggggggggg

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Your teaching skill is exceptionally phenomenal❤❤

[@shubhangichaturvedi8142]

Your explanation is crystal clear sir

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The way you teach everyone will learn sir.

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Sir you are great the way you explain coding with example is totally amazing and easy to understand I am so greatful to be your online student❤☺

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Thanks Riya Kandpal. Keep Learning and Supporting :)

[@SurajKumar-jw7jo]

I will definitely share your videos with my friends.

[@codeitup]

Thanks Suraj😊

[@shaileshsarda5694]

Another alternative method to calculate the Armstrong Number: ### Get the number n = int(input("Enter the number: ")) ### Convert to string n1 = str(n) ### String Count count = len(n1) ### add string to list n1 = [int(i) for i in n1] ### find the power of each number by its count and store in D list D = [ ] for i in n1: j = i ** count D.append(j) ### Initiate the dummy variable for the addition of list sums = 0 for num in D: sums += num ### Driver function to check the number is Armstrong or not. if n == sums: print("Its Armstrong Number.") else: print("Not an Armstrong number.")

[@codeitup]

Quite a lengthy method. However, good effort.

[@deekshalingayata9539]

Awesome videos sir... They are really helpful... Very nice

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Glad to help you Deeksha!

[@AbhishekKumar.connects]

Perfectly Explained , I understood totally ,Thank you sir... I like the way you teach,always from basic...

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The way yoy teach is amazing sir👍

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[@yashnadar8145]

Sir really you are awesome so nicely explained. Love u sir ji

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My pleasure Yash, keep learning!

[@pmm4157]

Your explanation is awesome sir

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Thanks😊

[@Aqeelkhan-nk4sk]

Thanks sir you give with best teaching way I like your way love and thanks Allah pak apko mazeed kamyab kary AMeen

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So nice of you🙏

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Sir, maine saal ke beech mein cs li hai, scul mein kuch samajh nhi aa rha tha, yt par bhatakte aapke channel par aaya seriously aap boht acche se samjhaate ho, ab sab ho jaata hai All thanks to u sir😄😊

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[@tusharkumar1783]

@@codeitup sure , sir

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@@tusharkumar1783 Thanks Tushar !

[@pratibhasalunke1512]

Too much simplicity in u'r video's.. Really I like it.. 🙌

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Thanks Pratibha!

[@pujajaiswal228]

Sir aap bahut achhe se samjhate h thank you

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Thanks & most welcome Puja!

[@harddecoder5860]

Very helpful sir..keep it up😄

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Keep Learning HardDecoder!

[@akhiltest3066]

Next level explanation sir..

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Keep watching🙂

[@Sneakingmentor]

What a tutorial sir Thank you so much 😀

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Thank you sir for this tutorial

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Step by step process is best way to teach....u r doing great 👍

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Sir the way u teach is very awesome I'm doing MCA & python is there in my syllabus & it's really great to learn from your KZbin video.

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🙂👍

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Sir you are just awesome great sir💜 keep it up sir and we want more videos.. Like this

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So nice of you!

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Ur the best teacher sir❤️❤️

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Thank you so much Mahesh!

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Good work 👍 keep it up

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thank you very much sir. helped me a lot one week before the practical exam

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You are most welcome!

[@apurvachavan8399]

You teach the logics for program in very understandable way . thank you sir 😊

[@rdxvikrant8608]

nice explanation

[@codeitup]

🙏

[@chinmoykumar1878]

Sir best series of python. Any one who is finding it hard to learn python can learn with codeitup because of the best explanation. Plus he teaches us with a lot of examples. BTW sir I have a suggestion that it would be better if you teach us with games also.....

[@codeitup]

Sure, chinmoy. I will upload all the videos!

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Sir you are amazing mind-blowing

[@mohammadmubeen1166]

your described is fantastic sir. thank you very much

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Thanks & most welcome Mubeen!

[@AksaMWani]

Nice explanation..!!! But this program is for 3-digit numbers only.

[@pravingole2406]

Awesome video sir,👍👍👍👍👍👍

[@codeitup]

Thanks a ton🙂

[@Secret_Superstar_Girl]

Best video on Armstrong.....

[@codeitup]

Thanks a ton dear😊

[@Mrsoumen073]

sir thinks a lot.its really helpful

[@codeitup]

Keep Learning ☺️

[@dharmendramaurya5469]

Superb teaching sir

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Thanks Dharmendra!

[@hummingmoon7364]

Sir...u are way too amazing..ur teaching methods are so easy... Glad to be learning from you😊😊

[@codeitup]

Thanks a lot dear!

[@kabirpal1803]

Sir thank you so so much because I am not able to understand program but after watching your video's I do programme very well.👌👌👌👌

[@codeitup]

Most welcome Kabir !

[@aaryanpratapsonker2902]

Your explained very well SIR ❤️

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Thanks Aaryan!

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Thankyou so much 😀...

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Thanks Naitik. Support this channel to grow.

