PYTHON DICTIONARIES & FOR LOOPS (Beginner's Guide to Python Lesson 8)

[@Richard-yz2gy]

nice vid cheers :)

[@ragnarhelgi9397]

Epic! Thank you man this helped me a lot, keep up the good work!

[@du422]

I am trying to update a nested dictionary within for loop. The issue I am facing is the dictionary within dictionary values are a list and I need to update say 100th index of the list with a numpy array element. It updates inside the loop using either exec command or using key value pair in for loop. But outside for loop I see that all the elements are updated with the last numpy element, It looks the for loop is overwriting the list for each dictioanry. Any solution?

[@TheCbrown146]

where does the stock_count come in on the 2nd for loop? This is where I am not that great at traversing yet.

[@TheCbrown146]

I think I understand what may be possibly: for apple[key] , stock_count[value] in apple.items(): Is this correct? I found some examples stating that d.items(): allows you to not only show the key, but portray the value of the key as well? Stock_count is a variable name that we give; wherein, we couldn't named it 'poop' and it would still work, right?

[@miriam9623]

But yes, what if i wanted to create a dictionary based on previously made list and use the values from that as keys.. how do i get them into the dictionary then??

[@thairston1]

# This is the dictionry pips = {"Tie":1, "Noah":2, "Ma":3, "rye":4, "Law":5, "shoe":6, "Cow":7, "ivy":8, "Bee":9, "Toe":10} # Request the user pick a number to the associated Key Peg = input(“ pick a number from 1-10 ” + pips [ ]) Print(“This is your associated key ” + peg) #How do you get the associated user input to the dictionry?

[@pushpendrakushwaha604]

I have the same doubt

[@udaypamphilos]

Can you help me understand how "stock_count" worked in your code. you did not define that as a variable before so i couldn't follow how you used it in the second 'for' loop. for apple, stock_count in apples.items():

[@alexbabich2698]

It would have made more sense if he didn't use apple. Could have just wrote k, v for key and value and it works the same

[@registeredrepublican7297]

Underrated viedo...video... think if you went through more ways to do it and larger dicts it would be even better. You do have the best one I've seen out of the many. Regular editor and real loops. Good job. Update it. I would definitely watch.

[@swallowedinthesea11]

Awesome! Thank you from Texas! Stay safe during the Coronavirus.

[@PatentPending20]

Hey, this video is awesome, and you're a great teacher. Thank you.

[@LondonAppDeveloper]

Thank you :)

[@hseas3793]

If I had data from an excel sheet I believe I can use openxpy to grab the data and make python work with it. From there how could I make it so that instead of filtering for lets say the number of gala, fiji, pink lady, etc apples--- how could i make it so that python can draw the numbers for them automatically?

[@ramoun16]

use the enumerate() function: listy = ['apples','oranges'] for index , item in enumerate(listy): print(index, item) # output: # 1 apples # 2 oranges

[@harshsahu2767]

Sir plz increase your font size for more convenience 😁😎

[@matthieu_fulhaber]

thx for video im learning python at school :)

[@Farhan-mv7es]

Sir it would be great if u could've explained us how to use for loops in dictionaries with if-elif-else statement.

[@LondonAppDeveloper]

Appreciate the feedback! I'll keep it in mind when planning future content.

Hello, can you help me with this dict? asort= [ {'name': 'apple', 'price': 2.49}, {'name': 'orange', 'price': 23.90}, {'name': 'banana', 'price': 3.49}, ] How to create the function that search the fruit and return the price. For example: client write input "apple" and function returns "2.49".

[@LondonAppDeveloper]

For this you would need to loop through the array and check if item['name'] == 'apple'... This would be quite inefficient because if you have 1,000 items and the one you need happens to be at index 999, you need to loop through each item to find the right one. A more efficient approach would be to have a flat dictionary and use the name as the key... So: {'apple': {'price': 2.49}, 'banana': {'price': 3.00}} Then you can locate apple using: apple = fruits['apple']

[@marlenevergara326]

What if you wanted to filter by price less than $2.00, for example?

[@marlenevergara326]

@London App Developer

[@hasibkhan9537]

sir please tell me how to use dictionary for make english dictionary if user enter some word it can show the meaning

[@Strunoder24]

well I guess you need to use searchable word as a KEY and meaning as VALUE. Something like: dictionary = {'apple': 'a fruit', 'human': 'peace of meat', 'mom': 'gay'}

[@Dr_SteveK]

@@Strunoder24 loooooool , human: 'piece of meat_'mom':gay

[@hennieliebenberg7114]

Hello im hoping you can help me. I have 2 dictionaries that i need to get the total_value of. I need to get "the total_value is 280.36" displayed in the console. stock = { "Apples": 15, "Banana": 20, "Cherries": 19, "Strawberries": 10, } print(stock) price = { "Apples": 4.99, "Banana": 2.99, "Cherries": 3.99, "Strawberries": 6.99, } print(price)

[@ramoun16]

too late i know but myabe someone needs that in the future: method #1: sum = 0 for key , value in stock.items(): sum += values print(sum) # 64 method #2: sum = 0 for value in price.values(): sum += value print(sum) # 18.96 #coding_is_fun

[@hennieliebenberg7114]

Advice is always welcome and better late than never :) Thank you for the reply though!!!

[@ebrahimabidi4224]

Ty bro! U da GOAT

[@sickie1034]

5 years later - still helpfull

[@LondonAppDeveloper]

Great to hear!

[@LondonAppDeveloper]

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[@OGBonesPro]

Awesome! Thanks a bunch!

[@kalkidanberhe827]

Thank you much.

[@LondonAppDeveloper]

You're welcome!

[@stlo0309]

Thanks a lot!

[@LondonAppDeveloper]

You're welcome. Thank you!

[@karlavillarrealleal1254]

Thank you!

[@ares106]

mmm cox

[@arctictimberwolf]

Fee Fye Foe Fum

[@aidankieffer]

Why aren’t we using f strings! Hehehe

[@naresh.c2677]

he like apples more

[@jessieorozco3186]

I wouldn't recomend this song. All thumbs down.!.!.!

[@emilyncozzens8309]

Thank you so much!