[@prajsingh5687]

Tqsm sir very helpful video tqsmm sir❤

[@mdgulamquadir2856]

Bahut hi useful video..👌 Sir apki video sirf 360 pe hi chalti hai 240 pe nahi aisa kyun ?

[@Iamkaran553]

Sir you are fabulous

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Thanks a ton Karan!

[@anshikakumari6525]

Thanks a lot 😊

[@pratikshakadam5884]

Thank you so much sir.. this video was really help me lot..

[@codeitup]

You are most welcome🙂

[@dhruvagrawal5399]

sir very nice video....excellent

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Thanks Dhruv !

[@aryansaxena4978]

I just wanna say that you are awesome

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🙂

[@ishangupta5183]

What a wonderful video sir u r great

[@codeitup]

Thanks a ton Amazed!

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Very nice lecture

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🙂

[@vidushiarora]

Awesome explanation sir! Keep going like this.👏👍

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Thank you, I will Viddushi !

[@AbhishekKumar.connects]

I have one request to you, Please make videos on Django Tutorial.

[@sanskarrastogi7660]

Love you sir

[@codeitup]

😊

[@normalman7663]

Sir armstrong number is not only used for doing cube of any number it is used for doing the power of the total number of digits available in original number For example, abcd= (4*pow(a))+(4*pow(b))+(4*pow(c))+(4*pow(d)) Here there are four digits in abcd number then it is used as 4 power of all the elements of abcd number

[@Sagarmahyavanshi]

##Try below method i = input() l=len(i) n=int(i) temp=n sum=0 while(n>0): r=n%10 sum=sum+(r**l) n=int(n/10) if(temp==sum) : print("Number is Armstrong") else : print("Number is not Armstrong")

[@codeitup]

👍

[@surajkiran636]

This method much better than that

[@codeitup]

Dear All, Please refer this video only for checking a 3 digit number is Armstrong or not. For any number of digits refer this program: kzbin.info/www/bejne/Zqa1paGQjbKZp68

[@Sachinyadav24G]

👏👏🙏🙏🙏thanks sir

[@codeitup]

Most welcome!

[@shaikshahimshaw1011]

Hi please consider easiest way: n1=input("Enter the number :") c1=[int(e) **len(n1) for e in n1] c2=(sum(c1)) If str(c2) ==n1: print ("its a Armstrong number") else: print ("Not a Armstrong number")

[@mamtagangwar7209]

Ha

[@lalitakumari3638]

Thank u very very much sir❣🙏

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Most welcome🙂

[@veerababupilli2907]

Veree level🔥🔥🔥

[@debatradas1597]

Thank you very much

[@codeitup]

Most welcome Debatra!

[@rishabhmittal123]

Thank you sir

[@subratkumar2608]

If I enter 1634, it is also an armstrong number. But if I run with your code than it will execute it is not an armstrong number. So, what to do in such case? Should I use the concept the exponentials? Anyways, love your video. Edit: So, I came up with this idea. num = int(input("Enter a number: ")) # initialize RESULT RESULT = 0 # changing num to string to find the length bcoz you cannot find the length of integer. power= len(str(num)) # find the sum of the cube of each digit temp = num # num value should be greater than 0 while temp > 0: digit = temp % 10 RESULT += digit ** power temp //= 10 # display the result if num == RESULT: print(num,"is an Armstrong number") else: print(num,"is not an Armstrong number") # So, this would work perfectly fine. Not copied ok!!!

[@codeitup]

Hello Subrat, I am also confused that why my code is not working. However, the way you suggested is Good. You can proceed with that. I am just trying to find out the loop hole as to why my code fails the this instance.

[@nehapandey2167]

@@codeitup I also stucked in the same question thanks subrat for the solution and the problem is that i think for 3 digit ex.153=1*1*1+5*5*5+3*3*3 is correct but when it comes to 4 digit number we have to find it like this 1634=1*1*1*1+6*6*6*6+3*3*3*3+4*4*4*4 but in the video it is sum=sum+(i%10) *(i%10) *(i%10) so it work for only for 3 digit.This is the reason its not working .Btw thank you sir for your videos it is helpful

[@codeitup]

@@nehapandey2167 Yes, my code will work only for three digit number. I will modify it.

[@subratkumar2608]

It is so good to hear that people are benefiting by this code. Thank u so much everyone.😇

[@codeitup]

Find here the new program for Armstrong for any number of digit: kzbin.info/www/bejne/Zqa1paGQjbKZp68

[@abdullahnawaz9464]

Thank you bahi g

[@codeitup]

Welcome dear.

[@NikhilKumar-th6yj]

Hats off 🙏🙏

[@codeitup]

😊🙏

[@rdxvikrant8608]

ty

[@kamil7922]

Helpfull❤️

[@codeitup]

Glad to help you

[@himanshusalvi4096]

print("ENTER A NUMBER FOR CHECK NUMBER IS AMSTRONG OR NOT") i=int(input("ENTER A NUMBER:")); n=int(input("SIZE OF NUMBER:")); a=i; sum=0; while(i>0): sum=sum+(i%10)**n; i=i//10 if(sum==a): print("THis",a,"NUMBER IS ARMSTRONG NUMBER"); else: print("THis",a,"NUMBER IS NOT ARMSTRONG NUMBER");

[@gautamjain2119]

ATQ, What about digits > or < 3 Armstrong numbers ?

[@Navya-s8o]

Tq clear explanation

[@codeitup]

Most welcome Navya!

[@carpediemscrate1923]

armstrong number is not only sum of cubes. if ex.35624 is 5 digit no. then sum of 5th power of all digit need to be same as 35624(original) if there has 12 digit no. then it should be same as sum of 12th power of all digits in it.

[@codeitup]

@Bharathi Pravallika Sagireddy Find here the new program for Armstrong for any number of digit: kzbin.info/www/bejne/Zqa1paGQjbKZp68

[@harmansingh6951]

The only thing holding me from taking sanyas from youtube

[@Alokraj-pq2oo]

Thank u sir

[@codeitup]

Welcome !

[@DK-js8cz]

Thanks for superb explanation. Sir, the above code is for 3 digit number separately and we can write it for 4 digit number also separately(sum=sum+(i%10)**4). But, How to write a single code to check whether a number is Armstrong or not for any digit?

[@codeitup]

kzbin.info/www/bejne/Zqa1paGQjbKZp68

[@user-rf3he9uv5m]

Code explanation was good .... but, how did u figure out what to write inside the while loop... how do we crack it , or do we need to remember that fourmla.... ????????

[@codeitup]

I think you watched this program directly. If you will see the programs I have uploaded just before this, you will know the concept how to figure out the logic for this program.. All my videos are step by step. See the video just before it i.e. tutorial 22 and 23 and you will understand how to figure out the logic.

[@VrushaliBhosale-dk4zr]

sir this logic gives correct result only for 3 digit number, for four digit and so on need to do some changes everytime

[@shilpachaudhary2739]

armstrong next method baata dijiye sir

[@rishabhmishra233]

Sir your explanation is too good.. But in this vdo you are forget Armstrong is not a equal of cubes.. This programme runned only 3 digits..

[@codeitup]

Yes rishabh, Thanks for letting me know this fact. I will make a new video on it.

[@rishabhmishra233]

Ok sir..

[@codeitup]

@@rishabhmishra233 Find the New Armstrong program video here: kzbin.info/www/bejne/Zqa1paGQjbKZp68

[@princededha3561]

Can we do it if we calculate the length of integer by using l=len(str(i)) And then use S=sum+i**l Plz reply

[@NehaRawal-qg5mk]

if we write 1634 this is also armstrong number but its coming wrong acording to your code pleace make me understand this for only 3 digit if we write for digit of arm strong then anser is not coming

[@codeitup]

kzbin.info/www/bejne/Zqa1paGQjbKZp68si=KTvKmsEi9_rwNiTP

[@akhilsharma4004]

i have one doubt zero is also an armstrong number but why have you written (i>0)??Please elaborate on this

[@codeitup]

In such case we need not to run the loop. Sum contains zero and the input number is also zero. Both are equal so it will print Armstrong.

[@parveenparveen4565]

Sir can you please tell me how to study computer science in class 11 😭😭😭 And also I don't know any basics but unfortunately I had taken cs in class 11..

[@ramanrajputindian5974]

Nice

[@codeitup]

Thanks dear😊

[@HitmanJaguar]

Sir can you please make a video on the.sum of the following series X+x^2/2!-x^3/3!+x^4/4! -...+x^n/n!

[@aqeelsaifi5273]

Sir please can you explain program to search between 1 to 1000 Armstrong number

[@nikhilanand1969]

bade bhai:D

[@varunagrawal385]

Sir, agar yahi code java me likhte toh bhot hard lagta lekin python me easy he. How many do agree with this?

[@shwetachaudhary8265]

How to become best coder sir

[@codeitup]

In the same way you learnt a,b,c,d then apple,boy,cat then apple is sweet.... Continuous practice and nothing else...

[@shwetachaudhary8265]

Okk thanku sir.

[@anamikapandey3121]

Thnq sir

[@codeitup]

Most welcome😊

[@iitianvibes_1]

nice

[@codeitup]

😊

[@FitnessMob]

Sir please tell what I'd we have take 2 inputs

[@gurjitkaur8750]

Sir can we use import math And then later use math.pow((i%10),3)

[@codeitup]

Yes, you can but is prohibited when you write the program in exam. You can also use: (i%10)**3 Why to use math module?

[@gurjitkaur8750]

@@codeitup means in paper it will be wrong

[@codeitup]

@@gurjitkaur8750 I think so. Using built in function is prohibited.

[@vanshikayadav5265]

Sir benifit of membership????

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Rs 159/- is just for supporting codeitup in which you may ask you question in comment box and you will definitely get a reply. But Rs 799/- is the most impressive one in which you will get my contact number and you can ask questions directly to me. Even, you can have one to one doubt clearing session once in a month.